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Principles of Reactivity: Chemical Kinetics Dr Abd El Rahman Salah Khder.

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1 Principles of Reactivity: Chemical Kinetics Dr Abd El Rahman Salah Khder

2 Kinetics Chemical kinetics is the study of the rates of chemical reactions. –Macroscopic level: rates of reactions, reaction rate, factors affecting rates –Particulate level: reaction mechanism (the detailed pathway taken by atoms and molecules as a reaction proceeds)

3 Rates of Chemical Reactions reaction rate is a measure of the speed of a reaction rate of a chemical reaction refers to the change in concentration of substance per unit of time –amounts of reactants decrease and amounts of products increase –often in units of M/s

4 Rates of Chemical Reactions 2N 2 O 5  4NO 2 + O 2 rate of rxn = - Δ[N 2 O 5 ]/Δt Or rate of rxn = Δ[NO 2 ]/Δt rate is expressed as a positive value; the sign on the rate indicates a decrease (reactant concentration) or increase (product concentration)

5 A B 13.1 rate = -  [A] tt rate = [B][B] tt time

6 Rates of Chemical Reactions 2N 2 O 5  4NO 2 + O 2 The graph of concentration vs. time is not straight because the rate of reaction changes during the course of the reaction. (largest at time = 0) Over a time period, the average rate can be calculated. For a single point in time, an instantaneous rate can also be calculated from the slope of the tangent line.

7 Reaction Rates A plot of concentration vs. time for this reaction yields a curve like this. The slope of a line tangent to the curve at any point is the instantaneous rate at that time. C 4 H 9 Cl (aq) + H 2 O (l)  C 4 H 9 OH (aq) + HCl (aq)

8 Reaction Rates The reaction slows down with time because the concentration of the reactants decreases. C 4 H 9 Cl (aq) + H 2 O (l)  C 4 H 9 OH (aq) + HCl (aq)

9 Reaction Rates and Stoichiometry To generalize, for the reaction aA + bBcC + dD Reactants (decrease) Products (increase)

10 For the decomposition of HBr 2HBr(g) → H 2 (g) + Br 2 (g) If HBr concentration is decreasing at a rate of 0.52 M/s What is the rate of the reaction? What is the rate of appearance of H 2 and Br 2 ? REACTION STOICHIOMETRY

11 Practice Problem Compare the rates of appearance or disappearance of each product and reactant, in the decomposition of nitrosyl chloride, NOCl. 2NOCl(g)  2NO(g) + Cl 2 (g)

12 Reaction Conditions and Rate Reaction rate increases with more collisions and more energy. Factors affecting the speed of reaction: –concentration of reactants – increasing [reactant] causes more collisions therefore increasing reaction rate –surface area – more surface area results in more collisions –physical state of reactants – homogeneous mixtures of liquids and gases tend to react faster (tied to surface area) –temperature – higher temp increases KE therefore increases collisions –catalysts – accelerate reaction but are not transformed themselves; changes reaction mechanism

13 Effect of Concentration on Rate the rate of reaction is proportional to the reactant concentration may be proportional to the concentrations of more than one reactant catalyst can affect the rate

14 Rate Equations A rate equation or rate law expresses the relationship between reactant concentration and rate

15 Rate Equations For a reaction such as aA + bB  xX the rate equation is rate = k[A] m [B] n where m and n are experimentally determined exponents NOT necessarily the stoichiometric coefficients (usually positive whole numbers)

16 Concentration and Rate Each reaction has its own equation that gives its rate as a function of reactant concentrations.  this is called its Rate Law To determine the rate law we measure the rate at different starting concentrations.

17 Concentration and Rate Compare Experiments 1 and 2: when [NH 4 + ] doubles, the initial rate doubles.

18 Concentration and Rate Likewise, compare Experiments 5 and 6: when [NO 2 - ] doubles, the initial rate doubles.

19 Concentration and Rate This equation is called the rate law, and k is the rate constant.

20 Rate Laws A rate law shows the relationship between the reaction rate and the concentrations of reactants. –For gas-phase reactants use P A instead of [A]. k is a constant that has a specific value for each reaction. The value of k is determined experimentally. “Constant” is relative here- k is unique for each rxn

21 Reaction order Exponents tell the order of the reaction with respect to each reactant. This reaction is First-order in [NH 4 + ] First-order in [NO 2 − ] The overall reaction order can be found by adding the exponents on the reactants in the rate law. This reaction is second-order overall.

22 Integrated Rate Laws Consider a simple 1st order rxn: A  B How much A is left after time t? Integrate: Differential form:

23 Integrated Rate Laws The integrated form of first order rate law: Can be rearranged to give: [A] 0 is the initial concentration of A (t=0). [A] t is the concentration of A at some time, t, during the course of the reaction.

24 Integrated Rate Laws Manipulating this equation produces… …which is in the form y = mx + b

25 First-Order Processes If a reaction is first-order, a plot of ln [A] t vs. t will yield a straight line with a slope of -k. So, use graphs to determine rxn order.

