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Flickr, Ken Lund Welcome to: Zipline Mathematics Focusing on: – STEM – Algebra I – Inquiry – Modeling

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Flickr, Ken Lund Real-life Problem Holly Mountain needs more revenue – Money from skiing in winter is not enough

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Flickr, Ken Lund Board of Directors They have approved the use of the slopes for zipline use in the summer

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Flickr, Ken Lund Problem – Part 1 Insurance company says the usual zipline equipment not safe enough

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Flickr, Ken Lund Problem Part 2 You must create a zipline carrier that: – attaches to the existing zipline – travels within a certain range of speed – provides a smooth, consistent descent – is safe – is easily used

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Flickr, Ken Lund Modeling Since we are not at the resort: – Fishing line represents zipline – Ping-pong ball represents a person – Minimal speed is 20 inches per second – Maximum speed is 60 inches per second

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Flickr, Ken Lund How can we calculate speed? What formulas could be helpful?

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Flickr, Ken Lund distance = rate x time

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Flickr, Ken Lund Low Cost is Good Materials UsedCost for MaterialsMoney Spent Kabob Stick$10 $ Duct Tape$12/inch $ Masking Tape$6/inch $ Straw$13 $ 3 by 5 card$18 $ Paper Clip$25 $ Washer$10 $ Total Spent $

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Flickr, Ken Lund Engineering Design Process What is it?

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Flickr, Ken Lund Engineering Design Process http://cromwellvalleyes.bcps.org/event_highlights/steam

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Flickr, Ken Lund Identify a problem Research and Brainstorm Several Solutions Design and Test Evaluate and Communicate Redesign Engineering Design Process

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Flickr, Ken Lund A successful design… meets the design criteria. Is NOT too expensive.

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Flickr, Ken Lund Criteria Reminder You must create a zipline carrier that: – attaches to the existing zipline. – travels at least 20 inches/second. – travels no faster than 60 inches/second. – provides a smooth, consistent descent. – does not allow harm to ping-pong ball. – is easily used.

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Review Homework page 203-206 # 1-12. 1) + = 6000 x 6000+x $ % 14 10 12 6000(14) + 10x = 12(6000 + x) 84000 +10 x = 72000 + 12x 12000 = 2x x = 6000 $6000.

Review Homework page 203-206 # 1-12. 1) + = 6000 x 6000+x $ % 14 10 12 6000(14) + 10x = 12(6000 + x) 84000 +10 x = 72000 + 12x 12000 = 2x x = 6000 $6000.

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