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VOTING SYSTEMS Section 2.5. Introduction The rights and duties of a citizen are captured in a simple one word mantra – VOTE! In this section we discuss.

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Presentation on theme: "VOTING SYSTEMS Section 2.5. Introduction The rights and duties of a citizen are captured in a simple one word mantra – VOTE! In this section we discuss."— Presentation transcript:

1 VOTING SYSTEMS Section 2.5

2 Introduction The rights and duties of a citizen are captured in a simple one word mantra – VOTE! In this section we discuss different types of ways to count the votes. Counting the votes is the heart of democracy Is the counting fair? How well does the counting work? These are the questions of Voting Theory. Not to disappoint you but a mathematical economist by the name of Kenneth Arrow has a theorem called Arrow’s Impossibility Theorem. The Arrow Theorem states that a method for determining election results that is democratic and always fair is a mathematical impossibility. Donal Saari a Mathematican and author of Chaotic Elections! A Mathematician Looks at Voting, has said: “For a price I will serve as a consultant to your group for your next election. Tell me who you want to win and I will devise a 'democratic process' which ensures the election of your candidate.”

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5 Reading the preference schedule The total number of ballots cast are =37. We see that Kirk received 14 first place votes. Archer received 11 first place votes. Pike received 8 first place votes, and Piccard got 4 first place votes. Since James T. Kirk received the most first place votes we can declare him the winner. This is an example of using the plurality method to determine the winner of an election.

6 Majority vs. Plurality Winning an election with a majority is when a candidate receives 50%+1 first place votes or more. The plurality method says that the candidate with the most first place votes is the winner. In the preference schedule from before, we saw that there were a total of 37 votes. A candidate winning with a majority would need 19 first place votes. None of the candidates received a majority. Kirk won the election with a plurality of 14 votes. President Clinton never won a majority of the popular vote in his two elections. The only President not to do so.

7 The problems with Plurality The plurality method has many flaws and is considered a poor method for choosing a winner of an election. The Condorcet Criterion states that if there is a candidate in head-to-head comparisons is preferred by the voters over each of the other choices, then that choice should be the winner. The plurality method violates this criterion. In the previous example, 14 voters preferred Kirk, while 23 voters preferred someone other than Kirk.

8 Pairwise Comparison Method (Copeland’s Method) The method of pairwise comparison is like a round-robin tournament. Each candidate is matched head-to-head with every other candidate. If a candidate wins a head-to-head matchup, they receive 1 point. If the matchup is tied each candidate gets ½ a point.

9 How many matchups???? Who wins??? To determine the correct number of matchups, use the combination formula. We have four candidates in the election and 2 candidates in a matchup, so use 4 choose 2. Which is 6. Here are the matchups –Kirk vs. Piccard: 23 voters prefer Piccard, 14 prefer Kirk thus Piccard gets the head-to-head victory. One point for Piccard. –Kirk vs. Pike: 23 voters prefer Pike, 14 prefer Kirk, thus Pike gets the victory and the point. –Kirk vs. Archer: 23 voters prefer Archer, 14 prefer Kirk, Archer wins the matchup and gets a point. –Piccard vs. Pike: 28 voters prefer Piccard, 9 prefer Pike, Piccard gets the point. Piccard has two points. –Piccard vs. Archer: 19 voters preferred Archer, only 18 for Piccard, thus Archer gets the point and she now has two. –Pike vs. Archer: 25 voters preferred Archer, only 12 for Pike, Archer gets a point and he now has three points. Archer got 3 points, Piccard 2 points, Pike 1 point, Kirk 0 points. Jonathan Archer is your winner.

10 What’s wrong with Pairwise Comparisons Pairwise Comparison’s violate a criterion known as Independence-of-irrelevant- Alternatives. What this means is that if choice X wins an election, and one or more other choices are disqualified, then when the ballots are recounted, choice X should still win the election.

11 Borda Count Method Each voter ranks all of the candidates. If there are k candidates, each candidate receives k points for 1 st choice, k – 1 points for second choice, and so on. The candidate with the most points is declared the winner. The Borda Count method takes into account all the information from the ballot and it produces the best compromise candidate. The problem with Borda Count is that it can violate the majority criterion. That is a candidate could have the majority of the 1 st place votes but lose with the Borda Count.

12 Borda Count Example Referring to the preference schedule slide, we see that there are 4 candidates in the election. First choice receives 4 points, second choice receives 3 points, third choice receives 2 points, and fourth choice receives 1 point. Kirk received 14 first choice votes and 23 fourth choice votes for a Borda Count total of (14 x 4) + (0 x 3) + (0 x 2) + (23 x 1) = 79 points Archer received 11 first choice votes, 8 second choice votes and 18 third choice votes for a Borda Count total of (11 x 4) + (8 x 3) + (18 x 2) + (0 x 1) = = 104 points. Pike’s Borda Count is (8 x 4) + (5 x 3) + (10 x 2) + (14 x 1) = = 81 points. Piccard’s Borda Count is (4 x 4) + (24 x 3) + (9 x 2) = = 106 points. Jean-Luc Piccard wins the election in the Borda Count Method.

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14 Example 2 Continued Since there are 11 voters in the preference schedule, 6 votes are needed for a majority. Candidate Foster has received 6 votes. Under a majority rules, Foster should be declared the winner. However if Borda Count is used we see the following: –Foster gets (6 x 4) + (5 x 1) = 29 points –Winkel gets (2 x 4) + (9 x 3) = 35 points –Heerey gets (3 x 4) + (2 x 3) + (6 x 2) = 30 points –LeVarge gets (3 x 3) + (2 x 2) + (6 x 1) = 16 points Under the Borda Count rule, Winkel would be declared the winner.

15 Ranked-Choice or Instant Run-Off Method Each voter ranks all of the candidates first, second, third, etc. If a candidate receives a majority of the first choice votes, that candidate is declared the winner. If no candidate receives a majority, then the candidate that received the fewest first choice votes is eliminated. Those votes are given to the next preferred candidate. If a candidate now has a majority, that candidate is declared the winner. If no candidate has a majority, then the process continues.

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18 Instant Run-Off Example Now we see that Kirk only has 14 first choice votes and Pike has 23 first choice votes. Christopher Pike is declared the winner of this election by the instant run-off method. The problem with Instant run-off is that it violates the Monotonicity criterion. The criterion states that if choice X is the winner of an election, and in a reelection, the only changes in the ballots are changes that only favor X, then X should remain the winner.

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20 Questions 1.How many votes were cast? 2.Use the Plurality method to determine the winner. 3.What percent of the votes did the winner in number 2 receive? 4.Use instant run-off method to determine the winner. 5.What percent of the votes did the winner in number 4 receive? 6.Use Borda Count to determine the winner. 7.How many points did the winner in number 6 receive? 8.Use pairwise comparison to determine the winner. 9.How many points did the winner receive in number 8?


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