Download presentation

Presentation is loading. Please wait.

Published byRocco Mathies Modified over 6 years ago

1
Comp 122, Spring 2004 Greedy Algorithms

2
greedy - 2 Lin / Devi Comp 122, Fall 2003 Overview Like dynamic programming, used to solve optimization problems. Problems exhibit optimal substructure (like DP). Problems also exhibit the greedy-choice property. »When we have a choice to make, make the one that looks best right now. »Make a locally optimal choice in hope of getting a globally optimal solution.

3
greedy - 3 Lin / Devi Comp 122, Fall 2003 Greedy Strategy The choice that seems best at the moment is the one we go with. »Prove that when there is a choice to make, one of the optimal choices is the greedy choice. Therefore, it’s always safe to make the greedy choice. »Show that all but one of the subproblems resulting from the greedy choice are empty.

4
greedy - 4 Lin / Devi Comp 122, Fall 2003 Activity-selection Problem Input: Set S of n activities, a 1, a 2, …, a n. »s i = start time of activity i. »f i = finish time of activity i. Output: Subset A of maximum number of compatible activities. »Two activities are compatible, if their intervals don’t overlap. Example: Activities in each line are compatible.

5
greedy - 5 Lin / Devi Comp 122, Fall 2003 Optimal Substructure Assume activities are sorted by finishing times. »f 1 f 2 … f n. Suppose an optimal solution includes activity a k. »This generates two subproblems. »Selecting from a 1, …, a k-1, activities compatible with one another, and that finish before a k starts (compatible with a k ). »Selecting from a k+1, …, a n, activities compatible with one another, and that start after a k finishes. »The solutions to the two subproblems must be optimal. Prove using the cut-and-paste approach.

6
greedy - 6 Lin / Devi Comp 122, Fall 2003 Recursive Solution Let S ij = subset of activities in S that start after a i finishes and finish before a j starts. Subproblems: Selecting maximum number of mutually compatible activities from S ij. Let c[i, j] = size of maximum-size subset of mutually compatible activities in S ij. Recursive Solution:

7
greedy - 7 Lin / Devi Comp 122, Fall 2003 Greedy-choice Property The problem also exhibits the greedy-choice property. »There is an optimal solution to the subproblem S ij, that includes the activity with the smallest finish time in set S ij. »Can be proved easily. Hence, there is an optimal solution to S that includes a 1. Therefore, make this greedy choice without solving subproblems first and evaluating them. Solve the subproblem that ensues as a result of making this greedy choice. Combine the greedy choice and the solution to the subproblem.

8
greedy - 8 Lin / Devi Comp 122, Fall 2003 Recursive Algorithm Recursive-Activity-Selector (s, f, i, j) 1.m i+1 2.while m < j and s m < f i 3. do m m+1 4.if m < j 5. then return {a m } Recursive-Activity-Selector(s, f, m, j) 6. else return Recursive-Activity-Selector (s, f, i, j) 1.m i+1 2.while m < j and s m < f i 3. do m m+1 4.if m < j 5. then return {a m } Recursive-Activity-Selector(s, f, m, j) 6. else return Initial Call: Recursive-Activity-Selector (s, f, 0, n+1) Complexity: (n) Straightforward to convert the algorithm to an iterative one. See the text.

9
greedy - 9 Lin / Devi Comp 122, Fall 2003 Typical Steps Cast the optimization problem as one in which we make a choice and are left with one subproblem to solve. Prove that there’s always an optimal solution that makes the greedy choice, so that the greedy choice is always safe. Show that greedy choice and optimal solution to subproblem optimal solution to the problem. Make the greedy choice and solve top-down. May have to preprocess input to put it into greedy order. »Example: Sorting activities by finish time.

10
greedy - 10 Lin / Devi Comp 122, Fall 2003 Elements of Greedy Algorithms Greedy-choice Property. »A globally optimal solution can be arrived at by making a locally optimal (greedy) choice. Optimal Substructure.

11
Comp 122, Spring 2004 Minimum Spanning Trees

12
greedy - 12 Lin / Devi Comp 122, Fall 2003 Minimum Spanning Trees Given: Connected, undirected, weighted graph, G Find: Minimum - weight spanning tree, T Example: bc a def 5 11 0 3 1 7 -3 2 a bc fed 5 3 1 0 Acyclic subset of edges(E) that connects all vertices of G.

13
greedy - 13 Lin / Devi Comp 122, Fall 2003 Generic Algorithm “Grows” a set A. A is subset of some MST. Edge is “safe” if it can be added to A without destroying this invariant. A := ; while A not complete tree do find a safe edge (u, v); A := A {(u, v)} od A := ; while A not complete tree do find a safe edge (u, v); A := A {(u, v)} od

14
greedy - 14 Lin / Devi Comp 122, Fall 2003 cut partitions vertices into disjoint sets, S and V – S. bca def 5 11 0 3 1 7 -3 2 this edge crosses the cut a light edge crossing cut (could be more than one) Definitions cut respects the edge set {(a, b), (b, c)} one endpoint is in S and the other is in V – S. no edge in the set crosses the cut

