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**Pressure and Volume (Boyle’s Law)**

Chapter 6 Gases 6.3 Pressure and Volume (Boyle’s Law)

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**Boyle’s Law Boyle’s Law states that**

the pressure of a gas is inversely related to its volume when T and n are constant. if volume decreases, the pressure increases.

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**PV Constant in Boyle’s Law**

In Boyle’s Law, the product P x V is constant as long as T and n do not change. P1V1 = atm x L = atm L P2V2 = atm x L = atm L P3V3 = atm x L = atm L Boyle’s Law can be stated as P1V1 = P2V2 (T, n constant)

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**Solving for a Gas Law Factor**

The equation for Boyle’s Law can be rearranged to solve for any factor. P1V1 = P2V Boyle’s Law To solve for V2 , divide both sides by P2. P1V1 = P2V2 P P2 V1 x P1 = V2 P2

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**Boyles’ Law and Breathing**

During an inhalation, the lungs expand. the pressure in the lungs decreases. air flows towards the lower pressure in the lungs. Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

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**Boyles’ Law and Breathing**

During an exhalation, lung volume decreases. pressure within the lungs increases. air flows from the higher pressure in the lungs to the outside. Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

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**Calculations with Boyle’s Law**

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**Calculation with Boyle’s Law**

Freon-12, CCl2F2, is used in refrigeration systems. What is the new volume (L) of a 8.0 L sample of Freon gas initially at 550 mm Hg after its pressure is changed to 2200 mm Hg at constant T? 1. Set up a data table: Conditions 1 Conditions 2 P1 = mm Hg P = mm Hg V1 = L V2 = ?

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**Calculation with Boyle’s Law (Continued)**

2. When pressure increases, volume decreases. Solve Boyle’s Law for V2: P1V1 = P2V2 V = V1 x P1 P2 V = L x 550 mm Hg = L 2200 mm Hg pressure ratio decreases volume

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**Learning Check 1) pressure decreases 2) pressure increases**

For a cylinder containing helium gas indicate if cylinder A or cylinder B represents the new volume for the following changes (n and T are constant). 1) pressure decreases 2) pressure increases

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**Solution 1) Pressure decreases B 2) Pressure increases A**

For a cylinder containing helium gas indicate if cylinder A or cylinder B represents the new volume for the following changes (n and T are constant): 1) Pressure decreases B 2) Pressure increases A

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**Learning Check If a sample of helium gas has a volume of 120 mL**

and a pressure of 850 mm Hg, what is the new volume if the pressure is changed to 425 mm Hg ? 1) 60 mL ) 120 mL 3) 240 mL

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**Solution P1 = 850 mm Hg P2 = 425 mm Hg V1 = 120 mL V2 = ??**

V2 = V1 x P1 = mL x mm Hg = 240 mL P mm Hg Pressure ratio increases volume

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Learning Check A sample of helium gas in a balloon has a volume of 6.4 L at a pressure of 0.70 atm. At 1.40 atm (T constant), is the new volume represented by A, B, or C?

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Solution A sample of helium gas in a balloon has a volume of 6.4 L at a pressure of 0.70 atm. At a higher pressure (T constant), the new volume is represented by the smaller balloon A.

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**Learning Check A) 3.2 L B) 6.4 L C) 12.8 L**

If the sample of helium gas has a volume of 6.4 L at a pressure of 0.70 atm, what is the new volume when the pressure is increased to 1.40 atm (T constant)? A) 3.2 L B) 6.4 L C) 12.8 L

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Solution If the sample of helium gas has a volume of 6.4 L at a pressure of atm, what is the new volume when the pressure is increased to 1.40 atm (T constant)? A) 3.2 L V2 = V1 x P1 P2 V2 = 6.4 L x atm = L 1.40 atm Volume decreases when there is an increase in the pressure (temperature is constant.)

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**Learning Check 1) 200. mm Hg 2) 400. mm Hg 3) 1200 mm Hg**

A sample of oxygen gas has a volume of 12.0 L at 600. mm Hg. What is the new pressure when the volume changes to 36.0 L? (T and n constant). 1) mm Hg 2) mm Hg 3) 1200 mm Hg

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**Solution 1) 200. mm Hg Data table Conditions 1 Conditions 2**

P1 = mm Hg P2 = ??? V1 = L V2 = L P2 = P1 x V1 V2 600. mm Hg x L = mm Hg L

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7.3 Pressure and Volume (Boyle’s Law)

7.3 Pressure and Volume (Boyle’s Law)

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