Download presentation

Presentation is loading. Please wait.

Published byJalynn Allington Modified over 2 years ago

1
MIT and James Orlin © 2003 1 Dynamic Programming 1 –Recursion –Principle of Optimality

2
MIT and James Orlin © 2003 2 Dynamic Programming Transforms a complex optimization problem into a sequence of simpler ones. Usually begins at the end and works backwards to the beginning. Can handle a wide range of problems Relies on recursion, and on the principle of optimality Developed by Richard Bellman

3
MIT and James Orlin © 2003 3 Recursion example There are 11 people in a room. How many ways can one select exactly 6 of them? Let f(n,k) denote the number of subgroups of size k out of n people. We want f(11,6) 1234567891011 The number of subgroups containing “1” is f(10,5). The number of subgroups not containing “1” is f(10,6).

4
MIT and James Orlin © 2003 4 f(n,k) = f(n-1,k-1) + f(n-1, k) f(n,n)=f(n,0)=1 f(0,0) f(1,0) f(2,0) f(3,0) f(4,0) f(5,0) f(6,0) f(7,0) f(8,0) f(1,1) f(2,1)f(2,2) f(3,1)f(3,2)f(3,3) f(4,1)f(4,2)f(4,3)f(4,4) f(5,1)f(5,2)f(5,3)f(5,4)f(5,5) f(6,1)f(6,2)f(6,3)f(6,4)f(6,5)f(6,6) f(7,1)f(7,2)f(7,3)f(7,4)f(7,5)f(7,6)f(7,7) f(8,1)f(8,2)f(8,3)f(8,4)f(8,5)f(8,6)f(8,7)f(8,8) 1 1 1 1 1 1 1 1 1 1 21 331 4641 510 51 615201561 72135 2171 8285670562881 Reduces each problem to previously solved problem(s).

5
MIT and James Orlin © 2003 5 A warm-up example Suppose that there are 20 matches on a table, and the person who picks up the last match wins. At each alternating turn, my opponent or I can pick up 1 or 2 matches. Assuming that I go first, how can I be sure of winning the game? (Play with partner, and then discuss).

6
MIT and James Orlin © 2003 6 20 Matches Choose a person to go first. Alternate in eliminating 1 or 2 matches. The person who takes the last match wins.

7
MIT and James Orlin © 2003 7 20 Matches strategy What is the optimal strategy?

8
MIT and James Orlin © 2003 8 An Example for Dynamic Programming: 20 matches Version 2 Choose a person to go first. Alternate in eliminating 1 or 2 or 6 matches. The person who takes the last match wins.

9
MIT and James Orlin © 2003 9 20 Matches

10
MIT and James Orlin © 2003 10 Winning and losing positions (in the game in 20 matches version 2) Suppose you have k matches left. Identify whether you have a Winning strategy (assuming your opponent plays optimally) or whether you will Lose. 12345678910 WWL 11121314151617181920

11
MIT and James Orlin © 2003 11 Determining the strategy using DP n = number of matches left f(n) = W if you can force a win at n matches. f(n) = L otherwise Determine f(1), f(2), …, f(6) For n > 6, determine f(n) from previously solved problems. f(n) = W if f(n-1) = L or f(n-2) = L or f(n-6) = L; f(n) = L if f(n-1) = W and f(n-2) = W and f(n-6) = W.

12
MIT and James Orlin © 2003 12 Determining the strategy using DP n = number of matches left (n is the state/stage) f(n) = W if you can force a win at n matches. f(n) = L otherwise f(n) = optimal value function. Determine f(1), f(2), …, f(6) (Boundary conditions) For n > 6, determine f(n) using a dynamic programming recursion f(n) = W if f(n-1) = L or f(n-2) = L or f(n-6) = L; f(n) = L if f(n-1) = W and f(n-2) = W and f(n-6) = W.

