2. JMerrill, 2010

3. IIt will be imperative that you know the identities from Section 5.1. Concentrate on the reciprocal, quotient, and Pythagorean identities. TThe Pythagorean identities are crucial!

4. SSolve sin x = ½ WWhere on the circle does the sin x = ½ ? Particular Solutions General solutions Solve for [0,2π] Find all solutions

6.  Find all solutions to: sin x + = -sin x

7.  Solve

8. Round to nearest hundredth

9.  Solve Verify graphically These 2 solutions are true because of the interval specified. If we did not specify and interval, you answer would be based on the period of tan x which is π and your only answer would be the first answer.

10.  Quick review of Identities

11. Reciprocal Identities Also true:

12. Quotient Identities

13. Pythagorean Identities These are crucial! You MUST know them.

14. sin 2 cos 2 tan 2 cot 2 sec 2 csc 2 (Add the top of the triangle to = the bottom) 1

15. SStrategies CChange all functions to sine and cosine (or at least into the same function) SSubstitute using Pythagorean Identities CCombine terms into a single fraction with a common denominator SSplit up one term into 2 fractions MMultiply by a trig expression equal to 1 FFactor out a common factor

17. Hint: Make the words match so use a Pythagorean identity Quadratic: Set = 0 Combine like terms Factor—(same as 2x 2 -x-1)

19.  You cannot divide both sides by a common factor, if the factor cancels out. You will lose a root…

20. Common factor— lost a root No common factor = OK

21.  Sometimes, you must square both sides of an equation to obtain a quadratic. However, you must check your solutions. This method will sometimes result in extraneous solutions.

22. SSolve cos x + 1 = sin x in [0, 2π) TThere is nothing you can do. So, square both sides ((cos x + 1) 2 = sin 2 x ccos 2 x + 2cosx + 1 = 1 – cos 2 x 22cos 2 x + 2cosx = 0 NNow what? Remember—you want the words to match so use a Pythagorean substitution!

23. 22cos 2 x + 2cosx = 0 22cosx(cosx + 1) = 0 22cosx = 0cosx + 1 = 0 ccosx = 0cosx = -1

25. SSolve 2cos3x – 1 = 0 for [0,2π) 22cos3x = 1 ccos3x = ½ HHint: pretend the 3 is not there and solve cosx = ½. AAnswer:  But….

26.  In our problem 2cos3x – 1 = 0  What is the 2?  What is the 3?  This graph is happening 3 times as often as the original graph. Therefore, how many answers should you have? amplitude frequency 6

27. Add a whole circle to each of these And add the circle once again.

28. Final step: Remember we pretended the 3 wasn’t there, but since it is there, x is really 3x:

29. WWork the problems by yourself. Then compare answers with someone sitting next to you. RRound answers: 11. csc x = -5 (degrees) 22. 2 tanx + 3 = 0 (radians) 33. 2sec 2 x + tanx = 5 (radians)

30. 44. 3sinx – 2 = 5sinx – 1 55. cos x tan x = cos x 66. cos 2  - 3 sin  = 3