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Available worksheet, PE, KE, and ME. First Law of Energy (Thermodynamics) First Law of Energy (Thermodynamics) All energy is either kinetic or potential.

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Presentation on theme: "Available worksheet, PE, KE, and ME. First Law of Energy (Thermodynamics) First Law of Energy (Thermodynamics) All energy is either kinetic or potential."— Presentation transcript:

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2 Available worksheet, PE, KE, and ME.

3 First Law of Energy (Thermodynamics) First Law of Energy (Thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

4 First Law of Energy (thermodynamics) First Law of Energy (thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

5 First Law of energy (thermodynamics) First Law of energy (thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

6 First Law of Energy (thermodynamics) First Law of Energy (thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

7 First Law of Energy (thermodynamics) First Law of Energy (thermodynamics) All energy is either kinetic or potential. All energy is either kinetic or potential. Copyright © 2010 Ryan P. Murphy

8 Potential Energy: (PE) The energy stored by an object as a result of its position. Potential Energy: (PE) The energy stored by an object as a result of its position. Copyright © 2010 Ryan P. Murphy

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11 Potential Enegy (PE)Kinetic Energy (KE)

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15 Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Kinetic Energy is the energy of motion. Kinetic Energy is the energy of motion. Copyright © 2010 Ryan P. Murphy

16 Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Kinetic Energy is the energy of motion. Kinetic Energy is the energy of motion. Copyright © 2010 Ryan P. Murphy

17 Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Potential Energy is the energy of position. Objects that are elevated have a high potential energy. Kinetic Energy is the energy of motion. Kinetic Energy is the energy of motion. Copyright © 2010 Ryan P. Murphy

18 Available worksheet, PE, KE, and ME.

19 Activity! Please write and plan on sharing a sentence about PE and KE about the animation below. Copyright © 2010 Ryan P. Murphy

20 Activity! Please write and plan on sharing a sentence about PE and KE about the animation below. Copyright © 2010 Ryan P. Murphy

21 The monkey has potential energy because of its position in the tree. When she lets go her potential energy is transferred into the energy of motion (KE). and Copyright © 2010 Ryan P. Murphy

22 The monkey has potential energy because of its position in the tree. When he lets go his potential energy is transferred into the energy of motion (KE). Copyright © 2010 Ryan P. Murphy

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37 Video Link! (Optional) Energy changes, Potential and Kinetic Energy. –http://www.youtube.com/watch?v=Jnj8mc04r9Ehttp://www.youtube.com/watch?v=Jnj8mc04r9E

38 Activity! PE – KE Skateboarder Simulator Search Phet Skate Board Demo. Download program (Free) -skate-park -skate-park Copyright © 2010 Ryan P. Murphy

39 PE = mgh PE = mgh Copyright © 2010 Ryan P. Murphy

40 PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) Copyright © 2010 Ryan P. Murphy

41 PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) m = mass (in kilograms) m = mass (in kilograms) Copyright © 2010 Ryan P. Murphy

42 PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) m = mass (in kilograms) m = mass (in kilograms) g = gravitational acceleration of the earth (9.8 m/s²) g = gravitational acceleration of the earth (9.8 m/s²) Copyright © 2010 Ryan P. Murphy

43 PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) m = mass (in kilograms) m = mass (in kilograms) g = gravitational acceleration of the earth (9.8 m/s²) g = gravitational acceleration of the earth (9.8 m/s²) h = height above Earth's surface (in meters) h = height above Earth's surface (in meters) Copyright © 2010 Ryan P. Murphy

44 PE = mgh PE = mgh PE = Energy (in Joules) PE = Energy (in Joules) m = mass (in kilograms) m = mass (in kilograms) g = gravitational acceleration of the earth (9.8 m/s²) g = gravitational acceleration of the earth (9.8 m/s²) h = height above Earth's surface (in meters) h = height above Earth's surface (in meters) Copyright © 2010 Ryan P. Murphy Learn more about Potential Energy at… s/energy/u5l1b.cfm