26 First-Order Processes Consider the process in which methyl isonitrile is converted to acetonitrile. CH 3 NCCH 3 CN How do we know this is a first order rxn?

27 First-Order Processes This data was collected for this reaction at 198.9°C. CH 3 NCCH 3 CN Does rate=k[CH 3 NC] for all time intervals?

28 First-Order Processes When ln P is plotted as a function of time, a straight line results. –The process is first-order. –k is the negative slope: 5.1  s -1.

29 Order of a Reaction The order with respect to a reactant is the exponent of its concentration term in the rate expression. Total reaction order is the sum of the exponents in the concentration terms.

30 Order of a Reaction A reactant is first order if doubling it (while holding the other reactants constant) doubles the rate. A reactant is second order if doubling it quadruples the rate. A reactant is third order if doubling it increases the rate by 8. A reactant is zero order if doubling it has no effect on the rate.

31 Order of a Reaction 2NO(g) + Cl 2 (g)  2NOCl(g) Rate = k[NO] 2 [Cl 2 ] This reaction is second order in NO, first order in Cl 2, and third order overall. Compare experimental evidence to figure out the order respective to reactants. Exp.[NO] mol/L [Cl 2 ] mol/L Rate mol/L∙s e e e e -6

32 Rate Constant, k The rate constant, k, is a proportionality constant relating rate and concentrations at a given temp. Units of the rate constant have to match; depends on order of reaction. –0 order = mol/L∙time –1 st order = time -1 –2 nd order = L/mol∙time –3 rd order = L 2 /mol 2 ∙time

33 Determining a Rate Equation A rate equation must be determined experimentally. –“method of initial rates” –initial rate is the instantaneous reaction rate at the start of the reaction (at t = 0)

34 Practice Problem The initial rate of the reaction of nitrogen monoxide and oxygen 2NO(g) + O 2 (g)  2NO 2 (g) was measured at 25 o C for various initial concentrations of NO and O 2. Data are collected in the table on p Determine the rate equation from these data. What is the value of the rate constant and what are the appropriate units of k?

35 Practice Problem The rate constant k is h -1 for the reaction Pt(NH 3 ) 2 Cl 2 (aq) + H 2 O(l)  [Pt(NH 3 ) 2 (H 2 O)Cl] + (aq) + Cl - (aq) and the rate equation is rate = k[Pt(NH 3 ) 2 Cl 2 ] Calculate the rate of reaction when the concentration of Pt(NH 3 ) 2 Cl 2 is 0.020M. What is the rate of change in the concentration of Cl - under those conditions?

36 Homework After reading section 15.3, you should be able to do the following… P. 713 (9-13)

37 15.4 Concentration-Time Relationships Integrated rate equation: ln( [R]t /[R]o ) = -kt [R] o and [R] t are concentrations of reactant at time t = 0 and at a later time, t. The ratio of concentrations is the fraction of reactant that remains after a given time has elapsed.

38 First Order Reactions ln [R]t /[R]o = -kt For a first order reaction, k has units of time -1, which means that you can choose any unit for [R] such as M, moles, grams, atoms, molecules, or pressure.

39 Practice Problem Sucrose, a sugar, decomposes in acid solution to glucose and fructose. The reaction is first order in sucrose, and the rate constant at 25 o C is k=0.21h -1. If the initial concentration of sucrose is M, what is its concentration after 5.0 h.

40 Practice Problem Gaseous NO 2 decomposes when heated 2NO 2 (g)  2NO(g) + O 2 (g) The disappearance of NO 2 is a first order reaction with k = 3.6x10 -3 s -1 at 300 o C. a.A sample of gaseous NO 2 is placed in a flask and heated at 300 o C for 150 s. What fraction of the initial sample remains after this time? b.How long must a sample be heated so that 99% of the sample has decomposed?

41 Second-Order Reaction For second-order reactions, the rate equation becomes 1/[R] t – 1/[R] o = kt same symbolism applies and k has units of L/mol∙time.

42 Practice Problem Using the rate constant for HI as k = 30. L/mol∙min, calculate the concentration of HI after 12 min if [HI] 0 = mol/L.

43 Zero-Order Reactions For a zero-order reaction, the integrated rate equation is [R] 0 – [R] t = kt where the units of k are mol/(L∙time).

44 Graphical Methods Each of the integrated rate laws can be rearranged to take the form of a straight line y = mx + b where m is the slope and b is the y-intercept.

45 Graphical Methods Zero Order [R] t = -kt + [R] o First Order ln[R] t = -kt + ln[R] o Second Order 1/[R] t = kt + 1/[R] o

46 Half-Life and First-Order Reactions The half-life, t 1/2, of a reaction is the time required for the concentration of a reactant to decrease to one-half its initial value. Longer half-life equals slower reaction. For first order reactions: t 1/2 = 0.693/k half life is independent of concentration!

