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Available worksheet, PE, KE, and ME.

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First Law of Energy (Thermodynamics) First Law of Energy (Thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

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First Law of Energy (thermodynamics) First Law of Energy (thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

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First Law of energy (thermodynamics) First Law of energy (thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

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First Law of Energy (thermodynamics) First Law of Energy (thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

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First Law of Energy (thermodynamics) First Law of Energy (thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

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Potential Energy: (PE) The energy stored by an object as a result of its position. Potential Energy: (PE) The energy stored by an object as a result of its position. Copyright © 2010 Ryan P. Murphy

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Potential Enegy (PE)Kinetic Energy (KE)

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Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Kinetic Energy is the energy of motion. Kinetic Energy is the energy of motion. Copyright © 2010 Ryan P. Murphy

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Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Kinetic Energy is the energy of motion. Kinetic Energy is the energy of motion. Copyright © 2010 Ryan P. Murphy

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Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Kinetic Energy is the energy of motion. Kinetic Energy is the energy of motion. Copyright © 2010 Ryan P. Murphy

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Available worksheet, PE, KE, and ME.

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Activity! Please write and plan on sharing a sentence about PE and KE about the animation below. Copyright © 2010 Ryan P. Murphy

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Activity! Please write and plan on sharing a sentence about PE and KE about the animation below. Copyright © 2010 Ryan P. Murphy

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The monkey has potential energy because of its position in the tree. When she lets go her potential energy is transferred into the energy of motion (KE). and Copyright © 2010 Ryan P. Murphy

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The monkey has potential energy because of its position in the tree. When he lets go his potential energy is transferred into the energy of motion (KE). Copyright © 2010 Ryan P. Murphy

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Video Link! (Optional) Energy changes, Potential and Kinetic Energy. –http://www.youtube.com/watch?v=Jnj8mc04r9Ehttp://www.youtube.com/watch?v=Jnj8mc04r9E

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Activity! PE – KE Skateboarder Simulator Search Phet Skate Board Demo. Download program (Free) -skate-park -skate-park Copyright © 2010 Ryan P. Murphy

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PE = mgh PE = mgh Copyright © 2010 Ryan P. Murphy

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PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) Copyright © 2010 Ryan P. Murphy

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PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) m = mass (in kilograms) m = mass (in kilograms) Copyright © 2010 Ryan P. Murphy

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PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) m = mass (in kilograms) m = mass (in kilograms) g = gravitational acceleration of the earth (9.8 m/s²) g = gravitational acceleration of the earth (9.8 m/s²) Copyright © 2010 Ryan P. Murphy

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PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) m = mass (in kilograms) m = mass (in kilograms) g = gravitational acceleration of the earth (9.8 m/s²) g = gravitational acceleration of the earth (9.8 m/s²) h = height above Earth's surface (in meters) h = height above Earth's surface (in meters) Copyright © 2010 Ryan P. Murphy

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PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) m = mass (in kilograms) m = mass (in kilograms) g = gravitational acceleration of the earth (9.8 m/s²) g = gravitational acceleration of the earth (9.8 m/s²) h = height above Earth's surface (in meters) h = height above Earth's surface (in meters) Copyright © 2010 Ryan P. Murphy Learn more about Potential Energy at… s/energy/u5l1b.cfm

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Available worksheet, PE, KE, and ME.

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Calculate the potential energy for a 2 kg basketball dropping from a height of 3.5 meters with a velocity of 9.8 m / sec². –Find the PE in Joules? PE=mgh Copyright © 2010 Ryan P. Murphy

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Calculate the potential energy for a 2 kg basketball dropping from a height of 3.5 meters with a velocity of 9.8 m / s². –Find the PE in Joules? PE=mgh Copyright © 2010 Ryan P. Murphy

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Calculate the potential energy for a 2 kg basketball dropping from a height of 3.5 meters with a velocity of 9.8 m / s². –Find the PE in Joules? PE=mgh Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2 kg g = 9.8 m/sec2 h = 3.5 m Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2 kg g = 9.8 m/sec2 h = 3.5 m Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m PE = (2 kg ) (9.8 m/s²) (3.5 m) Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m PE = (2 kg ) (9.8 m/s²) (3.5 m) PE = Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m PE = (2 kg ) (9.8 m/s²) (3.5 m) PE = 68.6 Joules Copyright © 2010 Ryan P. Murphy

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Available worksheet, PE, KE, and ME.