45 Available worksheet, PE, KE, and ME.

46 Calculate the potential energy for a 2 kg basketball dropping from a height of 3.5 meters with a velocity of 9.8 m / sec². –Find the PE in Joules? PE=mgh Copyright © 2010 Ryan P. Murphy

47 Calculate the potential energy for a 2 kg basketball dropping from a height of 3.5 meters with a velocity of 9.8 m / s². –Find the PE in Joules? PE=mgh Copyright © 2010 Ryan P. Murphy

48 Calculate the potential energy for a 2 kg basketball dropping from a height of 3.5 meters with a velocity of 9.8 m / s². –Find the PE in Joules? PE=mgh Copyright © 2010 Ryan P. Murphy

49 PE = mgh m = 2 kg g = 9.8 m/sec2 h = 3.5 m Copyright © 2010 Ryan P. Murphy

50 PE = mgh m = 2 kg g = 9.8 m/sec2 h = 3.5 m Copyright © 2010 Ryan P. Murphy

51 PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m Copyright © 2010 Ryan P. Murphy

52 PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m Copyright © 2010 Ryan P. Murphy

53 PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m PE = (2 kg ) (9.8 m/s²) (3.5 m) Copyright © 2010 Ryan P. Murphy

54 PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m PE = (2 kg ) (9.8 m/s²) (3.5 m) PE = Copyright © 2010 Ryan P. Murphy

55 PE = mgh m = 2 kg g = 9.8 m/s² h = 3.5 m PE = (2 kg ) (9.8 m/s²) (3.5 m) PE = 68.6 Joules Copyright © 2010 Ryan P. Murphy

56 Available worksheet, PE, KE, and ME.

57 Calculate the potential energy of a shot put dropping from a height of 6 meters weighing 5.44 kg with a velocity of 9.8 m/s². – Find the PE in Joules? Copyright © 2010 Ryan P. Murphy

58 Calculate the potential energy of a shot put dropping from a height of 6 meters weighing 5.44 kg with a velocity of 9.8 m/s². – Find the PE in Joules? Copyright © 2010 Ryan P. Murphy

59 Calculate the potential energy of a shot put dropping from a height of 6 meters weighing 5.44 kg with a velocity of 9.8 m/s². – Find the PE in Joules? PE=mgh Copyright © 2010 Ryan P. Murphy

60 PE = mgh m = 5.44 kg g = 9.8 m/s² h = 6 m Copyright © 2010 Ryan P. Murphy

61 PE = mgh m = 5.44 kg g = 9.8 m/s² h = 6 m PE = (5.44kg) (9.8m/s²) (6m) PE = Copyright © 2010 Ryan P. Murphy

62 Answer: PE = Joules. Copyright © 2010 Ryan P. Murphy

63 Available worksheet, PE, KE, and ME.

64 Calculate the potential energy for a 2500 kg satellite orbiting at an altitude of 50,000 meters above the surface of the earth if it is traveling with a velocity of 9.8 m/s². Find PE in Joules? –Assume we are using the earth gravity constant.

65 Calculate the potential energy for a 2500 kg satellite orbiting at an altitude of 50,000 meters above the surface of the earth if it is traveling with a velocity of 9.8 m/s². Find PE in Joules? –Assume we are using the earth gravity constant.

66 Calculate the potential energy for a 2500 kg satellite orbiting at an altitude of 50,000 meters above the surface of the earth if it is traveling with a velocity of 9.8 m/s². Find PE in Joules? PE=mgh –Assume we are using the earth gravity constant.

67 Calculate the potential energy for a 2500 kg satellite orbiting at an altitude of 50,000 meters above the surface of the earth if it is traveling with a velocity of 9.8 m/s². Find PE in Joules? PE=mgh –Assume we are using the earth gravity constant.

