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 Name to Formula ◦ 1. Write the cation first (include charge) ◦ 2. Write the anion second (include charge) ◦ 3. “Swap and drop” the charges to determine.

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Presentation on theme: " Name to Formula ◦ 1. Write the cation first (include charge) ◦ 2. Write the anion second (include charge) ◦ 3. “Swap and drop” the charges to determine."— Presentation transcript:

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2  Name to Formula ◦ 1. Write the cation first (include charge) ◦ 2. Write the anion second (include charge) ◦ 3. “Swap and drop” the charges to determine how many of each ion are needed ◦ 4. Make sure the total charge of the compound is 0  (The final formula will NOT have + or – in it.) ◦ 5. Rewrite the formula without charges

3  Lithium oxide ◦ 1. Cation (including charge): Li + ◦ 2. Anion (including charge): O 2- ◦ 3. Swap and drop charges:  Li + O 2-  Li + 2 O 2- 1  Li 2 O There is are two lithium cations and one oxide anion. “Oxide” ends in –ide and is not found on the polyatomic ion chart. We know the charge is 2- because of where oxygen is found on the periodic table. The formula is neutral: Li: +1 x 2 = +2 charge O: -2 x 1 = -2 charge 0 total charge

4  Barium nitrate ◦ 1. Cation (including charge): Ba 2+ ◦ 2. Anion (including charge): NO 3 - ◦ 3. Swap and drop charges:  Ba 2+ NO 3 -  Ba 2+ 1 NO  Ba(NO 2 ) 2 There is one barium cation and two nitrate anions. The parentheses show that there are two nitrate ions. “Nitrate” is a polyatmic ion whose name you should have memorized. The formula is neutral: Ba: +2 x 1 = +2 charge NO 3 : -1 x 2 = -2 charge 0 total charge

5  Aluminum sulfate ◦ 1. Cation (including charge): Al 3+ ◦ 2. Anion (including charge): SO 4 2- ◦ 3. Swap and drop charges:  Al 3+ SO 4 2-  Al 3+ 2 SO  Al 2 (SO 4 ) 3 The parentheses show that there are three sulfate ions. There are two aluminum cations and three sulfate anions. “Sulfate” is a polyatmic ion whose name you should have memorized. The formula is neutral: Al: +3 x 2 = +6 charge SO 4 : -2 x 3 = -6 charge 0 total charge

6  Sodium chloride ◦ 1. Cation (including charge): Na + ◦ 2. Anion (including charge): Cl - ◦ 3. Swap and drop charges:  Na + Cl -  Na + 1 Cl - 1  NaCl There is one sodium cation and one chloride anion. “Chloride” ends in –ide and is not found on the polyatomic ion chart. We know the charge is 1- because of where chlorine is found on the periodic table. The formula is neutral: Na: +1 x 1 = +1 charge Cl: -1 x 1 = -1 charge 0 total charge

7  Aluminum oxide ◦ 1. Cation (including charge): Al 3+ ◦ 2. Anion (including charge): O 2- ◦ 3. Swap and drop charges:  Al 3+ O 2-  Al 3+ 2 O 2- 3  Al 2 O 3 There are two aluminum cations and three oxide anions. “Oxide” ends in –ide and is not found on the polyatomic ion chart. We know the charge is 2- because of where oxygen is found on the periodic table. The formula is neutral: Al: +3 x 2 = +6 charge O: -2 x 3 = -6 charge 0 total charge

8  Ammonium nitrate ◦ 1. Cation (including charge): NH 4 + ◦ 2. Anion (including charge): NO 3 - ◦ 3. Swap and drop charges:  NH 4 + NO 3 -  NH NO  NH 4 NO 3 Parentheses are not needed because there is only one of each polyatomic ion. There is one ammonium cation and one nitrate anion. “Ammonium” and “nitrate” are polyatmic ions whose names you should have memorized. The formula is neutral: NH 4 : +1 x 1 = +1 charge NO 3 : -1 x 1 = -1 charge 0 total charge

9  Calcium hydroxide ◦ 1. Cation (including charge): Ca 2+ ◦ 2. Anion (including charge): OH - ◦ 3. Swap and drop charges:  Ca 2+ OH -  Ca 2+ 1 OH - 2  Ca(OH) 2 The parentheses show that there are two hydroxide ions. There is one calcium cation and two hydroxide anions. “Hydrocide” is a polyatmic ion whose name you should have memorized. The formula is neutral: Ca: +2 x 1 = +2 charge OH: -1 x 2 = -2 charge 0 total charge

10  Barium chloride ◦ 1. Cation (including charge): Ba 2+ ◦ 2. Anion (including charge): Cl - ◦ 3. Swap and drop charges:  Ba 2+ Cl -  Ba 2+ 1 Cl - 2  BaCl 2 There is one barium cation and two chloride anions. The formula is neutral: Ba: +2 x 1 = +2 charge Cl: -1 x 2 = -2 charge 0 total charge “Chloride” ends in –ide and is not found on the polyatomic ion chart. We know the charge is 1- because of where chlorine is found on the periodic table.