15
greedy - 15 Lin / Devi Comp 122, Fall 2003 Proof: Let T be a MST that includes A. Case: (u, v) in T. We’re done. Case: (u, v) not in T. We have the following: u y x v edge in A cut shows edges in T Theorem 23.1 Theorem 23.1: Let (S, V-S) be any cut that respects A, and let (u, v) be a light edge crossing (S, V-S). Then, (u, v) is safe for A. Theorem 23.1: Let (S, V-S) be any cut that respects A, and let (u, v) be a light edge crossing (S, V-S). Then, (u, v) is safe for A. (x, y) crosses cut. Let T´ = T - {(x, y)} {(u, v)}. Because (u, v) is light for cut, w(u, v) w(x, y). Thus, w(T´) = w(T) - w(x, y) + w(u, v) w(T). Hence, T´ is also a MST. So, (u, v) is safe for A.

16
greedy - 16 Lin / Devi Comp 122, Fall 2003 In general, A will consist of several connected components. Corollary Corollary: If (u, v) is a light edge connecting one CC in (V, A) to another CC in (V, A), then (u, v) is safe for A. Corollary: If (u, v) is a light edge connecting one CC in (V, A) to another CC in (V, A), then (u, v) is safe for A.

17
greedy - 17 Lin / Devi Comp 122, Fall 2003 Kruskal’s Algorithm Starts with each vertex in its own component. Repeatedly merges two components into one by choosing a light edge that connects them (i.e., a light edge crossing the cut between them). Scans the set of edges in monotonically increasing order by weight. Uses a disjoint-set data structure to determine whether an edge connects vertices in different components.

18
greedy - 18 Lin / Devi Comp 122, Fall 2003 Prim’s Algorithm Builds one tree, so A is always a tree. Starts from an arbitrary “root” r. At each step, adds a light edge crossing cut ( V A, V - V A ) to A. »V A = vertices that A is incident on.

19
greedy - 19 Lin / Devi Comp 122, Fall 2003 Prim’s Algorithm Uses a priority queue Q to find a light edge quickly. Each object in Q is a vertex in V - V A. Key of v is minimum weight of any edge ( u, v ), where u V A. Then the vertex returned by Extract-Min is v such that there exists u V A and ( u, v ) is light edge crossing ( V A, V - V A ). Key of v is if v is not adjacent to any vertex in V A.

20
greedy - 20 Lin / Devi Comp 122, Fall 2003 Q := V[G]; for each u Q do key[u] := od; key[r] := 0; [r] := NIL; while Q do u := Extract - Min(Q); for each v Adj[u] do if v Q w(u, v) < key[v] then [v] := u; key[v] := w(u, v) fi od Q := V[G]; for each u Q do key[u] := od; key[r] := 0; [r] := NIL; while Q do u := Extract - Min(Q); for each v Adj[u] do if v Q w(u, v) < key[v] then [v] := u; key[v] := w(u, v) fi od Complexity: Using binary heaps: O(E lg V). Initialization – O(V). Building initial queue – O(V). V Extract-Min’s – O(V lgV). E Decrease-Key’s – O(E lg V). Using Fibonacci heaps: O(E + V lg V). (see book) Prim’s Algorithm Note: A = {(v, [v]) : v v - {r} - Q}. decrease-key operation

21
greedy - 21 Lin / Devi Comp 122, Fall 2003 Example of Prim’s Algorithm b/ c/ a/0 d/ e/ f/ 5 11 0 3 1 7 -3 2 Q = a b c d e f 0 Not in tree

22
greedy - 22 Lin / Devi Comp 122, Fall 2003 Example of Prim’s Algorithm b/5 c/ a/0 d/11 e/ f/ 5 11 0 3 1 7 -3 2 Q = b d c e f 5 11

23
greedy - 23 Lin / Devi Comp 122, Fall 2003 Example of Prim’s Algorithm b/5 c/7 a/0 d/11e/3 f/ 5 11 0 3 1 7 -3 2 Q = e c d f 3 7 11

24
greedy - 24 Lin / Devi Comp 122, Fall 2003 Example of Prim’s Algorithm b/5 c/1 a/0 d/0 e/3 f/2 5 11 0 3 1 7 -3 2 Q = d c f 0 1 2

25
greedy - 25 Lin / Devi Comp 122, Fall 2003 Example of Prim’s Algorithm b/5 c/1 a/0 d/0e/3 f/2 5 11 0 3 1 7 -3 2 Q = c f 1 2

26
greedy - 26 Lin / Devi Comp 122, Fall 2003 Example of Prim’s Algorithm b/5c/1 a/0 d/0 e/3 f/-3 5 11 0 3 1 7 -3 2 Q = f -3

27
greedy - 27 Lin / Devi Comp 122, Fall 2003 Example of Prim’s Algorithm b/5c/1 a/0 d/0 e/3 f/-3 5 11 0 3 1 7 -3 2 Q =

28
greedy - 28 Lin / Devi Comp 122, Fall 2003 Example of Prim’s Algorithm 0 b/5c/1 a/0 d/0 e/3f/-3 5 3 1 -3

Similar presentations

© 2022 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google