68 PE = mgh m = 2500 kg g = 9.8 m/s² h = 50,000m Copyright © 2010 Ryan P. Murphy

69 PE = mgh m = 2500 kg g = 9.8 m/s² h = 50,000m Copyright © 2010 Ryan P. Murphy

70 PE = mgh m = 2500 kg g = 9.8 m/s² h = 50,000m PE = (2500 kg) (9.8 m/s²) (50,000 m) Copyright © 2010 Ryan P. Murphy

71 PE = mgh m = 2500 kg g = 9.8 m/s² h = 50,000m PE = (2500 kg) (9.8 m/s²) (50,000 m) PE = ? Copyright © 2010 Ryan P. Murphy

72 Or PE = 1,225,000,000 Joules Copyright © 2010 Ryan P. Murphy

73 Or PE = 1,225,000,000 Joules Can you put it into scientific notation? Copyright © 2010 Ryan P. Murphy

74 Or PE = 1,225,000,000 Joules Can you put it into scientific notation? Copyright © 2010 Ryan P. Murphy 9

75 Or PE = 1,225,000,000 Joules Can you put it into scientific notation? Copyright © 2010 Ryan P. Murphy PE = x 10 9 Joules 9

76 Kinetic energy Kinetic energy Copyright © 2010 Ryan P. Murphy

77 Kinetic energy Kinetic energy The energy that matter has because of its motion and mass. The energy that matter has because of its motion and mass. Copyright © 2010 Ryan P. Murphy

78 Kinetic energy Kinetic energy The energy that matter has because of its motion and mass. The energy that matter has because of its motion and mass. Where m = mass of object (kg). Where m = mass of object (kg). Copyright © 2010 Ryan P. Murphy

79 Kinetic energy Kinetic energy The energy that matter has because of its motion and mass. The energy that matter has because of its motion and mass. Where m = mass of object (kg). Where m = mass of object (kg). v = speed of object. v = speed of object. Copyright © 2010 Ryan P. Murphy

80 Kinetic energy Kinetic energy The energy that matter has because of its motion and mass. The energy that matter has because of its motion and mass. Where m = mass of object (kg). Where m = mass of object (kg). v = speed of object. v = speed of object. KE = Energy in Joules. KE = Energy in Joules. Copyright © 2010 Ryan P. Murphy

81 Kinetic energyKinetic energy –The energy that matter has because of its motion and mass. –Where m = mass of object (kg). –v = speed of object. –KE = Energy in Joules. Copyright © 2010 Ryan P. Murphy This equation shows that the kinetic energy of an object is proportional to the square of its speed. For a twofold increase in speed, the kinetic energy will increase by a factor of four.

82 Kinetic energyKinetic energy –The energy that matter has because of its motion and mass. –Where m = mass of object (kg). –v = speed of object. –KE = Energy in Joules. Copyright © 2010 Ryan P. Murphy This equation shows that the kinetic energy of an object is proportional to the square of its speed. For a twofold increase in velocity, the kinetic energy will increase by a factor of four.

83 Kinetic energy Kinetic energy Copyright © 2010 Ryan P. Murphy

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85 Kinetic Energy

86 Copyright © 2010 Ryan P. Murphy Kinetic Energy

87 Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

88 Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

89 Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

90 Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

91 Amount of KE depends on both the objects mass and its velocity / (speed).Amount of KE depends on both the objects mass and its velocity / (speed). Copyright © 2010 Ryan P. Murphy

92 Available worksheet, PE, KE, and ME.

93 What is the kinetic energy of a 10 kilogram cannon ball traveling at 50 meters per second? m = 10 kg v = 50 m/s Copyright © 2010 Ryan P. Murphy

94 What is the kinetic energy of a 10 kilogram cannon ball traveling at 50 meters per second? m = 10 kg v = 50 m/s Copyright © 2010 Ryan P. Murphy

95 What is the kinetic energy of a 10 kilogram cannon ball traveling at 50 meters per second? m = 10 kg v = 50 m/s Copyright © 2010 Ryan P. Murphy

96 Don’t forget your order of operations. Copyright © 2010 Ryan P. Murphy

97 Don’t forget your order of operations. PEMDAS Copyright © 2010 Ryan P. Murphy

98 Don’t forget your order of operations. PEMDAS For KE, you must do exponents (E) before multiplying (M). Copyright © 2010 Ryan P. Murphy

