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SI Final Exam Review: A review on the application of the material

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a. 7.5 x 10 -14 b. 3.0 x 10 -13 c. 4.5 x 10 -5 d. 2.2 x 10 -5 e. 1.5 x 10 -13

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a. 7.5 x 10 -14 b. 3.0 x 10 -13 c. 4.5 x 10 -5 d. 2.2 x 10 -5 e. 1.5 x 10 -13

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A.2 B.4 C.6 D.8 E.10

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p is power

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A.2 B.4 C.6 D.8 E.10

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A.30 B.33 C.36 D.39 E.42

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A.30 B.33 C.36 D.39 E.42

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A.29 B.39 C.49 D.59 E.69

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A.29 B.39 C.49 D.59 E.69

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Sunlight reflects off the smooth surface of a swimming pool, for what angle of reflection is the reflected light completely polarized? A.49.2 B.60.3 C.56.2 D.53.1 E.57.8

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Sunlight reflects off the smooth surface of a swimming pool, for what angle of reflection is the reflected light completely polarized? A.49.2 B.60.3 C.56.2 D.53.1 E.57.8

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A.0 B.I o /128 C.I o /32 D.I o /8 E.I o /2

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Where I 0 is un polarized

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A.0 B.I o /128 C.I o /32 D.I o /8 E.I o /2

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Its mirror convention time time!

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Direction of Positive (s,f)

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Step 1: Direction of Positive (s,f) Step 2: Draw Eye

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Step 1: Direction of Positive (s,f) Step 2: Draw Eye Step 3: Draw arrow at eye. This is the positive s’ direction

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A.1 B.1.2 C.2.5 D.6 E.9.4 A. real, erect, and smaller than the object. B. real, inverted, and larger than the object. C. real, erect, and larger than the object. D. virtual, inverted, and larger than the object. E. virtual, erect, and smaller than the object.

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A.1 B.1.2 C.2.5 D.6 E.9.4 A. real, erect, and smaller than the object. B. real, inverted, and larger than the object. C. real, erect, and larger than the object. D. virtual, inverted, and larger than the object. E. virtual, erect, and smaller than the object.

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Step 1: Direction of Positive (s,f)

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Step 2: sphere on the right has f1, left has f2

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Step 1: Direction of Positive (s,f) Step 2: sphere on the right has f1, left has f2

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Step 1: Direction of Positive (s,f) Step 2: sphere on the right has f1, left has f2 Step 3: Draw Eye

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Step 1: Direction of Positive (s,f) Step 2: sphere on the right has f1, left has f2 Step 3: Draw arrow at eye. This is the positive s’ direction Step 3: Draw Eye

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A.1 B.3 C.5 D.7 E.9 What is the direction? A.Positive B.Negative

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A.1 B.3 C.5 D.7 E.9 What is the direction? A.Positive B.Negative

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spherical refracting surface

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A) 1.5 cm B) 3.0 cm C) 4.5 cm D) 6.0 cm E) 7.0 cm

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A) 1.5 cm B) 3.0 cm C) 4.5 cm D) 6.0 cm E) 7.0 cm

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A.148 nm B.250 nm C.295 nm D.325 nm E.425 nm

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A Physics Poem “Low to Hi Phase shift Pi” “ Hi to low, Phase shift? NO” n air = 1 n oil = 1.1 n water = 1.3

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A.148 nm B.250 nm C.295 nm D.325 nm E.425 nm

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A.2mm B.1mm C..09mm D..5mm E..2mm

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A.2mm B.1mm C..09mm D..5mm E..2mm

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Special Equations (Used very, very rarely)

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A. 30 B. 40 C. 50 D. 60 E. 70

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A. 30 B. 40 C. 50 D. 60 E. 70

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A. 1 × 10 19 B. 2 × 10 18 C. 3 × 10 17 D. 4 × 10 16 E. 5 × 10 15

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A. 1 × 10 19 B. 2 × 10 18 C. 3 × 10 17 D. 4 × 10 16 E. 5 × 10 15

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Definitions

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Which one of the following five statements is false? A. The de Broglie wavelength of a free proton decreases if the kinetic energy of the proton increases. B. The Pauli Exclusion Principle states that the hydrogen atom nucleus can contain no neutrons. C. The Heisenberg Uncertainty Principle arises from the properties of a matter wave pulse. D. The Bohr theory of the hydrogen atom and the quantum mechanical wave theory of the hydrogenatom give the same values for the allowed energies of the electron in the atom. E. The magnitude of the intrinsic spin angular momentum of the electron has one possible value.

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? ? ? ? ? ?

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Which one of the following five statements is false? A. The de Broglie wavelength of a free proton decreases if the kinetic energy of the proton increases. B. The Pauli Exclusion Principle states that the hydrogen atom nucleus can contain no neutrons. C. The Heisenberg Uncertainty Principle arises from the properties of a matter wave pulse. D. The Bohr theory of the hydrogen atom and the quantum mechanical wave theory of the hydrogenatom give the same values for the allowed energies of the electron in the atom. E. The magnitude of the intrinsic spin angular momentum of the electron has one possible value.

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WTFWTF H A T H E YSICS?YSICS? WTPH

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Actually these are mostly constants! (Not that hard)

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Any Questions??? Tips: -Look at the book (to clear anything up) -I posted my source for Pre 2010 exams, review that for practice (About 60% are good questions) -Practice -Be confident (don’t second guess yourself) -Review my worksheets (again posted) -Review other class materials

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Electron Configuration Nucleus is (+) because it is composed of neutrons (0) and protons (+). Atoms = neutral, therefore #p (+) = #e- (-). Electrons determine.

Electron Configuration Nucleus is (+) because it is composed of neutrons (0) and protons (+). Atoms = neutral, therefore #p (+) = #e- (-). Electrons determine.

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