Download presentation

Presentation is loading. Please wait.

Published byJoy joyce Stansbury Modified over 2 years ago

1
Numerical Analysis 1 EE, NCKU Tien-Hao Chang (Darby Chang)

2
In the previous slide Fixed point iteration scheme –what is a fixed point? –iteration function –convergence Newton’s method –tangent line approximation –convergence Secant method 2

3
In this slide Accelerating convergence –linearly convergent –Newton’s method on a root of multiplicity >1 –(exercises) Proceed to systems of equations –linear algebra review –pivoting strategies 3

4
2.6 4 Accelerating Convergence

5
Accelerating convergence Having spent so much time discussing convergence –is it possible to accelerate the convergence? How to speed up the convergence of a linearly convergent sequence? How to restore quadratic convergence to Newton’s method? –on a root of multiplicity > 1 5

6
Accelerating convergence Linearly convergence Thus far, the only truly linearly convergent sequence –false position –fixed point iteration Bisection method is not according to the definition 6

7
7

8
Aitken’s Δ 2 -method Substituting Eq. (2) into Eq. (1) Substituting Eq. (4) into Eq. (3) The above formulation should be a better approximation to p than p n 8

9
9

10
Aitken’s Δ 2 -method Accelerated? 10 which implies super- linearly convergence later answer

11
11

12
Any Questions? 12 About Aitken’s Δ 2 -method

13
Accelerating convergence Anything to further enhance? 13

14
14 Why not use p-head instead of p ?

15
Steffensen’s method 15

16
16 Restoring quadratic convergence to Newton’s method

17
17

18
18

19
Any Questions? 19

20
Two disadvantages Both the first and the second derivatives of f are needed Each iteration requires one more function evaluations 20 answer

21
Any Questions? 21 Chapter 2 Rootfinding (2.7 is skipped)

22
Exercise 22 2010/4/21 9:00am Email to darby@ee.ncku.edu.tw or hand over in class. You may arbitrarily pick one problem among the first three, which means this exercise contains only five problems.darby@ee.ncku.edu.tw

23
23

24
24

25
25

26
26

27
27 (Programming)

28
Chapter 3 28 Systems of Equations

29
Systems of Equations Definition 29

30
3.0 30 Linear Algebra Review (vectors and matrices)

31
Matrix Definitions 31

32
Any Questions? 32 m, n, m, i, j, E QUAL, S UM, S CALAR M ULTIPLICATION, P RODUCT …

33
The Inverse Matrix 33 (cannot be skipped)

34
34

35
Any questions? 35 answerquestion

36
The Determinant 36 (cannot be skipped, too)

37
37 cofactor

38
38

39
Link the concepts –All these theorems will be extremely important throughout this chapter Nonsingular matrices Determinants Solutions of linear systems of equations 39

40
40

41
41 (Hard to prove)

42
Any Questions? 42 3.0 Linear Algebra Review

43
3.1 43 Gaussian Elimination (I suppose you have already known it)

44
An application problem 44

45
I 1 -I 2 -I 3 =0 I 2 -I 4 -I 5 =0 I 3 +I 4 -I 6 =0 2I 3 +I 6 =7 I 2 +2I 5 =13 -I 2 +2I 3 -3I 4 =0 45

46
Following Gaussian elimination 46

47
Any Questions? 47 Gaussian elimination

48
Gaussian elimination Operation Counts 48

49
Operation Counts Comparison Gaussian elimination –forward elimination –back substitution Gauss-Jordan elimination Compute the inverse matrix 49

50
3.2 50 Pivoting Strategy

51
51

52
52

53
53 Compare to x 1 =1, x 2 =7, x 3 =1

54
Pivoting strategy To avoid small pivot elements A scheme for interchanging the rows (interchanging the pivot element) Partial pivoting 54

55
55 In action http://thomashawk.com/hello/209/1017/1024/Jackson%20Running.jpg

56
56

57
57 Compare to x 1 =1, x 2 =7, x 3 =1

58
Any Questions? 58

59
From the algorithm view How to implement the interchanging operation? –change implicitly Introduce a row vector r –each time a row interchange is required, we need only swap the corresponding elements of the vector –number of operations from 3n to 3 59 hint answer

60
60 In action http://thomashawk.com/hello/209/1017/1024/Jackson%20Running.jpg

61
61 Without pivoting

62
62

63
63

64
x = [1.000, -0.9985, 0.9990, -1.000] T –exact solution x = [1,-1,1,-1] T –no r x = [1.131, -0.7928, 0.8500, -0.9987] T 64

65
Scaled Partial Pivoting 65

66
Scaled partial pivoting An example 66

67
Any Questions? 67

68
Scaled partial pivoting A blind spot of partial pivoting 68 answer

69
Scaled partial pivoting 69

70
70

71
71 In action http://thomashawk.com/hello/209/1017/1024/Jackson%20Running.jpg

72
72

73
73

74
x = [1.000, -1.000, 1.000, -1.000] T –exact solution x = [1,-1,1,-1] T –no s x = [1.000, -0.9985, 0.9990, -1.000] T –no r x = [1.131, -0.7928, 0.8500, -0.9987] T 74

75
Any Questions? 75 3.2 Pivoting Strategy

Similar presentations

OK

Gaoal of Chapter 2 To develop direct or iterative methods to solve linear systems Useful Words upper/lower triangular; back/forward substitution; coefficient;

Gaoal of Chapter 2 To develop direct or iterative methods to solve linear systems Useful Words upper/lower triangular; back/forward substitution; coefficient;

© 2018 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on electricity distribution system in india Ppt on arunachal pradesh cultures Ppt on ready to serve beverages direct Ppt on waves tides and ocean currents lab Ppt on ten sikh gurus Ppt on road accidents today Ppt on index numbers formula Ppt on work and energy class 11 Ppt on wireless communication network Ppt on business etiquette in india