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Calculate the potential energy of a shot put dropping from a height of 6 meters weighing 5.44 kg with a velocity of 9.8 m/s². – Find the PE in Joules? Copyright © 2010 Ryan P. Murphy

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Calculate the potential energy of a shot put dropping from a height of 6 meters weighing 5.44 kg with a velocity of 9.8 m/s². – Find the PE in Joules? Copyright © 2010 Ryan P. Murphy

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Calculate the potential energy of a shot put dropping from a height of 6 meters weighing 5.44 kg with a velocity of 9.8 m/s². – Find the PE in Joules? PE=mgh Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 5.44 kg g = 9.8 m/s² h = 6 m Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 5.44 kg g = 9.8 m/s² h = 6 m PE = (5.44kg) (9.8m/s²) (6m) PE = Copyright © 2010 Ryan P. Murphy

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Answer: PE = Joules. Copyright © 2010 Ryan P. Murphy

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Available worksheet, PE, KE, and ME.

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Calculate the potential energy for a 2500 kg satellite orbiting at an altitude of 50,000 meters above the surface of the earth if it is traveling with a velocity of 9.8 m/s². Find PE in Joules? –Assume we are using the earth gravity constant.

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Calculate the potential energy for a 2500 kg satellite orbiting at an altitude of 50,000 meters above the surface of the earth if it is traveling with a velocity of 9.8 m/s². Find PE in Joules? –Assume we are using the earth gravity constant.

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Calculate the potential energy for a 2500 kg satellite orbiting at an altitude of 50,000 meters above the surface of the earth if it is traveling with a velocity of 9.8 m/s². Find PE in Joules? PE=mgh –Assume we are using the earth gravity constant.

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Calculate the potential energy for a 2500 kg satellite orbiting at an altitude of 50,000 meters above the surface of the earth if it is traveling with a velocity of 9.8 m/s². Find PE in Joules? PE=mgh –Assume we are using the earth gravity constant.

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PE = mgh m = 2500 kg g = 9.8 m/s² h = 50,000m Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2500 kg g = 9.8 m/s² h = 50,000m Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2500 kg g = 9.8 m/s² h = 50,000m PE = (2500 kg) (9.8 m/s²) (50,000 m) Copyright © 2010 Ryan P. Murphy

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PE = mgh m = 2500 kg g = 9.8 m/s² h = 50,000m PE = (2500 kg) (9.8 m/s²) (50,000 m) PE = ? Copyright © 2010 Ryan P. Murphy

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Or PE = 1,225,000,000 Joules Copyright © 2010 Ryan P. Murphy

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Or PE = 1,225,000,000 Joules Can you put it into scientific notation? Copyright © 2010 Ryan P. Murphy

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Or PE = 1,225,000,000 Joules Can you put it into scientific notation? Copyright © 2010 Ryan P. Murphy 9

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Or PE = 1,225,000,000 Joules Can you put it into scientific notation? Copyright © 2010 Ryan P. Murphy PE = x 10 9 Joules 9

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Kinetic energy Kinetic energy Copyright © 2010 Ryan P. Murphy

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Kinetic energy Kinetic energy The energy that matter has because of its motion and mass. The energy that matter has because of its motion and mass. Copyright © 2010 Ryan P. Murphy

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Kinetic energy Kinetic energy The energy that matter has because of its motion and mass. The energy that matter has because of its motion and mass. Where m = mass of object (kg). Where m = mass of object (kg). Copyright © 2010 Ryan P. Murphy

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Kinetic energy Kinetic energy The energy that matter has because of its motion and mass. The energy that matter has because of its motion and mass. Where m = mass of object (kg). Where m = mass of object (kg). v = speed of object. v = speed of object. Copyright © 2010 Ryan P. Murphy

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Kinetic energy Kinetic energy The energy that matter has because of its motion and mass. The energy that matter has because of its motion and mass. Where m = mass of object (kg). Where m = mass of object (kg). v = speed of object. v = speed of object. KE = Energy in Joules. KE = Energy in Joules. Copyright © 2010 Ryan P. Murphy

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Kinetic energyKinetic energy –The energy that matter has because of its motion and mass. –Where m = mass of object (kg). –v = speed of object. –KE = Energy in Joules. Copyright © 2010 Ryan P. Murphy This equation shows that the kinetic energy of an object is proportional to the square of its speed. For a twofold increase in speed, the kinetic energy will increase by a factor of four.

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Kinetic energyKinetic energy –The energy that matter has because of its motion and mass. –Where m = mass of object (kg). –v = speed of object. –KE = Energy in Joules. Copyright © 2010 Ryan P. Murphy This equation shows that the kinetic energy of an object is proportional to the square of its speed. For a twofold increase in velocity, the kinetic energy will increase by a factor of four.

