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** Chapter 11: Rotational Dynamics and Static Equilibrium Ch11-1 Torque**

CCW +

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Applying a Torque

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**Ct1: You are using a wrench and trying to loosen a rusty nut**

Ct1: You are using a wrench and trying to loosen a rusty nut. Which of the arrangements shown is least effective in loosening the nut? A B C D

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**Chapter 11: Rotational Dynamics and Static Equilibrium**

Ch11-1 Torque = rF = rFsin

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**Chapter 11: Rotational Dynamics and Static Equilibrium**

Torque = moment arm x force = rF = rsinF The moment arm is the perpendicular distance from rotation axis to the line of action of the force. moment arm line of action of the force

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P11.2 (p.350)

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** = I Torques summed about fixed axis O.**

Chapter 11: Rotational Dynamics and Static Equilibrium CCW + Ch11-2 Torque and Angular Acceleration = I Torques summed about fixed axis O. P11.15 (p.351)

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CT2: Two wheels with fixed hubs, each having a mass of 1 kg, start from rest, and forces are applied as shown. Assume the hubs and spokes are massless, so that the rotational inertia is I = mR2. In order to impart identical angular accelerations, how large must F2 be? A N B. 0.5 N C. 1 N D. 2 N E. 4 N

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** Chapter 11: Rotational Dynamics and Static Equilibrium**

CCW + Ch11-3 Zero Torque and Static Equilibrium F = 0 and = P11.22 (p.351)

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CT3: P11.22c If the mass of the teeter-totter were doubled, the answers to parts a and b for the position of the applied force would double. halve. stay the same.

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P11.31 (p.352)

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**Chapter 11: Rotational Dynamics and Static Equilibrium**

Ch11-4 Center of Mass and Balance Near the Earth, the center of mass is the balance point of an object.

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**Chapter 11: Rotational Dynamics and Static Equilibrium**

Ch11-5 Dynamic Applications of Torque We can finally relax the simplification that a pulley is massless P11.44 (p.353)

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CT4: P11.44a The 25N tension is greater than the tension on the other side. less than the tension on the other side. the same as the tension on the other side.

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**Chapter 11: Rotational Dynamics and Static Equilibrium**

Ch11-6 Angular Momentum p = mv (kgm/s) L = I (fixed axis) (kgm2/s) F = p/t = L/t P11.55 (p.353)

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**Chapter 11: Rotational Dynamics and Static Equilibrium**

Ch11-7 Conservation of Angular Momentum If Fext = 0, then ptot is conserved If = 0, then Ltot is conserved P11.63 (p.354)

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**Chapter 11: Rotational Dynamics and Static Equilibrium**

Ch11-8 Rotational Work and Power W = Fx = (one dimension or fixed axis) W = K Power = W/t = /t = P11.68 (p.354)

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