99 Don’t forget your order of operations. PEMDAS For KE, you must do exponents (E) before multiplying (M). Copyright © 2010 Ryan P. Murphy

100 Don’t forget your order of operations. PEMDAS For KE, you must do exponents (E) before multiplying (M). Copyright © 2010 Ryan P. Murphy

101 KE = 0.5 times 10 kg times (50) ² Joules Copyright © 2010 Ryan P. Murphy

102 KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules Copyright © 2010 Ryan P. Murphy

103 KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules Copyright © 2010 Ryan P. Murphy

104 KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules Copyright © 2010 Ryan P. Murphy

105 KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules KE = 5 kg times 2,500 Joules Copyright © 2010 Ryan P. Murphy

106 KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules KE = 5 kg times 2,500 Joules KE = Copyright © 2010 Ryan P. Murphy

107 KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules KE = 5 kg times 2,500 Joules KE = 12,500 Joules Copyright © 2010 Ryan P. Murphy

108 KE = 0.5 times 10 kg times (50) ² Joules KE = 0.5 times 10 kg times 2,500 Joules KE = 5 kg times 2,500 Joules KE = 12,500 Joules Copyright © 2010 Ryan P. Murphy

109 Available worksheet, PE, KE, and ME.

110 What is the kinetic energy of a.142 kilogram baseball traveling at 45 meters per second? m =.142 kg v = 45 m/s Copyright © 2010 Ryan P. Murphy

111 What is the kinetic energy of a.142 kilogram baseball traveling at 45 meters per second? m =.142 kg v = 45 m/s Copyright © 2010 Ryan P. Murphy

112 What is the kinetic energy of a.142 kilogram baseball traveling at 45 meters per second? m =.142 kg v = 45 m/s Copyright © 2010 Ryan P. Murphy

113 KE = 0.5 times.142 kg times (45) ² Joules Copyright © 2010 Ryan P. Murphy

114 KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules Copyright © 2010 Ryan P. Murphy PEMDASPEMDAS

115 KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules Copyright © 2010 Ryan P. Murphy

116 KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules KE =.071 kg times 2,025 Joules Copyright © 2010 Ryan P. Murphy

117 KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules KE =.071 kg times 2,025 Joules KE = Copyright © 2010 Ryan P. Murphy

118 KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules KE =.071 kg times 2,025 Joules KE = Joules Copyright © 2010 Ryan P. Murphy

119 KE = 0.5 times.142 kg times (45) ² Joules KE = 0.5 times.142 kg times 2,025 Joules KE =.071 kg times 2,025 Joules KE = Joules Copyright © 2010 Ryan P. Murphy

120 Mechanical Energy (ME): Energy due to position and motion. Mechanical Energy (ME): Energy due to position and motion. - Copyright © 2010 Ryan P. Murphy

121 Mechanical Energy (ME): Energy due to position and motion. Mechanical Energy (ME): Energy due to position and motion. Sum of potential and kinetic energies, includes heat and friction. PE + KE = ME Sum of potential and kinetic energies, includes heat and friction. PE + KE = ME Copyright © 2010 Ryan P. Murphy

122 Available worksheet, PE, KE, and ME.

123 A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy?

124 A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy?

125 A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy?

126 A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy? ME = PE + KE

127 A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy? ME = PE + KE ME = 6,500 J + 10,500 J

128 A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy? ME = PE + KE ME = 6,500 J + 10,500 J ME =

129 A ski jumper moving down the hill had a Potential Energy of 6,500 Joules, and a Kinetic Energy of 10,500 Joules. –What is her Mechanical Energy? ME = PE + KE ME = 6,500 J + 10,500 J ME = 17,000 Joules.

130 Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

131 Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

132 Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V 2 –(Assume all energy in the vault was transformed into potential energy to make this question easier.) “The homework isn’t color coded.” “The homework isn’t color coded.”

