Download presentation

Presentation is loading. Please wait.

Published byKamron Northington Modified over 2 years ago

1
Breaking Brackets Demo 3(2c+5)

2
Single Bracket 0 123 456 789 Ans5 C. ÷ x 0 + On ² - Ans = √ (-) 1 ( - ) x8 = - 2 3 4 5 6 7 8 9 10 Show Working Clear r

3
How to “Break” Brackets 2 Simply multiply everything inside the bracket by what is outside the bracket x( 4 +) = 2 x x + 4 = 8 2x2x2x2x = 8 The + between the x and 4 tells you to add the answers + 2x2x2x2x Two “answers one for each term inside the brackets

4
How to “Break” Brackets 5 Simply multiply everything inside the bracket by what is outside the bracket x( 3 -) = 5 x x - 3 = 15 5x5x5x5x = 15 The - between the x and 3 tells you to subtract the answers - 5x5x5x5x Two “answers one for each term inside the brackets

5
How to “Break” Brackets 4444 Simply multiply everything inside the bracket by what is outside the bracket rrrr( 7777- ) = 0 123 456 789 C. ÷ x 0 + On ² - Ans = √ (-) rx - x = - New Example Start

6
More Examples 2 ( a + 3 ) = Examples Multiply Out 2a+ 6 5 ( b + 3 ) = 5b+ 15 8 ( c + 7 ) = 8c+ 56 3 ( d - 2 ) = 3d- 6 9 ( e - 5 ) = 9e- 45 (a) 7 ( f + 4 ) = 7f + 28 (b) 6 ( g - 5 ) = 6g - 30 (c) 5 ( h - 8 ) = 5h - 40 (d) 10 ( k + 7 ) = 10k + 70 (e) 9 ( m - 8 ) = 9m - 72 (f) 4 ( n + 11 ) = 4n + 44

7
3(a+5) type Examples a) b) c) d) e) f) g) 4(a-9) = 4a-36 3(a+5) = 7(a+3) = 5(a+4) = 6(a-7) = 9(a-2) = 8(a-6) = 3a+15 7a+21 5a+20 6a-42 9a-18 8a-48 0 123 456 789 C. ÷ x 0 + On ² - Ans = √ (-) a New Examples Show Answers

8
3(2c+5) 3 Simply multiply everything inside the bracket by what is outside the bracket 2c ( 5 ) = 3 x 2c 3 x + 5 = 15 6 x c = 15 The + between the 2c and 5 tells you there is a + between the answers + 6c 2 x c x 3 Two answers, one for each term x 3

9
2(5z-7) 2 Simply multiply everything inside the bracket by what is outside the bracket 5z ( 7 ) = 2 x 5z 2 x - 7 = 14 10 x z = 14 The - between the 5z and 7 tells you there is a - between the answers - 10z 5 x z x 2 Two answers, one for each term x 2

10
1 st term in brackets 3b, 2a, 7g etc 7777 Simply multiply everything inside the bracket by what is outside the bracket 2q ( 2222+ ) = 0 123 456 789 14 C. ÷ x 0 + On ² - Ans = √ (-) qx + x = + New Example Start

11
Examples like 5(3p – 2 ) 2 ( 2a + 3 ) = Examples Multiply Out 4a+ 6 4 ( 3b + 5 ) = 12b + 20 6 ( 2c + 3 ) = 12c+ 18 5 (5e - 4 ) = 25e- 20 9 ( 7e - 3 ) = 63e- 27 (a) 7 ( 2f + 5 ) = 14f + 35 (b) 6 ( 2g - 5 ) = 12g - 30 (c) 5 ( 7h - 9 ) = 35h - 45 (d) 10 ( 2k + 7 ) = 20k + 70 (e) 9 ( 3m - 9 ) = 27m - 81 (f) 4 ( 4n + 10 ) = 16n + 40

12
3(?a+5) type Examples a) b) c) d) e) f) g) 4(5a+4) = 20a+16 8(7a+6) = 2(9a-7) = 6(8a+9) = 9(4a+3) = 3(6a+5) = 7(2a+5) = 56a+48 18a-14 48a+54 36a+27 18a+15 14a+35 0 123 456 789 C. ÷ x 0 + On ² - Ans = √ (-) a New Examples Show Answers

13
Removing Brackets : 3(2a+b-5) 3 Simply multiply everything inside the bracket by what is outside the bracket 2a ( b ) = 3 x 2a 3 x + b = 3b 6 x a = 3b Copy the signs between each term + 6a 2 x a x 3 Three answers, one for each term x 3 5 - - b x 3 3 x 5 =15

14
Removing Brackets : 3(s + 4)+2s 3 Simply multiply everything inside the bracket by what is outside the bracket s ( 4 ) = + The + between the p and 3 tells you there is a + between the answers + x 3 Two answers, one for each term x 3 + 2s All Maths “sums” involve BODMAS. ( B ) first 3 x s = 3s 3 x 4 = 12

