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ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 1 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Bruce Mayer, PE Licensed.

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Presentation on theme: "ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 1 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Bruce Mayer, PE Licensed."— Presentation transcript:

1 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 1 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Bruce Mayer, PE Licensed Electrical & Mechanical Engineer Engineering 36 Chp 5: FBDs 2D/3D Systems

2 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 2 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Free Body Diagrams (FBDs)  A free-body diagram is a sketch of an object of interest with all the surrounding objects stripped away to reveal all of the forces acting on the body  The purpose of a free-body force diagram is to assist with determination of the Net Force and/or Moment acting on a body Space Diagram Free Body Diagram

3 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 3 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Constructing a free-body diagram  Select an object or group of objects to focus on as the "body“: i.e., the system.  Sketch the body by itself, "free" of its surroundings  Draw only those forces/moments that are acting directly on the body. Include both the magnitude and the direction of these forces.  Do not include any forces that the body exerts on it surroundings, they do NOT act ON the body. However, there is always an equal reaction force acting on the body.  For a compound body (e.g. Trusses, Machines) you do NOT need to include any INTERNAL forces acting between the body's SUBPARTS these internal forces come in action-reaction pairs which cancel out each other because of Newton's Third Law.  Choose a coordinate system and sketch it on the free-body diagram.  Often choose one of the axes to be parallel one or more forces it can sometimes simplify the equations to be solved.

4 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 4 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Structural Supports  NonMoving Structures are typically Connected to Some Sort of Supporting Base  The connection between the Structure and Base are usually Called “Structural Supports”  The Force and/or moments exerted on the Structure Base are usually called “Structural Reactions” (RCNs for Short)

5 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 5 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Structural Supports  A Support that Prevents Linear Motion (sliding, translating) of the structure then exerts a Force on the structure  A Support that Prevents Rotating Motion (twisting, turning) of the structure then exerts a Couple Moment on the structure

6 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 6 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Recall SLIDING & FREE Vectors  Forces are SLIDING Vectors; They can applied at ANY-POINT on the Vector Line of Action (LoA)  COUPLE-Moments are FREE Vectors; They can be applied at ANY Point, On or Off the Body

7 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 7 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 2D Support ReActions  Cable can only Generate TENSION  WeightLess Link is 2-Force Element

8 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 8 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 2D Support ReActions  Note that in BOTH these Cases the Support ReAction is NORMAL (Perpendicular) to the Supporting Surface  RCN can only PUSH, and NOT PULL

9 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 9 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 2D Support ReActions  Note that in BOTH these Cases the Support ReAction is NORMAL (Perpendicular) to the Supporting Surface  RCN can PUSH or PULL

10 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 10 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 2D Support ReActions  Only the Supports (9) & (10) Can Generate a Couple-Moment ReAction

11 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 11 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Center of Gravity  If the Weight of the Rigid Body is Not Negligible, then the Entire Weight of the Body can be concentrated at a Single Point Called the Center of Gravity (CG) Many times the CG location is Given –Can Calculate using Centroid Methods which will be covered later

12 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 12 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 2D Free-Body Diagram  First Steps for Static Rigid-Body Equilibrium Analysis Identification of All Forces & Moments Acting on the Body Formulation of the Free-Body Diagram  Free Body Diagram Construction Process See next slide

13 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 13 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 2D Free-Body Diagram cont 1.Select the extent of the free-body and detach it from the ground and other bodies 2.Indicate for external loads: Point of application Magnitude & Direction Of External Forces –Including The Body Weight. 3.Indicate point of application and ASSUMED direction of UNKNOWN applied forces

14 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 14 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 2D Free-Body Diagram cont.2 The Unknown Forces Typically Include REACTIONS through which the GROUND and OTHER BODIES oppose the possible motion of the rigid body 4.Include All dimensions Needed to Calculate the Moments of the Forces

15 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 15 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example: Truss Structure  Consider Rocker & Pin Supported Truss  Analyze Loading Four External Force Loads as shown Truss Weight, W RCN at Pt-A by Rocker –Expect NORMAL to support Pad RCN at Pt-B by Pin –Expect  in plane of Truss  Arbitrarily Directed  Draw the FBD for this Structure

16 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 16 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example: Truss – Draw FBD W RARA R By R Bx RBRB  This Dwg is, in fact, a Full Free Body Diagram φ

17 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 17 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 3D Support ReActions  Same as 2D ReActions of this Type

18 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 18 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 3D Support ReActions  Ball-n-Socket is the 3D analog to the 2D Smooth Pin or Hinge

19 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 19 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 3D Support ReActions  This configuration is Commonly Known as a “Pillow Block Bearing”.  Type of support is (obviously) designed to allow the shaft to SPIN FREELY on its AXIS