133 Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V 2 –(Assume all energy in the vault was transformed into potential energy to make this question easier.) “The homework isn’t color coded.” “The homework isn’t color coded.”

134 Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

135 Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.) KE = ½ m * V KE = ½ m * V ² KE =

136 Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.) KE = ½ m * V KE = ½ m * V ² KE =.5* 77 kg * 8.3 m/s KE =

137 Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.) KE = ½ m * V KE = ½ m * V ² KE =.5* 77 kg * 8.3 m/s KE =.5* 77 kg * m/s KE =

138 Please calculate the potential energy of a pole-vaulter at the top of their vault. The run into the vault was 8.3 m/s and they weighed 77 kilograms. KE= ½ m * V ² –(Assume all energy in the vault was transformed into potential energy to make this question easier.) KE = ½ m * V KE = ½ m * V ² KE =.5* 77 kg * 8.3 m/s KE =.5* 77 kg * m/s KE = Joules

139 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

140 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

141 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

142 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

143 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

144 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

145 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.)

146 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) “Organize your work please.”

147 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh

148 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m

149 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules

150 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules

151 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules KE = Joules

152 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules KE = Joules Joules for heat, sound, and other losses.

153 Please calculate the potential energy of a pole-vaulter at the top of their vault. Their height was 3 meters and they weighed 77 kilograms. PE= mgh (9.8 m/s²) –(Assume all energy in the vault was transformed into potential energy to make this question easier.) PE= mgh PE = 77 kg* 9.8 m/s * 3 m PE = 77 kg* 9.8 m/s² * 3 m PE = Joules KE = Joules Joules for heat, sound, and other losses.

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155 Activity! Please make a roller coaster on a page in your science journal. –Color Key Areas with high potential energy and kinetic energy. Copyright © 2010 Ryan P. Murphy

156 Activity! Please make a roller coaster on a page in your science journal. –Color Key Areas with high potential energy and kinetic energy. Copyright © 2010 Ryan P. Murphy

157 Activity! Please make a roller coaster on a page in your science journal. –Color Key Areas with high potential energy and kinetic energy. Copyright © 2010 Ryan P. Murphy

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159 Centripetal Force: A force that makes a body follow a curved path. Centripetal Force: A force that makes a body follow a curved path. Copyright © 2010 Ryan P. Murphy

160 Centripetal Force: A force that makes a body follow a curved path. Centripetal Force: A force that makes a body follow a curved path. Copyright © 2010 Ryan P. Murphy

161 Video! Centripetal Force –http://www.youtube.com/watch?v=XWCBk9Vl-rchttp://www.youtube.com/watch?v=XWCBk9Vl-rc

162 Gravity from the mass of the sun keeps the earth from heading out into space. Copyright © 2010 Ryan P. Murphy

163 Gravity from the mass of the sun keeps the earth from heading out into space. Copyright © 2010 Ryan P. Murphy

164 Gravity from the mass of the sun keeps the earth from heading out into space. Copyright © 2010 Ryan P. Murphy

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166 The World of the Hammer Throw. Centripetal and Centrifugal Force –http://www.youtube.com/watch?v=tB00eDfTNhshttp://www.youtube.com/watch?v=tB00eDfTNhs

167 Activity (Optional) Funky foam tube roller coaster. –Use ½ inch foam pipe insulation cut in half, duct tape to connect the tubes and anchor, cup to catch at end, and marbles.

168 Create a one page visual of a roller coaster with drawings. –Name your coaster. –Create a not to scale visual that will be achievable with the materials provided by teacher. –Class will vote to choose a model and build the coaster. –Calculate the PE and KE. –Find the mass of the marble. –Measure the height of the coaster. –Calculate the velocity. Distance / meters divided by seconds and direction

169 Create a one page visual of a roller coaster with drawings. –Name your coaster. –Create a not to scale visual that will be achievable with the materials provided by teacher. –Class will vote to choose a model and then build the coaster. –Calculate the PE and KE. –Find the mass of the marble. –Measure the height of the coaster. –Calculate the velocity. Distance / meters divided by seconds and direction