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Kinetic energy Kinetic energy Copyright © 2010 Ryan P. Murphy

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Kinetic Energy

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Copyright © 2010 Ryan P. Murphy Kinetic Energy

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Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

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Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

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Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

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Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

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Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

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Available worksheet, PE, KE, and ME.

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What is the kinetic energy of a 10 kilogram cannon ball traveling at 50 meters per second? m = 10 kg v = 50 m/s Copyright © 2010 Ryan P. Murphy

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What is the kinetic energy of a 10 kilogram cannon ball traveling at 50 meters per second? m = 10 kg v = 50 m/s Copyright © 2010 Ryan P. Murphy

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What is the kinetic energy of a 10 kilogram cannon ball traveling at 50 meters per second? m = 10 kg v = 50 m/s Copyright © 2010 Ryan P. Murphy

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Don’t forget your order of operations. Copyright © 2010 Ryan P. Murphy

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Don’t forget your order of operations. PEMDAS Copyright © 2010 Ryan P. Murphy

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Don’t forget your order of operations. PEMDAS For KE, you must do exponents (E) before multiplying (M). Copyright © 2010 Ryan P. Murphy

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Don’t forget your order of operations. PEMDAS For KE, you must do exponents (E) before multiplying (M). Copyright © 2010 Ryan P. Murphy

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Don’t forget your order of operations. PEMDAS For KE, you must do exponents (E) before multiplying (M). Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times 10 kg times (50) ² Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules KE = 5 kg times 2,500 Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules KE = 5 kg times 2,500 Joules KE = Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules KE = 5 kg times 2,500 Joules KE = 12,500 Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules KE = 5 kg times 2,500 Joules KE = 12,500 Joules Copyright © 2010 Ryan P. Murphy

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Available worksheet, PE, KE, and ME.

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What is the kinetic energy of a.142 kilogram baseball traveling at 45 meters per second? m =.142 kg v = 45 m/s Copyright © 2010 Ryan P. Murphy

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What is the kinetic energy of a.142 kilogram baseball traveling at 45 meters per second? m =.142 kg v = 45 m/s Copyright © 2010 Ryan P. Murphy

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What is the kinetic energy of a.142 kilogram baseball traveling at 45 meters per second? m =.142 kg v = 45 m/s Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times.142 kg times (45) ² Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules Copyright © 2010 Ryan P. Murphy PEMDASPEMDAS

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KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules KE =.071 kg times 2,025 Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules KE =.071 kg times 2,025 Joules KE = Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules KE =.071 kg times 2,025 Joules KE = Joules Copyright © 2010 Ryan P. Murphy

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KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules KE =.071 kg times 2,025 Joules KE = Joules Copyright © 2010 Ryan P. Murphy

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Mechanical Energy (ME): Energy due to position and motion. Mechanical Energy (ME): Energy due to position and motion. - Copyright © 2010 Ryan P. Murphy

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Mechanical Energy (ME): Energy due to position and motion. Mechanical Energy (ME): Energy due to position and motion. Sum of potential and kinetic energies, includes heat and friction. PE + KE = ME Sum of potential and kinetic energies, includes heat and friction. PE + KE = ME Copyright © 2010 Ryan P. Murphy

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Available worksheet, PE, KE, and ME.

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A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy?

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A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy?

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A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy?

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A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy? ME = PE + KE

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A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy? ME = PE + KE ME = 6,500 J + 10,500 J

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A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy? ME = PE + KE ME = 6,500 J + 10,500 J ME =

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A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy? ME = PE + KE ME = 6,500 J + 10,500 J ME = 17,000 Joules.

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Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V 2 –(Assume all energy in the vault was transformed into potential energy to make this question easier.) “The homework isn’t color coded.” “The homework isn’t color coded.”

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Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V 2 –(Assume all energy in the vault was transformed into potential energy to make this question easier.) “The homework isn’t color coded.” “The homework isn’t color coded.”

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Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.) KE = ½ m * V KE = ½ m * V ² KE =

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Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.) KE = ½ m * V KE = ½ m * V ² KE =.5* 77 kg * 8.3 m/s KE =

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Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.) KE = ½ m * V KE = ½ m * V ² KE =.5* 77 kg * 8.3 m/s KE =.5* 77 kg * m/s KE =

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Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.) KE = ½ m * V KE = ½ m * V ² KE =.5* 77 kg * 8.3 m/s KE =.5* 77 kg * m/s KE = Joules

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) “Organize your work please.”

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules KE = Joules

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules KE = Joules Joules for heat, sound, and other losses.

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Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules KE = Joules Joules for heat, sound, and other losses.