13
MIT and James Orlin © 2003 13 12345678910 11121314151617181920 21222324252627282930 31323334353637383940 41424344454647484950 12345678910 11121314151617181920 21222324252627282930 31323334353637383940 41424344454647484950 Running the Recursion Who sees the pattern determining the losing hands?

14
MIT and James Orlin © 2003 14 1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950 The same table

15
MIT and James Orlin © 2003 15 Examples Suppose there are 30 matches on a table. I begin by picking up 1, 2, or 3 matches. Then my opponent must pick up 1, 2, or 3 matches. We continue in this fashion until the last match is picked up. The player who picks up the last match is the loser. How can I (the first player) be sure of winning the game?

16
MIT and James Orlin © 2003 16 Examples Suppose there are 40 matches on a table. I begin by picking up 1, 2, 3, or 4 matches. Then my opponent must pick up 1, 2, 3, or 4 matches. We continue until the last match is picked up. The player who picks up the last match is the loser. Can I be sure of victory? If so, how?

17
MIT and James Orlin © 2003 17 Examples I have a 9-oz cup and a 4-oz cup. My mother has ordered me to bring home exactly 6 oz of milk. How can I accomplish this goal? We have 21 coins and are told that one is heavier than any of the other coins. How many weighings on a balance will it take to find the heaviest coin?

18
MIT and James Orlin © 2003 18 Finding the shortest path from node s to all other nodes in an acyclic network. s

19
MIT and James Orlin © 2003 19 Shortest Paths Find the shortest path from node 1 to each other node, in order. –What is the shortest path from node 1 to node 2, 3, 4, … ? –Determine these values one at a time. Shortest path

20
MIT and James Orlin © 2003 20 Finding the shortest path to node t from all other nodes in an acyclic network. t

21
MIT and James Orlin © 2003 21 Shortest Paths Find the shortest path to node 19 from each node in order. –What is the shortest path to node 19 from node 18, 17, 16….? –Determine these values one at a time. Shortest path

22
MIT and James Orlin © 2003 22 Dynamic Programming in General Break up a complex decision problem into a sequence of smaller decision subproblems. Stages: one solves decision problems one “stage” at a time. Stages often can be thought of as “time” in most instances. –Not every DP has stages –The previous shortest path problem has 7 stages –The match problem does not have stages.

23
MIT and James Orlin © 2003 23 Dynamic Programming in General States: The smaller decision subproblems are often expressed in a very compact manner. The description of the smaller subproblems is often referred to as the state. –match problem: “state” is the number of matches left –shortest path problem: “state” is the node At each state-stage, there are one or more decisions. The DP recursion determines the best decision. –match problem: how many matches to remove –shortest path example: which arc to choose

24
MIT and James Orlin © 2003 24 Principle of Optimality Any optimal policy has the property that whatever the current state and decision, the remaining decisions must constitute an optimal policy with regard to the state resulting from the current decision. (As formulated by Richard Bellman.) Whatever node j is selected, the remaining path from j to the end is the shortest path starting at j.

25
MIT and James Orlin © 2003 25 Forwards recursion Start with stage 1 and determine values for larger stages using recursion In the match examples, determine f(n) from f(k) for k < n.

26
MIT and James Orlin © 2003 26 Backwards Recursion Boundary conditions: optimum values for states at the last stage Determine optimum values for other stages using backwards recursion

27
MIT and James Orlin © 2003 27 Summary for Dynamic Programming Recursion Principle of optimality states and stages and decisions useful in a wide range of situations –games –shortest paths –more will be presented in next lecture.

Similar presentations

Presentation is loading. Please wait....

OK

Analysis of Algorithms

Analysis of Algorithms

© 2018 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on seven segment display diagram Ppt on nuclear micro batteries Ppt on sectors of indian economy download Ppt on duty roster spreadsheet Ppt on standing order template Ppt on chromosomes and genes video Ppt on blood stain pattern analysis expiration pattern Ppt on needle stick injury Ppt on email etiquettes presentation high school Ppt on cement concrete flooring