170 Academic Link! (Optional) –http://www.youtube.com/watch?v=BSWl_Zj-CZshttp://www.youtube.com/watch?v=BSWl_Zj-CZs

171 F=MA, PE, KE and more ramp activity. –Available Sheet

172 Activity! Kinetic and Potential Energy + Newton’s Laws F=MA. Copyright © 2010 Ryan P. Murphy

173 Activity! Kinetic and Potential Energy + Newton’s Laws F=MA. Copyright © 2010 Ryan P. Murphy

174 Please create this spreadsheet in your journal. Truck (D Battery) Car (AA Batter) – Cup (Parked Car) Ramp Height Parked car One Washer Parked Car Two Washer Parked Car Three Washers Lowest (Distance of Parked Car) AA –Car_________ D – Truck________ AA –Car_________ D – Truck________ Middle (Distance of Parked Car) AA –Car___________ D – Truck__________ AA –Car_________ D – Truck________ Highest (Distance of Parked Car) AA –Car___________ D – Truck__________ AA –Car_________ D – Truck________ Copyright © 2010 Ryan P. Murphy Make Prediction after data collection,

175 Set-up of the activity. The height can change by placing the rectangular block on its various sides. Copyright © 2010 Ryan P. Murphy Ramp start line Plastic Cup Washers 1-3 5cm gap Height Meter Stick to measure distance cup “parked car” travels after hit. D AA

176 Conduct trials with small car (AA Battery) with one and three washers and the three different heights, measuring the distance the parked car traveled after hit in cm. Repeat with Truck / D Battery. – Do not do medium height as we will predict later. Copyright © 2010 Ryan P. Murphy

177 F=MA, PE, KE and more ramp activity. –Available Sheet

178 F=MA, PE, KE and more ramp activity. –Available Sheet

179 Based on your data, make a prediction for the distance the parked car should travel for both the small car (AA) and truck (D) on your spreadsheets for medium height with two washers. Copyright © 2010 Ryan P. Murphy

180 Based on your data, make a prediction for the distance the parked car should travel for both the small car (AA) and truck (D) on your spreadsheets for medium height with two washers. –Run some trials afterward to see if your prediction is correct. Copyright © 2010 Ryan P. Murphy

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186 Increase in Friction / Mass to move.

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193 F=MA, PE, KE and more ramp activity. –Available Sheet

194 F=MA, PE, KE and more ramp activity. –Available Sheet

195 How did the height of the ramp affect the movement of the parked car? – Use potential energy and kinetic energy in your response. –Measure the height of the ramp, mass of the batteries, and determine the Potential Energy. PE=mgh Copyright © 2010 Ryan P. Murphy

196 How did the resistance to force (washers) affect the movement of the parked car? Copyright © 2010 Ryan P. Murphy

197 How did the height of the ramp affect the movement of the parked car? Copyright © 2010 Ryan P. Murphy

198 How did the height of the ramp affect the movement of the parked car? –Increasing the height of the ramp increased the batteries potential energy. Copyright © 2010 Ryan P. Murphy

199 How did the height of the ramp affect the movement of the parked car? –Increasing the height of the ramp increased the batteries potential energy. This increase of potential energy created an increase in kinetic energy / (Acceleration) which caused the parked car to move further (force). Copyright © 2010 Ryan P. Murphy

200 How did the resistance to force (washers) affect the movement of the parked car? Copyright © 2010 Ryan P. Murphy

201 How did the resistance to force (washers) affect the movement of the parked car? –The more mass added to the parked car (washers) decreased the distance it traveled after being struck. Copyright © 2010 Ryan P. Murphy

202 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity 2 –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/sec –Velocity 3 m/sec

203 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/sec –Velocity 3 m/sec

204 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s

205 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s Organize your work! PE= mgh PE = ____ * ___ * ____ PE = Joules

206 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s

207 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

208 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

209 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

210 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

211 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

212 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules Organize your work! PE= mgh PE = ____ * ___ * ____ PE = Joules

