Download presentation

Presentation is loading. Please wait.

Published byJaylin Croswell Modified over 2 years ago

2
Time (s)012 Mass of car & bucket (kg) Mass of falling bucket (kg) Force of falling bucket (F = m x a (earth) ) (N) Acceleration of the system ( F = m x a ) (m/s/s) Speed at the end of this second ( a = (Vf-Vo)/t ) (m/s) Distance traveled during this second ( s = ½ a t^2 ) (m) Total distance traveled (m)

3
Time (s)012 Mass of car & bucket (kg) 1.2.7.2 Mass of falling bucket (kg) Force of falling bucket (F = m x a (earth) ) (N) Acceleration of the system ( F = m x a ) (m/s/s) Speed at the end of this second ( a = (Vf-Vo)/t ) (m/s) Distance traveled during this second ( s = ½ a t^2 ) (m) Total distance traveled (m)

4
Time (s)012 Mass of car & bucket (kg) 1.2.7.2 Mass of falling bucket (kg) 1.5 0 Force of falling bucket (F = m x a (earth) ) (N) 9.81 4.9 0 Acceleration of the system ( F = m x a ) (m/s/s) Speed at the end of this second ( a = (Vf-Vo)/t ) (m/s) Distance traveled during this second ( s = ½ a t^2 ) (m) Total distance traveled (m)

5
Time (s)012 Mass of car & bucket (kg) 1.2.7.2 Mass of falling bucket (kg) 1.5 0 Force of falling bucket (F = m x a (earth) ) (N) 9.81 4.9 0 Acceleration of the system ( F = m x a ) (m/s/s) 4.45 4.08 0 Speed at the end of this second ( a = (Vf-Vo)/t ) (m/s) Distance traveled during this second ( s = ½ a t^2 ) (m) Total distance traveled (m)

6
Time (s)012 Mass of car & bucket (kg) 1.2.7.2 Mass of falling bucket (kg) 1.5 0 Force of falling bucket (F = m x a (earth) ) (N) 9.81 4.9 0 Acceleration of the system ( F = m x a ) (m/s/s) 4.45 4.08 0 Speed at the end of this second ( a = (Vf-Vo)/t ) (m/s) 4.45 8.5 8.5 Distance traveled during this second ( s = ½ a t^2 ) (m) Total distance traveled (m)

7
Time (s)012 Mass of car & bucket (kg) 1.2.7.2 Mass of falling bucket (kg) 1.5 0 Force of falling bucket (F = m x a (earth) ) (N) 9.81 4.9 0 Acceleration of the system ( F = m x a ) (m/s/s) 4.45 4.08 0 Speed at the end of this second ( a = (Vf-Vo)/t ) (m/s) 4.45 8.5 8.5 Distance traveled during this second ( s = ½ a t^2 ) (m) 2.2 6.5 8.5 Total distance traveled (m) 2.2 8.7 17.2

Similar presentations

OK

1. What distance will a train stop in if its initial velocity is 23 m/s and its acceleration is -0.25 m/s/s? 1058 m xvivfatxvivfat.

1. What distance will a train stop in if its initial velocity is 23 m/s and its acceleration is -0.25 m/s/s? 1058 m xvivfatxvivfat.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on 21st century skills common Ppt on group life insurance Ppt on any man made disaster Ppt on condition based maintenance Ppt on cross border merger and acquisition Ppt on tcp/ip protocols Ppt on domains of earth Ppt on modern periodic table Ppt on computer languages for gaming Ppt on mobile communication and bluetooth