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Completing the Square Section 9.1 MATH 116-460 Mr. Keltner.

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Presentation on theme: "Completing the Square Section 9.1 MATH 116-460 Mr. Keltner."— Presentation transcript:

1 Completing the Square Section 9.1 MATH Mr. Keltner

2 Example 1 Solve ( x + 6) 2 = 20. We know how to solve equations when it is possible to take the square root of each side, such as: 4x 2 = 16 Constant multiple with a variable x x + 49 = 25 A quantity that can be rewritten x 2 = -76 Where we take the square root of a negative number, or use i

3 A need for a new strategy Sometimes, we will have an expression of the form x 2 + bx, that requires us to insert an additional term to make it a perfect square, like (x + k) 2. The process of forcing a quadratic expression to become a perfect square trinomial is called completing the square.

4 Completing the Square in 3 “Easy” Steps Steps These steps may only be used on a quadratic expression in the form ax 2 + bx, where a = 1, and b is a real number. 1. Find half the coefficient of x. 2. Square that value. 3. Replace c with the resulting value. Example: Find the value of c that makes x 2 -26x + c a perfect square trinomial. Then write the expression as the square of a trinomial ÷ 2 = (-13) 2 = x 2 -26x + c becomes x x + 169, which is equal to ( x-13 ) 2 when it is factored.

5 Example 2 Find the value of c that makes each expression a perfect square trinomial. Then write each expression as the square of a binomial.  x x + c  x x + c  x 2 – 9x + c What do you notice about the value of c if b happens to be an odd number? Does the sign of c change or does it remain constant?

6 Solving Quadratic Equations by Completing the Square Related example: Solve x = 12. Your first step would be to add 4 to each side of the equation. Just the same as we add the same value to both sides of this equation, we apply this same idea when completing the square. Example 3 Solve x x + 1 = 0 by completing the square.

7 Solving ax 2 + bx + c = 0 if a ≠ 1 Divide every term of both sides by the coefficient of x 2 (the value of a ). Make sure to balance the equation by adding the same value to both sides. Example 4: Solve 3x 2 – 36x = 0 by completing the square.

8 Example 5 Solve the equation by completing the square.  ( NOTE : You cannot apply the Zero-Product Property and say that either 6x = 12 or (x + 8) = 12 and solve.) 6x (x + 8) = 12

9 Baseball example: Finding a maximum value  The height, y (in feet), of a baseball x seconds after it is hit is given by the equation: y = -16x x + 3 Find the maximum height of the baseball. The maximum height of the baseball will be the y-coordinate of the vertex of the parabola.  It will help if we can write the equation in vertex form.

10 Baseball Example, Cont. The height, y (in feet), of a baseball x seconds after it is hit is given by the equation: y = -16x x + 3 Find the maximum height of the baseball. Start by writing the function in vertex form.  If we can find the y-value at the vertex, we will have found the maximum height of the ball.

11 Fountain Example At the Buckingham Fountain in Chicago, the water’s height h (in feet) above the main nozzle can be modeled by h = -16t t, where t is the time in seconds) since the water has left the nozzle. Find the highest point the water reaches above the fountain.  What does this vertex represent, in real-world terms?

12 Assessment Pgs : #’s 7-98, multiples of 7


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