213 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules PE=mgh

214 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules PE=mgh PE=.148kg * 9.8 m/s *.06m PE=.148kg * 9.8 m/s² *.06m

215 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules PE=mgh PE=.148kg * 9.8 m/s *.06m PE=.148kg * 9.8 m/s² *.06m

216 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules PE=mgh PE=.148kg * 9.8 m/s *.06m PE=.148kg * 9.8 m/s² *.06m PE =.087 Joules

217 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules

218 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ²

219 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ²

220 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ²

221 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ²

222 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules

223 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules KE =.666 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules

224 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules KE =.666 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules

225 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules KE =.666 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules Mechanical Energy (ME) =

226 Find the Mechanical Energy of the large D battery hitting the parked car from the highest position. PE = mgh KE = ½ mass * velocity² PE =.087 Joules KE =.666 Joules –D Battery mass = 148 g (.148kg) –Height = 6 cm (.06m) –Gravity = 9.8 m/s ² –Velocity 3 m/s –Answer in Joules KE=1/2 m * velocity KE=1/2 m * velocity ² KE=.5 *.148 * 3 m/s KE=.5 *.148 * 3 m/s ² KE=.5 *.148 * 9 m/s KE=.5 *.148 * 9 m/s ² KE =.666 Joules Mechanical Energy (ME) =.753 Joules

227 Question on homework: Describe three ways potential energy of position as well as potential chemical energy are combined with kinetic energy to generate kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

228 Question on homework: Describe three ways potential energy of position as well as potential chemical energy are combined with kinetic energy to generate kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

229 Hydropower : Potential energy turned into kinetic energy of motion turned into kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

230 Hydropower : Potential energy turned into kinetic energy of motion turned into kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

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232 Hydropower gave rise to early industry. –One of our earliest ways to harness energy. Copyright © 2010 Ryan P. Murphy

233 Hydropower gave rise to early industry. –One of our earliest ways to harness energy. Copyright © 2010 Ryan P. Murphy Potential Energy

234 Hydropower gave rise to early industry. –One of our earliest ways to harness energy. Copyright © 2010 Ryan P. Murphy Potential Energy Transfer to Kinetic Energy Transfer to Kinetic Energy

235 In Dinowrig, Wales. Water is pumped from the lower lake to the upper lake when electricity is low in demand.

236 During times high electrical demand, the stored potential energy flows downhill to generate electricity (Kinetic).

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239 Kinetic energy to kinetic electrical energy Copyright © 2010 Ryan P. Murphy

240 Gravity turns potential energy in tides, into kinetic energy (flowing tides) into kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

241 Geothermal Copyright © 2010 Ryan P. Murphy

242 Geothermal -Kinetic energy heat, turns water into steam, water rises and runs a turbine to generate electrical energy. Copyright © 2010 Ryan P. Murphy

243 Geothermal -Kinetic energy heat, turns water into steam, water rises and runs a turbine to generate electrical energy. Copyright © 2010 Ryan P. Murphy

244 Geothermal -Kinetic energy heat, turns water into steam, water rises and runs a turbine to generate kinetic electrical energy. Copyright © 2010 Ryan P. Murphy

245 Steam / Coal and wood burning electric plant

246 Nuclear energy – Nuclear reactions generate kinetic electrical energy using water, steam, and a turbine.

247 When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic) used to move your arm and the object upward and into heat given off by your body. Copyright © 2010 Ryan P. Murphy

248 When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic). Which is then used to move your body. Heat is produced Copyright © 2010 Ryan P. Murphy

249 When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic). Which is then used to move your body. Heat is produced Copyright © 2010 Ryan P. Murphy

250 When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic). Which is then used to move your body. Heat is produced Copyright © 2010 Ryan P. Murphy

251 When you lift an object, chemical energy (a form of potential energy) stored in the chemicals obtained from your digested food is converted into the mechanical energy (kinetic). Which is then used to move your body. Heat is released. Copyright © 2010 Ryan P. Murphy


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