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WATERFALL BY: MISAKI A., TERESA C., EMILY L., SELINA M.

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Length of the ride: 1.2 KM Time of ride: 1.42 min Height of drop: 12.19 m INFO

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What is the velocity of the log before it it’s the water? PART A

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What is the deceleration after the log ride hits the water? (it takes 4.5m to slow down to 3m/s) PART B

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What is the force of the water? (m-212kg) PART C

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Find the average velocity of the ride. (m/s) PART D 1

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Find the average speed of the ride. (m/s) PART D 2

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PE1+KE1=PE2+KE2 mg(12.19)=1/2mv2 12.19(9.8)=1/2v2 238.924=v2 15.5m/s=v Velocity is 15.5 m/s ANSWER A

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V2=v2+2ad (3.0)2=(15.5)2+2a(4.5) 9=240.25+9a a=-25.694m/s2 a=-26m/s2 ANSWER B

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F=ma F=(212)(25.694) F=5447.2 N Fwater= 545oN ANSWER C

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V=d/t d = 0 because it starts and finish at the same point T=1.42 min -> 201 s V=0/201 Average velocity = 0m/s ANSWER D1

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V=d/t d= 1.2km -> 12.00m T= 1.42min -> 201s V=1200/201 Average speed = 6.0 m/s ANSWER Q D2

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