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Highland Science Department Limiting Reactants in Solution.

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Presentation on theme: "Highland Science Department Limiting Reactants in Solution."— Presentation transcript:

1 Highland Science Department Limiting Reactants in Solution

2 Highland Science Department Limiting Reactants in Solution Limiting Reactant: the reactant that is used up first in a chemical reaction. Excess Reactant: the reactant that will still be left over when the reaction is complete

3 Highland Science Department Limiting Reactants in Solution Limiting Reactant: the reactant that is used up first in a chemical reaction. Excess Reactant: the reactant that will still be left over when the reaction is complete Finding Limiting Reactant: compare mole ratios to those needed in the balanced chemical reaction to see which one is present in lower numbers

4 Highland Science Department Limiting Reactants in Solution e.g. 1: Find the mass of aluminum hydroxide that precipitates when 20.0 mL of mol/L aqueous aluminum sulfate is mixed with 30.0 mL of mol/L aqueous calcium hydroxide.

5 Highland Science Department Limiting Reactants in Solution e.g. 1: Find the mass of aluminum hydroxide that precipitates when 20.0 mL of mol/L aqueous aluminum sulfate is mixed with 30.0 mL of mol/L aqueous calcium hydroxide. G: Al 2 (SO 4 ) 3(aq) + 3Ca(OH) 2(aq)  2Al(OH) 3(s) + 3CaSO 4(aq)

6 Highland Science Department Limiting Reactants in Solution e.g. 1: Find the mass of aluminum hydroxide that precipitates when 20.0 mL of mol/L aqueous aluminum sulfate is mixed with 30.0 mL of mol/L aqueous calcium hydroxide. G: Al 2 (SO 4 ) 3(aq) + 3Ca(OH) 2(aq)  2Al(OH) 3(s) + 3CaSO 4(aq) volume = 20.0 mL concentration = mol/L Al 2 (SO 4 ) 3(aq) = L volume = 30.0 mLconcentration = mol/L Ca(OH) 2(aq) = L M.M. Al(OH) 3(s) = 78.0 g/mol

7 Highland Science Department Limiting Reactants in Solution e.g. 1: Find the mass of aluminum hydroxide that precipitates when 20.0 mL of mol/L aqueous aluminum sulfate is mixed with 30.0 mL of mol/L aqueous calcium hydroxide. U: mass of aluminum hydroxide

8 Highland Science Department Limiting Reactants in Solution e.g. 1: Find the mass of aluminum hydroxide that precipitates when 20.0 mL of mol/L aqueous aluminum sulfate is mixed with 30.0 mL of mol/L aqueous calcium hydroxide. U: mass of aluminum hydroxide S: 1. limiting reactant = volume x concentration ÷ lowest # moles n VM.R.M.M. 2. concentration  moles  moles  mass L.R.L.R.Al(OH) 3 Al(OH) 3

9 Highland Science Department Limiting Reactants in Solution e.g. 1: Find the mass of aluminum hydroxide that precipitates when 20.0 mL of mol/L aqueous aluminum sulfate is mixed with 30.0 mL of mol/L aqueous calcium hydroxide. S: 1. moles= L= 3.0 x mol Al 2 (SO 4 ) 3 moles= L = 5.55 x mol Ca(OH) 2

10 Highland Science Department Limiting Reactants in Solution e.g. 1: Find the mass of aluminum hydroxide that precipitates when 20.0 mL of mol/L aqueous aluminum sulfate is mixed with 30.0 mL of mol/L aqueous calcium hydroxide. S: 1. moles= L = 3.0 x mol Al 2 (SO 4 ) x mol =1equal to 1 mole moles= L = 5.55 x mol Ca(OH) x mol =1.85less than 3 moles

11 Highland Science Department Limiting Reactants in Solution e.g. 1: Find the mass of aluminum hydroxide that precipitates when 20.0 mL of mol/L aqueous aluminum sulfate is mixed with 30.0 mL of mol/L aqueous calcium hydroxide. S: 1. moles= L = 3.0 x mol Al 2 (SO 4 ) x mol =1equal to 1 mole Excess moles= L = 5.55 x mol Ca(OH) x mol =1.85less than 3 moles Limiting

12 Highland Science Department Limiting Reactants in Solution e.g. 1: Find the mass of aluminum hydroxide that precipitates when 20.0 mL of mol/L aqueous aluminum sulfate is mixed with 30.0 mL of mol/L aqueous calcium hydroxide. S: 2.mass = L Ca(OH) 2 Al(OH) 3 = g


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