Download presentation

Presentation is loading. Please wait.

Published byIvy Draine Modified over 3 years ago

1
8.6 Problem Solving: Compound Interests

2
43210 In addition to level 3, students make connections to other content areas and/or contextual situations outside of math. Students will construct, compare, and interpret linear and exponential function models and solve problems in context with each model. - Compare properties of 2 functions in different ways (algebraically, graphically, numerically in tables, verbal descriptions) - Describe whether a contextual situation has a linear pattern of change or an exponential pattern of change. Write an equation to model it. - Prove that linear functions change at the same rate over time. - Prove that exponential functions change by equal factors over time. - Describe growth or decay situations. - Use properties of exponents to simplify expressions. Students will construct, compare, and interpret linear function models and solve problems in context with the model. - Describe a situation where one quantity changes at a constant rate per unit interval as compared to another. Students will have partial success at a 2 or 3, with help. Even with help, the student is not successful at the learning goal. Focus 8 Learning Goal – (HS.N-RN.A.1 & 2, HS.A-SSE.B.3, HS.A-CED.A.2, HS.F-IF.B.4, HS.F- IF.C.8 & 9, and HS.F-LE.A.1) = Students will construct, compare and interpret linear and exponential function models and solve problems in context with each model.

3
Simple interest: I=prt I = interest p = principal: amount you start with r = rate of interest t= time in years

4
If you invest $3,000 at 5% for one year, how much will you make for the year? I = prt = 3000 0.05 1 = 150 You made $150 for the year.

5
A = p(1+r) t A = balancep = principal r = ratet = time in years Compound interest formula:

6
Find the total amount in your account if you start with $750 at 7.5% interest compounded annually for 2.5 years. A = p(1+r) t = 750(1+0.075) 2.5 = 750(1.075) 2.5 (use a calculator here!) = $898.63

7
How much should you invest at 7% compounded annually to have $200 after 5 years? A = p(1+r) t (Plug in what you know.) 200 = p(1.07) 5 ( get p alone, then use a calculator.) 200 = p (1.07) 5 142.60= p

8
If you put $100 in the bank at 4% interest compounded annually and leave it until you are 60, how much money will you have? A = p(1+r)t = 100(1.04) 46 (This assumes you are currently 14) = 607.48

9
What about a mutual fund that pays 10% interest compounded annually? A = p(1+r)t = 100(1.10) 46 = 8017.95

Similar presentations

Presentation is loading. Please wait....

OK

6.5 Graphing Linear Inequalities in Two Variables

6.5 Graphing Linear Inequalities in Two Variables

© 2018 SlidePlayer.com Inc.

All rights reserved.

To ensure the functioning of the site, we use **cookies**. We share information about your activities on the site with our partners and Google partners: social networks and companies engaged in advertising and web analytics. For more information, see the Privacy Policy and Google Privacy & Terms.
Your consent to our cookies if you continue to use this website.

Ads by Google

Ppt on history of computer generations Animated ppt on magnetism and electromagnetism Ppt on service oriented architecture tutorial Ppt on dry cell and wet cell phone Ppt on event handling in javascript what is the syntax Laser video display ppt on tv Ppt on eid Ppt on biotechnology in agriculture Ppt on economic order quantity calculator Ppt on engineering college life