Download presentation

Presentation is loading. Please wait.

Published byKurt Nevils Modified over 3 years ago

1
5.4D: More with Integral Functions Today, we will construct integral functions, and find values of integral functions given an initial condition.

2
HW: p. 303, #57 Let

4
Find the numerical value of each integral function with the given condition:

5
500 = initial amount in tons G(s) is amount arriving in tons per hour and 100 is amount processed in tons per hour. G(s)-100 is the rate at which the amount of gravel is changing in tons per hour. The integral is essentially (tons/hour)(hours) = tons of gravel, and therefore gives the net/accumulated amount of unprocessed gravel at the plant at any time t (which gets added to the 500 tons already present)

6
tA(t) 00 4.92348635.376 8525.551 The maximum amount of unprocessed gravel during the given workday is 635.376 tons.

7
Assignment: 5.4D: p. 302: 21,23,59,61,67,68,74

Similar presentations

OK

To solve an equation with variables on both sides, use inverse operations to "collect" variable terms on one side of the equation. Helpful Hint Equations.

To solve an equation with variables on both sides, use inverse operations to "collect" variable terms on one side of the equation. Helpful Hint Equations.

© 2018 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on non agricultural activities definition Ppt on water our lifeline adoption Types of window display ppt on tv Seven segment led display ppt on tv Ppt on statistics in maths what does median Download ppt on transportation in human beings what is the largest Download ppt on biodegradable and nonbiodegradable waste Ppt on blood stain pattern analysis terminology Ppt on tcp/ip protocol diagram Ppt on object-oriented programming php