15
Removing Brackets : 3(s + 4)+2s 3 Simply multiply everything inside the bracket by what is outside the bracket s ( 4 ) = + + + 2s 3s 12 + 2s Three terms now The brackets equal 5p + 15 The middle is a number, the others letters. ….. can add the two letter terms 3s + 2s = 5s = + 12 The expression has been simplified to 5s + 12 A letter term plus a number term …… hide the number 5s

16
More Examples 5 ( d + 3 ) +d = Examples Multiply Out 5d + 15 + d = 6d + 15 7 ( e + 4 ) – 3e = 7e + 28 - 3e = 4e + 28 8 (f + 3 ) – 5f = 8f + 24 - 5f = 3f + 24 (a) 7(g + 3 ) + 2g = 9g + 21 (b) 4(h + 2 ) - h = 3h + 8 (c) 2(j + 7) + 3j = 5j + 14 (d) 9(k + 3 ) – 2k = 7k + 27 (e) 6(m + 9 ) – 4m = 2m + 54 (f) 8(n – 3 ) + 2n = 10n - 24

17
3(a+5) +5a type Examples a) b) c) d) e) f) g) 4(a-7) + 4a = 8a-28 2(a-4) + 5a = 5(a+8) + 7a = 9(a+5) + 6a = 8(a+3) + 8a = 6(a+6) + 2a = 3(a-2) + 9a = 7a-8 12a+40 15a+45 16a+24 8a+36 12a-6 0 123 456 789 C. ÷ x 0 + On ² - Ans = √ (-) a New Examples Show Answers 4a-28 + 4a = 4a-28 + 4a = 2a-8 + 5a = 2a-8 + 5a = 5a+40 + 7a = 5a+40 + 7a = 9a+45 + 6a = 9a+45 + 6a = 8a+24 + 8a = 8a+24 + 8a = 6a+36 + 2a = 6a+36 + 2a = 3a-6 + 9a = 3a-6 + 9a =

18
Removing Brackets : 5( p + 3 ) + 7 5 Simply multiply everything inside the bracket by what is outside the bracket p ( 3 ) = + The + between the p and 3 tells you there is a + between the answers + x 5 Two answers, one for each term x 5 + 7 All Maths “sums” involve BODMAS. ( B ) first 5 x p = 5p 5 x 3 = 15

19
Removing Brackets : 5( p + 3 ) + 7 5 Simply multiply everything inside the bracket by what is outside the bracket p ( 3 ) + + + 7 5p 15 + 7 Three terms now The brackets equal 5p + 15 The 1 st is a letter term the others numbers ….. can add the two numbers 15 + 7 = 22 5p = + 22 The expression has been simplified to 5p + 22 A letter term plus a number term

20
Some more examples 3 ( a + 4 ) +5 = Examples Multiply Out 3a + 12 + 5 = 3a + 17 5 ( b + 3 ) - 6 = 5b + 15 - 6 = 5b + 9 6 (c + 9 ) – 10 = 6c + 54 - 10 = 6c + 48 (a) 4(e + 5 ) + 3 = 4e + 23 (b) 2(f + 7 ) - 2 = 2f + 12 (c) 5(g + 3) + 10 = 5g + 25 (d) 3(h + 8 ) - 7 = 3h + 17 (e) 6(k + 2 ) - 11 = 6k + 1 (f) 8(m – 3 ) + 35 = 8m - 11

21
3(a+5) +7 type Examples a) b) c) d) e) f) g) 2(a-4) + 5 = 2a-3 6(a-7) + 4 = 4(a-3) + 2 = 3(a+5) + 7 = 5(a-2) + 6 = 8(a-6) + 3 = 9(a+8) + 9 = 6a-38 0 123 456 789 C. ÷ x 0 + On ² - Ans = √ (-) a New Examples Show Answers 2a-8 + 5 = 2a-8 + 5 = 6a-42 + 4 = 6a-42 + 4 =

22
Removing Brackets : 4( 2a + 5 ) + 6 4 Simply multiply everything inside the bracket by what is outside the bracket 2a ( 7 ) 4 x 2a 4 x + 7 = 28 8 x a = 28 The + between the 2a and 7 tells you there is a + between the answers + 8a 2 x a x 4 Two answers, one for each term x 4 + 6 All Maths “sums” involve BODMAS. ( B ) first

23
Removing Brackets : 4( 2a + 5 ) + 6 4 Simply multiply everything inside the bracket by what is outside the bracket 2a ( 7 ) = + + + 6 8a 28 + 6 Three terms now The brackets equal 8a + 28 The 1 st is a letter term the others numbers ….. can add the two numbers 28 + 6 = 34 8a = + 34 The expression has been simplified to 8a + 34 A letter term plus a number term

