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5.4D: More with Integral Functions Today, we will construct integral functions, and find values of integral functions given an initial condition.

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HW: p. 303, #57 Let

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Find the numerical value of each integral function with the given condition:

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500 = initial amount in tons G(s) is amount arriving in tons per hour and 100 is amount processed in tons per hour. G(s)-100 is the rate at which the amount of gravel is changing in tons per hour. The integral is essentially (tons/hour)(hours) = tons of gravel, and therefore gives the net/accumulated amount of unprocessed gravel at the plant at any time t (which gets added to the 500 tons already present)

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tA(t) 00 4.92348635.376 8525.551 The maximum amount of unprocessed gravel during the given workday is 635.376 tons.

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Assignment: 5.4D: p. 302: 21,23,59,61,67,68,74

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