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Activity! Please make a roller coaster on a page in your science journal. –Color Key Areas with high potential energy and kinetic energy. Copyright © 2010 Ryan P. Murphy

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Activity! Please make a roller coaster on a page in your science journal. –Color Key Areas with high potential energy and kinetic energy. Copyright © 2010 Ryan P. Murphy

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Activity! Please make a roller coaster on a page in your science journal. –Color Key Areas with high potential energy and kinetic energy. Copyright © 2010 Ryan P. Murphy

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Centripetal Force: A force that makes a body follow a curved path. Centripetal Force: A force that makes a body follow a curved path. Copyright © 2010 Ryan P. Murphy

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Centripetal Force: A force that makes a body follow a curved path. Centripetal Force: A force that makes a body follow a curved path. Copyright © 2010 Ryan P. Murphy

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Video! Centripetal Force –http://www.youtube.com/watch?v=XWCBk9Vl-rchttp://www.youtube.com/watch?v=XWCBk9Vl-rc

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Gravity from the mass of the sun keeps the earth from heading out into space. Copyright © 2010 Ryan P. Murphy

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Gravity from the mass of the sun keeps the earth from heading out into space. Copyright © 2010 Ryan P. Murphy

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Gravity from the mass of the sun keeps the earth from heading out into space. Copyright © 2010 Ryan P. Murphy

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The World of the Hammer Throw. Centripetal and Centrifugal Force –http://www.youtube.com/watch?v=tB00eDfTNhshttp://www.youtube.com/watch?v=tB00eDfTNhs

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Activity (Optional) Funky foam tube roller coaster. –Use ½ inch foam pipe insulation cut in half, duct tape to connect the tubes and anchor, cup to catch at end, and marbles.

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Create a one page visual of a roller coaster with drawings. –Name your coaster. –Create a not to scale visual that will be achievable with the materials provided by teacher. –Class will vote to choose a model and build the coaster. –Calculate the PE and KE. –Find the mass of the marble. –Measure the height of the coaster. –Calculate the velocity. Distance / meters divided by seconds and direction

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Create a one page visual of a roller coaster with drawings. –Name your coaster. –Create a not to scale visual that will be achievable with the materials provided by teacher. –Class will vote to choose a model and then build the coaster. –Calculate the PE and KE. –Find the mass of the marble. –Measure the height of the coaster. –Calculate the velocity. Distance / meters divided by seconds and direction

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Academic Link! (Optional) –http://www.youtube.com/watch?v=BSWl_Zj-CZshttp://www.youtube.com/watch?v=BSWl_Zj-CZs

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F=MA, PE, KE and more ramp activity. –Available Sheet

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Activity! Kinetic and Potential Energy + Newton’s Laws F=MA. Copyright © 2010 Ryan P. Murphy

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Activity! Kinetic and Potential Energy + Newton’s Laws F=MA. Copyright © 2010 Ryan P. Murphy

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Please create this spreadsheet in your journal. Truck (D Battery) Car (AA Batter) – Cup (Parked Car) Ramp Height Parked car One Washer Parked Car Two Washer Parked Car Three Washers Lowest (Distance of Parked Car) AA –Car_________ D – Truck________ AA –Car_________ D – Truck________ Middle (Distance of Parked Car) AA –Car___________ D – Truck__________ AA –Car_________ D – Truck________ Highest (Distance of Parked Car) AA –Car___________ D – Truck__________ AA –Car_________ D – Truck________ Copyright © 2010 Ryan P. Murphy Make Prediction after data collection,

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Set-up of the activity. The height can change by placing the rectangular block on its various sides. Copyright © 2010 Ryan P. Murphy Ramp start line Plastic Cup Washers 1-3 5cm gap Height Meter Stick to measure distance cup “parked car” travels after hit. D AA

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Conduct trials with small car (AA Battery) with one and three washers and the three different heights, measuring the distance the parked car traveled after hit in cm. Repeat with Truck / D Battery. – Do not do medium height as we will predict later. Copyright © 2010 Ryan P. Murphy

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F=MA, PE, KE and more ramp activity. –Available Sheet

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F=MA, PE, KE and more ramp activity. –Available Sheet

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Based on your data, make a prediction for the distance the parked car should travel for both the small car (AA) and truck (D) on your spreadsheets for medium height with two washers. Copyright © 2010 Ryan P. Murphy

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Based on your data, make a prediction for the distance the parked car should travel for both the small car (AA) and truck (D) on your spreadsheets for medium height with two washers. –Run some trials afterward to see if your prediction is correct. Copyright © 2010 Ryan P. Murphy

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Increase in Friction / Mass to move.

