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Example 4 Evaluating Algebraic Expressions Evaluate the expression for the given value (s) of the variable (s). 3x3x+ 4,4, x=7 a. –s= 2,2,b. p=410s 3 3p.

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Presentation on theme: "Example 4 Evaluating Algebraic Expressions Evaluate the expression for the given value (s) of the variable (s). 3x3x+ 4,4, x=7 a. –s= 2,2,b. p=410s 3 3p."— Presentation transcript:

1 Example 4 Evaluating Algebraic Expressions Evaluate the expression for the given value (s) of the variable (s). 3x3x+ 4,4, x=7 a. –s= 2,2,b. p=410s 3 3p 2,3p 2, SOLUTION 3x3x+4=3 a. () 7 +4 Substitute 7 for x. =21+4 Multiply. =25 Add.

2 Example 4 Evaluating Algebraic Expressions – b. 10s 3 3p 23p 2 =10 () 3) 3 2 – Substitute 2 for s and 4 for p. 3 () 2) 2 4 Evaluate powers. =10 () 8 –3 ()16 =80 Multiply. –48 =32 Subtract.

3 Example 5 Evaluating a Real-Life Expression A river carries a stone over a waterfall. The stone hits the water 5 seconds later. To find the height of the waterfall, use the expression 16t 2, which gives the distance in feet that a dropped object falls in t seconds. WATERFALL SOLUTION 16t 2 =16 () 2) 2 5 Substitute 5 for t. Evaluate the power. 16 ()25 = =400 Multiply.

4 Example 5 Evaluating a Real-Life Expression ANSWER The waterfall is about 400 feet high.

5 Guided Practice Evaluate the expression for the given value (s) of the variable (s). for Examples 4 and r4r+ 6,6, r=5 18. ( ),), 5–y3 y=8 19. n2n2 + q3,q3, n= 1,1, q=2 ANSWER 26 ANSWER 9 9

6 Guided Practice 20. WHAT IF? for Examples 4 and 5 ANSWER 64 ft In Example 5, suppose the stone hits the water after 2 seconds. Find the height of the waterfall.


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