47 Half-Life and Other Reactions Zero Order t 1/2 = [R] o /2k Second Order t 1/2 = 1/(k[R] o )

48 Practice Problem Americium is used in smoke detectors and in medicine for the treatment of certain malignancies. One isotope of americium, 241 Am, has a rate constant, k, for radioactive decay of year -1. In contrast, radioactive iodine-125, which is used for studies of thyroid functioning, has a rate constant for decay of day -1. a. What are the half-lives of these isotopes? b. Which element decays faster? c. If you begin a treatment with iodine-125, and have 1.6e 15 atoms, how many remain after 2.0 days?

49 Homework After reading section 15.4, you should be able to do the following… P. 714 (19-23)

50 15.5 Particulate View of Reaction Rates For a reaction to occur: Collision Theory –Reacting molecules must collide with each other. –Reacting molecules must collide with sufficient energy. –Molecules must collide in an orientation that can lead to rearrangement of the atoms.

51 Collision Theory Increasing the concentration of the reactant particles will increase the number of collisions. –The number of collisions between the reactant molecules is directly proportional to the concentrations of each reactant.

52 Activation Energy An “energy barrier” must be overcome for a reaction to occur. The energy required to overcome this barrier is called activation energy, E a. Fast reactions usually have low activation energies, and slow reactions have high activation energies.

53 Activation Energy As a reaction passes over the activation energy barrier, the transition state (also called an activated complex) is the arrangement of reactant molecules and atoms at the maximum point in the reaction coordinate diagram. (see page 625) –Must be inferred!

54 Effect of Temperature Increase Raising temperature increases the reaction rate by increasing the fraction of molecules with enough energy to surmount the activation energy barrier.

55 Effect of Molecular Orientation “steric factor” The lower the probability of achieving the proper alignment, the lower the value of k and the slower the reaction.

56 Arrhenius Equation The observation that reaction rates depend on the energy and frequency of collisions between reacting molecules, on the temperature, and on whether the collisions have the correct geometry is summarized by the Arrhenius equation: k = Ae -Ea/RT

57 Arrhenius Equation k = Ae -Ea/RT where R is the gas constant ( e -3 kJ/Kmol) and T is the temperature in kelvins. The parameter A is called the frequency factor and is related to the number of collisions that have correct geometry. The other factor refers to the fraction of molecules having at least the minimum energy required for reaction.

58 Arrhenius Equation Can be used to calculate the value of activation energy from the temperature dependence of the rate constant AND calculate the rate constant for a given temperature if the activation energy and A are known.

59 Arrenius Equation Can be rearranged to form an equation for a straight line relating ln k to 1/T. k = Ae -Ea/RT ln k = ln A – (E a /R)(1/T) y = mx + b

60 Arrhenius Equation We can also solve for E a by comparing k at two different temperatures… ln k 2 /k 1 = - E a /R[1/T 2 – 1/T 1 ]

61 Practice Problem The colorless gas N 2 O 4 decomposes to the brown gas NO 2 in a first-order reaction: N 2 O 4 (g)  2NO 2 (g) The rate constant k = 4.5 x 10 3 s -1 at 274K and 1.00 x 10 4 s -1 at 283K. What is the energy of activation?

62 Effect of Catalysts Catalysts speed up the rate of a chemical reaction but are not consumed in the reaction. Reaction intermediates are species formed in one step of a reaction that are then consumed in a later step.

63 Homework After reading section 15.5, you should be able to do the following… P. 715 (32-36)

64 15.6 Reaction Mechanisms Reaction mechanisms refer to the sequence of bond-making and bond- breaking steps that occurs during the conversion of reactants to products.

65 Reaction Mechanisms Step 1: Br 2 + NO  Br 2 NO Step 2: Br 2 NO + NO  2BrNO Overall: Br 2 + 2NO  2BrNO Each step is an elementary step. Each step has its own E a and k. Intermediates are substances formed in one step and then consumed in another (don’t appear in overall reaction).

66 Elementary Steps Although the rate constant for a reaction MUST be determined experimentally, for an elementary step it is determined stoichiometrically. The molecularity (unimolecular, bimolecular, termolecular) is the same as its order. Classified by the number of reactant molecules that come together. –NOT true for the overall reaction!

67 Practice Problem Nitric oxide is reduced by hydrogen to give nitrogen and water, 2NO(g) + 2H 2 (g)  N 2 (g) + 2H 2 O(g) and one possible mechanism is 2NO(g)  N 2 O 2 (g) N 2 O 2 (g) + H 2 (g)  N 2 O(g) + H 2 O(g) N 2 O(g) + H 2 (g)  N 2 (g) + H 2 O(g) What is the molecularity of each of the three steps? What is the rate equation for the third step? Show that the sum of these elementary steps gives the net equation.

68 Rate-Determining Steps Products can never be produced faster than the rate of the slowest elementary step, which is therefore called the rate- determining step.

69 Practice Problem The Raschig reaction produces the industrially important reducing agent hydrazine, N 2 H 4, from NH 3 and OCl - in basic, aqueous solution. A proposed mechanism is given on page 638. What is the overall stoichiometric equation? Which step is rate-determining? Write the rate equation for the rate- determining step. What reaction intermediates are involved?

70 Homework After reading section 15.6, you should be able to do the following… P. 716 (39-43)

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