24
More Examples 3 ( 2a + 3 ) +4 = Examples Multiply Out 6a + 9 + 4 = 6a + 13 4 ( 3b + 5 ) - 3 = 12b + 20 - 3 = 12b + 17 6 ( 2c + 3 ) – 10 = 12c + 18 - 10 = 12c + 8 (a) 4(3e + 2 ) +9 = 12e + 17 (b) 2(7f + 3 ) -2 = 14f +4 (c) 5(2g + 5) + 6 = 10g + 31 (d) 3(5h + 8 ) - 7 = 15h + 17 (e) 6(3k + 9 ) -11 = 18k +43 (f) 8(2m – 3 ) + 10 = 16m - 14

25
Removing Brackets : 5( 3b - 7 ) + 4b 5 Simply multiply everything inside the bracket by what is outside the bracket 3b ( 7 ) = 5 x 3b 5 x - 7 = 35 15 x b = 35 The - between the 3b and 7 tells you there is a - between the answers - 15b 3 x b x 5 Two answers, one for each term x 5 + 4b All Maths “sums” involve BODMAS. ( B ) first

26
Removing Brackets : 5( 3b - 7 ) + 4b 5 Simply multiply everything inside the bracket by what is outside the bracket 3b ( 7 ) = - - + 4b 15b 35 + 4b Three terms now The brackets equal 15b -35 The 1 st and last terms are letter terms the middle a number Hide the middle term and add the two letter terms 15b +4b = 19b = - 35 The expression has been simplified to 19b - 35 A letter term plus a number term 19b

27
Removing Brackets : 3( 2a + 5b ) – 2a 3 Simply multiply everything inside the bracket by what is outside the bracket 2a ( 5b ) = 3 x 2a + 5b = 6 x a The + between the 2a and 5b tells you there is a + between the answers + 6a 2 x a x 3 Two answers, one for each term x 3 - 2a All Maths “sums” involve BODMAS. ( B ) first 3 x = 15 x b 15b 5 x b

28
Removing Brackets : 3( 2a + 5b ) – 2a 3 Simply multiply everything inside the bracket by what is outside the bracket 2a ( 5b ) + + - 2a 6a 15b - 2a Three terms now The brackets equal 6a +15b The 1 st and last terms are letter terms in a the middle a letter terms in b Hide the middle term and add the two terms in a 9a – 2a = 4g = + 45b The expression has been simplified to 4a +15b Two terms in different letters 4a

29
More Examples 4 ( 3a + 5 ) + a = Examples Multiply Out 12a + 20 + a = 13a + 20 3 ( 2g + 5 ) – 2g = 6g + 15 - 2g = 4g + 15 5 ( 3s + 2t ) – 6s = 15s +10t - 6s = 9s + 10t (a) 5(3e + 2 ) +2e = 17e + 10 (b) 3(4f + 5 ) – 7f = 5f + 15 (c) 6(3g + 2) + 4g = 22g +12 (d) 2(5h + 3g ) – 6h = 4h +6g (e) 4(5s + 9t ) – 3t = 20s +33t (f) 8(2m – 5a ) – 3m = 13m -40a

30
Removing Brackets : 7a + 3(2a – 5) 3 Simply multiply everything inside the bracket by what is outside the bracket 2a ( 5 ) = 3 x 2a 3 x - 5 = 15 6 x a = 15 The - between the 2a and 5 tells you there is a - between the answers - 6a 2 x a x 3 Two answers, one for each term x 3 7a + All Maths “sums” involve BODMAS. ( B ) first

31
Removing Brackets : 7a + 3(2a – 5) 5 Simply multiply everything inside the bracket by what is outside the bracket 3b ( 7 ) = - - 4b 15b 35 4b Three terms now The brackets equal 15b -35 The 1 st and last terms are letter terms the middle a number Hide the middle term and add the two letter terms 15b +4b = 19b = - 35 The expression has been simplified to 19b - 35 A letter term plus a number term 19b + + 4b

32
More Examples 2a + 4 ( 5a + 1 ) = Examples Multiply Out 20a + 4 2a + 13a + 20 5g +2 ( 3g - 4 ) = 6g - 8 5g + 11g - 8 4s +3 ( 6s + 2t ) = 18s +6t 4s + 22s + 6t (a) 4e+3(2e + 7 ) = 10e + 21 (b) 3g + 5(2g + 1) = 13g + 5 (c) 5b + 2(9b – 4) = 23b - 8 (d) 9t +4(3t – 5) = 21t - 20 (e) 6r + 2(3r + 8) = 12r + 16 (f) 10f + 3(9 – 2f) = 4f + 27 = = =

Similar presentations

OK

Grade 6. Expression: a set of numbers that are related to one another by the use of operator symbols that represent a mathematical situation Has no equal.

Grade 6. Expression: a set of numbers that are related to one another by the use of operator symbols that represent a mathematical situation Has no equal.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on rbi reforms in education Ppt on applied operational research consultants Ppt on recent natural disasters Ppt on martin luther king for kids Ppt on statistics and probability review Ppt on ram and rom comparison Ppt on culture of china Ppt on crash fire tender specifications Ppt on abo blood grouping reagents Ppt on sikkim cultural