11  Magnesium oxide ◦ 1. Cation (including charge): Mg 2+ ◦ 2. Anion (including charge): O 2- ◦ 3. Swap and drop charges:  Mg 2+ O 2-  Mg 2+ 2 O 2- 2  Mg 2 O 2  MgO The smallest possible ratio is 1:1, not 2:2. There is one magnesium cation and one oxide anion. The formula is neutral: Mg: +2 x 2 = +4 charge Cl: -2 x 2 = -4 charge 0 total charge “Oxide” ends in –ide and is not found on the polyatomic ion chart. We know the charge is 2- because of where oxygen is found on the periodic table.

12  Lead (II) nitride ◦ 1. Cation (including charge): Pb 2+ ◦ 2. Anion (including charge): N 3- ◦ 3. Swap and drop charges:  Pb 2+ N 3-  Pb 2+ 3 N 3- 2  Pb 3 N 2 There are three lead (II) cations and two nitride anions. The Roman numeral tells us that lead has a charge of +2. “Nitride” ends in –ide and is not found on the polyatomic ion chart. We know the charge is -3 because of where nitrogen is found on the periodic table. The formula is neutral: Pb: +2 x 3 = +6 charge N: -3 x 2 = -6 charge 0 total charge

13  Formula to Name ◦ 1. Determine the charge of the cation (+) ◦ 2. Determine the charge of the anion (-) ◦ 3. Write the name of the cation  Use element name or polyatomic cation name  Include Roman numeral if necessary  D-block  NOT Ag +, Cd 2+, or Zn 2+ ◦ 4. Write the name of the anion  -ide or from the polyatomic ion chart

14 Sr(ClO 2 ) 2  Strontium chlorite Anion charge: ClO 2 has a charge of -1. It is a polyatomic ion. There are two of them so the -1 charge balances out the 2+ charge of Sr 2+. Name: Chlorite Cation charge: Sr has a charge of 2+. We know this because it is located in Group 2 on the periodic table. Name: Strontium Strontium does NOT need a Roman numeral because it is found in the s-block. Only d-block elements and some p-block elements need Roman numerals.

15 CuCl  Copper (I) chloride Anion charge: Cl has a charge of -1. We know this because it is located in Group 17 on the periodic table. The name will end in –ide. Name: Chloride Cation charge: Cu is found in the d-block and can form more than one ion. Its charge in this compound will be +1 to balance Cl -. Name: Copper (I) Copper DOES need a Roman numeral because it is found in the d-block. The +1 charge tells us what Roman numeral to use.

16 Pb(NO 3 ) 2 Lead (II) nitrate Anion charge: NO 3 has a charge of -1. It is a polyatomic ion. There are TWO of them for a total negative charge of -2. Name: Nitrate Cation charge: Pb is found in the lower-left p-block and can form more than one ion. Its charge in this compound will be +2 to balance the two NO 3 - ions. Name: Lead (II) Lead DOES need a Roman numeral because it is found in the lower-left p-block. The +2 charge tells us what Roman numeral to use.

17 Pb(NO 3 ) 3 Lead (III) nitrate Anion charge: NO 3 has a charge of -1. It is a polyatomic ion. There are THREE of them for a total negative charge of -3. Name: Nitrate Cation charge: Pb is found in the lower-left p-block and can form more than one ion. Its charge in this compound will be +3 to balance the two NO 3 - ions. Name: Lead (III) Lead DOES need a Roman numeral because it is found in the lower-left p-block. The +3 charge tells us what Roman numeral to use.

18 KI Potassium Iodide Anion charge: I has a charge of -1. We know this because it is located in Group 17 on the periodic table. The name will end in –ide. Name: Iodide Cation charge: K has a charge of +1. We know this because it is located in Group 1 on the periodic table. Name: Potassium Potassium does NOT need a Roman numeral because it is found in the s-block. Only d-block elements and some p-block elements need Roman numerals.


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