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LIMITING REACTANT. Limiting Reagent The reactant that is totally used up during the chemical reaction Limits the amount of product produced.

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Presentation on theme: "LIMITING REACTANT. Limiting Reagent The reactant that is totally used up during the chemical reaction Limits the amount of product produced."— Presentation transcript:

1 LIMITING REACTANT

2 Limiting Reagent The reactant that is totally used up during the chemical reaction Limits the amount of product produced

3 EXCESS REACTANT Excess Reagent The reactant present in a quantity that is greater than what is needed to react with the limiting reactant Remains after the limiting reactant has been used up

4 What is the limiting reactant? What are the excess reactants?

5 STEPS 1.Balance the equation 2.Identify the givens (there are 2!) 3.Identify what you want to find 4.Use stoichiometry to solve 5.The reactant with a smaller amount of product produced is the limiting reactant 6.The other reactant is in excess

6 How many grams of silver bromide (AgBr) can be formed when solutions containing 50.0 g of MgBr 2 and g of AgNO 3 are mixed together? What is the limiting reactant? What is in excess? 1 MgBr AgNO 3 2 AgBr + 1 Mg(NO 3 ) g MgBr 2 1 mol MgBr 2 2 mol AgBr g AgBr g MgBr 2 1 mol MgBr 2 1 mol AgBr = 102 g AgBr g AgNO 3 1 mol AgNO 3 2 mol AgBr g AgBr g AgNO 3 2 mol AgNO 3 1 mol AgBr = g AgBr Limiting Reactant (LR) = MgBr 2 Excess Reactant (ER) = AgNO 3

7 How many grams of hydrogen chloride can be produced from 1.00 g of hydrogen and 55.0 g of chlorine? What is the limiting reactant? What is in excess? H 2 + Cl 2 HCl 1.00 g H 2 1 mol H 2 2 mol HCl g HCl 2.02 g H 2 1 mol H 2 1 mol HCl = 36.1 g HCl 55.0 g Cl 2 1 mol Cl 2 2 mol HCl g HCl g Cl 2 1 mol Cl 2 1 mol HCl = 56.6 g HCl Limiting Reactant (LR) = H 2 Excess Reactant (ER) = Cl 2

8 How many grams of barium sulfate (BaSO 4 ) will be formed from g of barium nitrate (Ba(NO 3 ) 2 ) and g of sodium sulfate (Na 2 SO 4 )? What is the limiting reactant? What is in excess? Ba(NO 3 ) 2 + Na 2 SO 4 BaSO 4 + NaNO g Ba(NO 3 ) 2 1 mol Ba(NO 3 ) 2 1 mol BaSO g BaSO g Ba(NO 3 ) 2 1 mol Ba(NO 3 ) 2 1 mol BaSO 4 = g BaSO g Na 2 SO 4 1 mol Na 2 SO 4 2 mol BaSO g BaSO g Na 2 SO 4 2 mol AgNO 3 1 mol BaSO 4 = g BaSO 4 Limiting Reactant (LR) = Ba(NO 3 ) 2 Excess Reactant (ER) = Na 2 SO 4


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