Download presentation

Presentation is loading. Please wait.

Published byJennifer Houchen Modified over 3 years ago

1
Lesson starter 1: Lesson starter 1: Calculate the Mean of…… (a) 3, 4, 7, 3, 5, 2, 6, 10 (b) 8, 10, 12, 14, 7, 16, 5, 7, 9,11 (c) 64, 66, 65, 61, 67, 61, 57

2
Answers (a) Mean = 5 (b) Mean = 9.9 (c) Mean = 63

3
Lesson starter 2: What is the range of each set? (a) 3, 4, 7, 3, 5, 2, 6, 10 (b) 8, 10, 12, 14, 7, 16, 5, 7, 9,11 (c) 64, 66, 65, 61, 67, 61, 57

4
Answers (a) Range = 8 (b) Range = 11 (c) Range = 10

5
Objective: Mean of large data sets A businessman is deciding whether to open a new shop selling CD’s in Market Harborough. He conducts a survey in the town and manages to ask 250 shoppers how many CD’s they buy a month. He could add up all of the answers and divide by the number surveyed, but this is a lot of data! What would be a better way to organise this data to make it useful to him?

6
Number of CD’sTally 0||||| ||||| 1||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| |||| 2||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||| 3||||| ||||| ||||| ||||| ||||| || 4||||| ||||| ||||| ||||| ||| 5||||| ||||| | 6||||| ||| 7||||

7
Number of CD’s TallyFrequency 0||||| ||||| 20 1||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| |||| 49 2||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||| 108 3||||| ||||| ||||| ||||| ||||| ||27 4||||| ||||| ||||| ||||| |||23 5||||| ||||| |11 6||||| |||8 7||||4 Totals250

8
Calculating the Mean The final column completes the table and allows him to calculate the mean number of CD’s bought per person. Can you suggest what might go in this column? Complete the column and calculate mean number of CD’s bought per person.

9
Number of CD’s TallyFrequencyFrequency x CD’s 0||||| ||||| 20 0 20 = 0 1||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| |||| 49 1 49 = 49 2||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||||| ||| 108 2 108 = 216 3||||| ||||| ||||| ||||| ||||| ||27 3 27 = 81 4||||| ||||| ||||| ||||| |||23 4 23 = 92 5||||| ||||| |11 5 11 = 55 6||||| |||8 6 8 = 48 7||||4 7 4 = 28 Totals250569 Mean = 569 / 250 = 2.276

10
Questions How will the information about the mean number of CD’s help him? Can you buy 2.276 CD’s or would another measure of the average have given him a clearer answer? Can we find the mode? What about the median?

Similar presentations

Presentation is loading. Please wait....

OK

Mean, Median, Mode and Range By: Prae, Rimako and Aaron.

Mean, Median, Mode and Range By: Prae, Rimako and Aaron.

© 2018 SlidePlayer.com Inc.

All rights reserved.

To ensure the functioning of the site, we use **cookies**. We share information about your activities on the site with our partners and Google partners: social networks and companies engaged in advertising and web analytics. For more information, see the Privacy Policy and Google Privacy & Terms.
Your consent to our cookies if you continue to use this website.

Ads by Google

By appt only movie pro Ppt on save water in india Ppt on solar energy system Free download ppt on diversity in living organisms Ppt on formal education meaning Ppt on strategic management process Ppt on indian news channels Ppt on target marketing Download ppt on sets for class 11 Ppt on ancient indian mathematicians and their contributions