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Warmup KelvinCelsiusFahrenheit 150 -80 3000 Practice temperature conversions. How to do these needs to be memorized.

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Presentation on theme: "Warmup KelvinCelsiusFahrenheit 150 -80 3000 Practice temperature conversions. How to do these needs to be memorized."— Presentation transcript:

1 Warmup KelvinCelsiusFahrenheit Practice temperature conversions. How to do these needs to be memorized.

2 Warmup KelvinCelsiusFahrenheit Practice temperature conversions. How to do these needs to be memorized.

3 JANUARY 27, 2012

4 Specific Heat, Style 1 500g of water starts at 30*C. Then 8360J of energy is added. What is the new temperature?

5 Specific Heat, Style 2 What is the total energy of a 1000g lump of aluminum with a height of 100m, speed of 4m/s, and temperature of 127*C?

6 Specific Heat, Style g of water at 20*C (C=4.18 J/g *C) and 1000g of aluminum at 100*C (C=.64 J/g *C) are allowed to reach thermal equilibrium together. What will the final temperature be?

7 Specific Heat, Style 1 A certain section of asphalt (m=50kg, C=.50 J/g *K) starts at 20*C and then receives 200,000J of energy over the course of a day. Disregarding, any conduction or re-radiation of heat, what is its final temperature? Assuming 8 hours of daylight, what is the average power of the sunlight on the asphalt section?

8 Specific Heat, Style 2 A flying pig contains thermal, potential, kinetic, and chemical energy. It has a temperature of 30*C (C=3.9 J/g *K), mass of 50kg height of 1,000m, velocity of 20 m/s, and could be cooked and consumed as 5,000 Calories of bacon (mmmm). How many Joules of total energy does the flying pig contain, and in which type of energy is most of it stored?

9 Specific Heat, Style 3 250g of Coke at 25*C and 50g of those plastic freezer cube things (C=5.0 J/g *K) at -10*C are put in a glass. What is the thermal equilibrium they achieved?

10 Gravity Take-Home Answers 1)B 2)D 3)C 4)B 5)A 6)A 7)C 8)D 9)C 10)D 11) D 12) C 13) A 14) A 15) A 16) C 17) C 18) F = G m 1 m 2 / r 2 F = 6.67 * * 61.5 * 70 / F = 1.8*10 -7 N 19) F = G m 1 m 2 / r 2, F = m*g g = G m 1 / r * *1 / 1 2 = 6.67* *2 / r 2 r = √2 20) 6.7*10 -4 = 6.67* * m 1 m 2 /3 2, m 1 = m 2 9*10 7 = m 2 m = 9487 kg


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