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F=MA, PE, KE and more ramp activity. –Available Sheet

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F=MA, PE, KE and more ramp activity. –Available Sheet

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How did the height of the ramp affect the movement of the parked car? – Use potential energy and kinetic energy in your response. –Measure the height of the ramp, mass of the batteries, and determine the Potential Energy. PE=mgh Copyright © 2010 Ryan P. Murphy

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How did the resistance to force (washers) affect the movement of the parked car? Copyright © 2010 Ryan P. Murphy

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How did the height of the ramp affect the movement of the parked car? Copyright © 2010 Ryan P. Murphy

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How did the height of the ramp affect the movement of the parked car? –Increasing the height of the ramp increased the batteries potential energy. Copyright © 2010 Ryan P. Murphy

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How did the height of the ramp affect the movement of the parked car? –Increasing the height of the ramp increased the batteries potential energy. This increase of potential energy created an increase in kinetic energy / (Acceleration) which caused the parked car to move further (force). Copyright © 2010 Ryan P. Murphy

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How did the resistance to force (washers) affect the movement of the parked car? Copyright © 2010 Ryan P. Murphy

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How did the resistance to force (washers) affect the movement of the parked car? –The more mass added to the parked car (washers) decreased the distance it traveled after being struck. Copyright © 2010 Ryan P. Murphy

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity 2 –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/sec –Velocity 3 m/sec

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/sec –Velocity 3 m/sec

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s Organize your work! PE= mgh PE = ____ * ___ * ____ PE = Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules Organize your work! PE= mgh PE = ____ * ___ * ____ PE = Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules PE=mgh

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules PE=mgh PE=.148kg * 9.8 m/s *.06m PE=.148kg * 9.8 m/s² *.06m

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules PE=mgh PE=.148kg * 9.8 m/s *.06m PE=.148kg * 9.8 m/s² *.06m

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules PE=mgh PE=.148kg * 9.8 m/s *.06m PE=.148kg * 9.8 m/s² *.06m PE =.087 Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ²

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ²

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ²

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ²

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules KE =.666 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules KE =.666 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules KE =.666 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules Mechanical Energy (ME) =

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Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules KE =.666 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules Mechanical Energy (ME) =.753 Joules

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Question on homework: Describe three ways potential energy of position as well as potential chemical energy are combined with kinetic energy to generate kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

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Question on homework: Describe three ways potential energy of position as well as potential chemical energy are combined with kinetic energy to generate kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

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Hydropower : Potential energy turned into kinetic energy of motion turned into kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

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Hydropower : Potential energy turned into kinetic energy of motion turned into kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

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Hydropower gave rise to early industry. –One of our earliest ways to harness energy. Copyright © 2010 Ryan P. Murphy

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Hydropower gave rise to early industry. –One of our earliest ways to harness energy. Copyright © 2010 Ryan P. Murphy Potential Energy

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Hydropower gave rise to early industry. –One of our earliest ways to harness energy. Copyright © 2010 Ryan P. Murphy Potential Energy Transfer to Kinetic Energy Transfer to Kinetic Energy

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In Dinowrig, Wales. Water is pumped from the lower lake to the upper lake when electricity is low in demand.

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During times high electrical demand, the stored potential energy flows downhill to generate electricity (Kinetic).

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Kinetic energy to kinetic electrical energy Copyright © 2010 Ryan P. Murphy

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Gravity turns potential energy in tides, into kinetic energy (flowing tides) into kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

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Geothermal Copyright © 2010 Ryan P. Murphy

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Geothermal -Kinetic energy heat, turns water into steam, water rises and runs a turbine to generate electrical energy. Copyright © 2010 Ryan P. Murphy

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Geothermal -Kinetic energy heat, turns water into steam, water rises and runs a turbine to generate electrical energy. Copyright © 2010 Ryan P. Murphy

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Geothermal -Kinetic energy heat, turns water into steam, water rises and runs a turbine to generate kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

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Steam / Coal and wood burning electric plant

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Nuclear energy – Nuclear reactions generate kinetic electrical energy using water, steam, and a turbine.

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When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic) used to move your arm and the object upward and into heat given off by your body. Copyright © 2010 Ryan P. Murphy

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When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic). Which is then used to move your body. Heat is produced Copyright © 2010 Ryan P. Murphy

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When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic). Which is then used to move your body. Heat is produced Copyright © 2010 Ryan P. Murphy

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When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic). Which is then used to move your body. Heat is produced Copyright © 2010 Ryan P. Murphy

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When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic). Which is then used to move your body. Heat is released. Copyright © 2010 Ryan P. Murphy

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