20 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 20 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 3D Support ReActions  The Sq-Shaft Bearing System does NOT Allow the shaft to spin completely freely, Thus the M y

21 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 21 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 3D Support ReActions  These supports are (obviously) designed to allow the Free Spin on the Pin Axis

22 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 22 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics 3D Support ReActions  This Type of support is commonly Known as a CANTILEVER. Generates the Maximum Amount of Unknowns for 3D systems

23 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 23 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics ROUGH SURFACE ReActions  Friction on a Rough Surface will Generate RCNs Parallel to the Supporting Surface 2D 3D

24 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 24 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example: Hinge & Rough-Surf  Given Bar supported by Hinge at Pt-A and rests on the Rough x*y*z* Surface at Pt-B  Analyze Rcn at Pt-A. By 5.2-(9) the Single Axially Constrained Hinge will Provide Lateral (y & z) and Axial (x) Support Resist twisting about the y and z axes

25 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 25 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example: Hinge & Rough-Surf  PUSH (not PULL) Normal to the Surface In this case the y* direction is normal to the supporting plane  Resist Sliding in any direction WITHIN the supporting plane  Analyze Rcn at Pt-B. Support Leg on a rough surface will

26 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 26 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example: cont. M Az F Az F Ax F Ay M Ay F By* F Bx* F Bz* If the Weight of the Bar is negligible, then All Forces are accounted for and this is, in fact, the FBD

27 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 27 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Symmetry City  If We’re Lucky enough to have a Plane of Symmetry for BOTH Loading and Structural GEOMETRY then we can treat real world 3D problems as 2D OtherWise we need to Operate in full 3D Can Treat as 2DMust Treat as 3D No Symmetry

28 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 28 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example: Utility Pole  Consider Leaning Utility Pole  Determine the Loads acting on the BASE of the Pole  Analyze Rcn at Base This is a FIXED support which is often call a CantiLever Cantilever supports resist both forces and moments in ALL 3 Spatial Directions

29 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 29 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example: Pole  Draw in the BASE ReActions F Az F Ay F Ax M Az M Ay  This Diagram is NOT a FBD as it does not account for these forces acting on the pole Pole Weight Cable Tension M Ax

30 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 30 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Distributed Forces/Loads  In Some Cases Forces are concentrated at Points; this is simplest case  Often times a Load cannot be identified with a single point; Instead the Load is Spread Out over a supporting surface Such Forces are Called “Distributed”  Distributed Loads are indicated with a Load Profile

31 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 31 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Distributed Force Profiles  A uniformily Dist Load Has the same action at every point on it’s region of application. It’s profile is “Flat”  NonUniform Loads are also common They may be kinked, curved, or arbitrary

32 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 32 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Distributed-Force Equivalent  In Chp4 we discussed how to Replace a Distributed-Load with an Equivalent Point-Load placed at a Specific Location  Units for Distributed Forces 2D → Force per Length (lb/ft, lb/in N/m) 3D → Force Per Area (Pa, PSI, PSF)

33 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 33 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example: Hydraulic Cylinder  The Hydraulic Cylinder Pumps Fluid in & out of the Cylinder Reservoir as Shown at Right  Draw The loads on the Piston Assy  Game Plan: Isolate Piston Assy as Free Body CareFully Account for all Pt-Force and PRESSURES acting on the Piston Assy

34 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 34 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example – Cont. 9.81kN  Load-1 = 100 kg (220lb, 9.81kN) CounterWt  Load-2 = Weight of the Piston Rod WRWR  Load-3 = Weight of the Piston WPWP  Load-4 = Lateral Restraining Forces Exerted by the Cylinder Wall on the O-Ring F Or

35 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 35 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example – Cont. 9.81kN  Load-5 = The Air Pressure on Top of the Piston  Load-6 = The Hydraulic Fluid Pressure on the Bottom of the Cylinder WRWR WPWP F Or P air P fluid

36 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 36 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example – Cont. 9.81kN  We can SIMPLIFY the analysis by making assessments about the relative significance of the loads The Weight of the Rod and Piston are likely negligible compared to the Counter Weight WRWR WPWP F Or P air P fluid

37 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 37 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example – Cont. 9.81kN  Additional Symplifications The SideWall Forces on the O-Ring must cancel if the Cylinder is Balanced F Or P air P fluid The AIR pressure is negligible compared to the FLUID pressure

38 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 38 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Example – Cont. 9.81kN  Thus in the NonMoving Simplified System the Fluid Pressure balances the Counter Weight.  Mathematically P fluid

39 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 39 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics WhiteBoard Work None Today; Did by PowerPoint

40 ENGR-36_Lec-10_FBDs_2D_3D_Systems.pptx 40 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Bruce Mayer, PE Registered Electrical & Mechanical Engineer Engineering 36 Appendix


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