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Published byEnrique Widdows Modified over 3 years ago

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Not so long ago, in a chemistry lab far far away… May the FORCE/area be with you

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1.Use the Ideal Gas Law to solve a gas stoichiometry problem.

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When you know the guy has finally had enough!!!

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2 H 2 O 2 (l) ---> 2 H 2 O (g) + O 2 (g) Decompose 1.1 g of H 2 O 2 in a flask with a volume of 2.50 L. What is the volume of O 2 at STP? Bombardier beetle uses decomposition of hydrogen peroxide to defend itself.

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2 H 2 O 2 (l) ---> 2 H 2 O (g) + O 2 (g) Decompose 1.1 g of H 2 O 2 in a flask with a volume of 2.50 L. What is the volume of O 2 at STP? Solution 1.1 g H 2 O 2 1 mol H 2 O 2 1 mol O 2 22.4 L O 2 34 g H 2 O 2 2 mol H 2 O 2 1 mol O 2 34 g H 2 O 2 2 mol H 2 O 2 1 mol O 2 = 0.36 L O 2 at STP

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How many grams of He are present in 8.0 L of gas at STP? = 1.4 g He 8.0 L He x 1 mol He 22.4 L He x 4.00 g He 1 mol He

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Gas Stoichiometry Trick Page 41:1 If reactants and products are at the same conditions of temperature and pressure, then mole ratios of gases are also volume ratios. 3 H 2 (g) + N 2 (g) 2NH 3 (g) 3 moles H 2 + 1 mole N 2 2 moles NH 3 67.2 liters H 2 + 22.4 liter N 2 44.8 liters NH 3

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Gas Stoichiometry Trick Example How many liters of ammonia can be produced when 12 liters of hydrogen react with an excess of nitrogen in a closed container at constant temperature? 3 H 2 (g) + N 2 (g) 2NH 3 (g) 12 L H 2 L H 2 = L NH 3 L NH 3 3 2 8.00

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How to Report Computer Problems:

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1. You will need to use PV = nRT

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Gas Stoichiometry Example Page x:1 How many liters of oxygen gas, at 1.00 atm and 25 o C, can be collected from the complete decomposition of 10.5 grams of potassium chlorate? 2 KClO 3 (s) 2 KCl(s) + 3 O 2 (g) 10.5 g KClO 3 1 mol KClO 3 122.55 g KClO 3 3 mol O 2 2 mol KClO 3 0.13 mol O 2

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Gas Stoichiometry Example Page x:1 How many liters of oxygen gas, at 1.00 atm and 25 o C, can be collected from the complete decomposition of 10.5 grams of potassium chlorate? 2 KClO 3 (s) 2 KCl(s) + 3 O 2 (g) 3.2 L O 2 (1.0 atm)(V)(0.08206 atm*L / mol*K )(298 K)(0.13 mol)

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1.Use the Ideal Gas Law to solve a gas stoichiometry problem.

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Now we’re in big Do-Do

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Gas Stoichiometry Page x:2 1 P 4 (s) + 6 H 2 (g) 4 PH 3 (g) 2.51 g P 4 1 mol P 4 123.88 g P 4 6 mol H 2 1 mol P 4 0.122 mol H 2

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3.0 L H 2 (0.991 atm)(V)(0.08206 atm*L / mol*K )(298 K)(0.122 mol) Gas Stoichiometry Page x:2 1 P 4 (s) + 6 H 2 (g) 4 PH 3 (g)

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Quicklime Example Page x:3 1 CaCO 3 (s) 1 CaO (s) + 1 CO 2 (g) 152 g CaCO 3 100.09 g 1 mol CaCO 3 1 mol CO 2 1 mol CaCO 3 = 34.0 L CO 2 at STP 1 mol CO 2 22.4 L CO 2

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Pass the Clicker!!!

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1. ZnCl + H 2. ZnCl + H 2 3. Zn 2 Cl + H 2 4. ZnCl 2 + H 2 5. Not listed

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1. DD 2. SD 3. Synthesis 4. Decomposition 5. Not listed

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1. 1,2,1,2 2. 2,1,2,1 3. 1,1,1,1 4. 2,2,1,2 5. Not listed

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1. 250 atm 2. 314 atm 3. 0.329 atm 4. 0.987 atm 5. Not listed

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1. 0.112 g 2. 1.18 g 3. 628 g 4. 0.000 628 g 5. 0.369 g

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1.Explain Dalton’s Law and use it to solve a problem. 2.Use the Ideal Gas Law to solve a gas density problem. 3.Use the Ideal Gas Law to solve a gas stoichiometry problem.

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Highdensity Lowerdensity 22.4 L of ANY gas AT STP = 1 mole

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Gas Density … so at STP…

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Density and the Ideal Gas Law Combining the formula for density with the Ideal Gas law, substituting and rearranging algebraically: M = Molar Mass P = Pressure R = Gas Constant T = Temperature in Kelvins

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Gas Stoichiometry #4 How many liters of oxygen gas, at 37.0 C and 0.930 atmospheres, can be collected from the complete decomposition of 50.0 grams of potassium chlorate? 2 KClO 3 (s) 2 KCl(s) + 3 O 2 (g) = “n” mol O 2 50.0 g KClO 3 1 mol KClO 3 122.55 g KClO 3 3 mol O 2 2 mol KClO 3 = 0.612 mol O 2 = 16.7 L

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How many L of O 2 are needed to react 28.0 g NH 3 at 24°C and 0.950 atm? 4 NH 3 (g) + 5 O 2 (g) 4 NO(g) + 6 H 2 O(g)

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Ideal Gas Law PV = nRT P= pressure (atm) V= volume (L)

Ideal Gas Law PV = nRT P= pressure (atm) V= volume (L)

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