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Unit Two: Algebra Minds On Problem 1Problem 2Problem 3 Determine the width of the rectangle An antique plate is valued at $55. Its value increases each year by $1.20. Develop a formula for its value and then calculate its value after 15 years. Determine a simplified formula for the perimeter A = 20x 2 + 8x l = 4x 5x + 2 6x - 5

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Unit Two: Algebra Learning Goals: I can solve word problems involving polynomials Lesson 7: Polynomial Application Problems – Part 2

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Bob’s Sporting Goods Company rents out skis and snowboards to instructors at ski resorts. Below is a table showing the number of skis and snowboards that are in the warehouse, their original value, and depreciation. Equipment Number in Warehouse Original Value for Each Yearly Drop in Value Skis 200$600$50 Snowboards 300$800$60 Unit Two: Algebra Lesson 7: Polynomial Application Problems – Part 2

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Bob has hired you as his accountant. Please answer the following: 1.Determine an equation that represents the value, “V” of one pair of skis after “y” years of use. Equipment Number in Warehouse Original Value for Each Yearly Drop in Value Skis 200$600$50 Snowboards 300$800$60 Unit Two: Algebra Lesson 7: Polynomial Application Problems – Part 2

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2. Determine an expression that represents the value, “V” of one snowboard after “y” years of use. Equipment Number in Warehouse Original Value for Each Yearly Drop in Value Skis 200$600$50 Snowboards 300$800$60 Unit Two: Algebra Lesson 7: Polynomial Application Problems – Part 2

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3. Determine a simplified expression that represents the combined value, “CV” of all the equipment after “y” years of use. Unit Two: Algebra Equipment Number in Warehouse Original Value for Each Yearly Drop in Value Skis 200$600$50 Snowboards 300$800$60

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4. What is the combined value, “CV” of all the equipment after 2 years? CV = $360,000 - $28,000y Unit Two: Algebra Lesson 7: Polynomial Application Problems – Part 2

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5. When will all the equipment be worthless? Unit Two: Algebra Lesson 6: Polynomial Application Problems – Part 2 CV = $360,000 - $28,000y

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6. Bob’s Sporting Goods Company also has a few aluminum toboggans in its warehouse. The toboggans have a value given by the expression: V = 175 – 15y where “y” represents the years of use. How much did the company pay for each brand new toboggan and how much is it depreciating by? Explain. Unit Two: Algebra Lesson 6: Polynomial Application Problems – Part 2

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7. Which piece of equipment is depreciating at a faster rate? How do you know? Unit Two: Algebra Lesson 6: Polynomial Application Problems – Part 2 EquipmentEquation # of years until worthless (CV = 0) Depreciation as a portion of total Skis Snowboard Toboggan

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Practice Pg. 271 #1, 5 Pg. 265 #16acd, 17 Handout: #1, 2 Unit Two: Algebra Lesson 7: Polynomial Application Problems – Part 2

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Solve each equation. 1. 3b + 8 = –102. –12 = –3x – 9 3. – + 7 = 144. –x – 13 = 35 c4c4 –6 1 –28 –48 Math on the Mind.

Solve each equation. 1. 3b + 8 = –102. –12 = –3x – 9 3. – + 7 = 144. –x – 13 = 35 c4c4 –6 1 –28 –48 Math on the Mind.

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