Download presentation

Presentation is loading. Please wait.

Published byAnya Moorehouse Modified over 2 years ago

1
Level 4 Mathematical Similarity www.mathsrevision.com Calculating Scale Factor Similar Triangles Parallel Line Triangles Scale Factor in 2D (Area) Scale Factor 3D (Volume) Exam Questions

2
Level 4 Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015 Starter Questions Q1.Solve4sin x – 1 = 0 Q3.Factorise Q4.Find the mean and standard deviation for the data 4d 2 – 100k 2 www.mathsrevision.com Q2.Find the mini point for f(x) = (2 + x)(4 – x) 410236

3
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Learning Intention Success Criteria 1.We are learning what the term scale factor is and how it applies to shape. 1.Understand the term scale factor. www.mathsrevision.com 2.Solve problems using scale factor. Similarity

4
Conditions for similarity Two shapes are similar only when: Corresponding sides are in proportion and Corresponding angles are equal All rectangles are not similar to one another since only condition number 2 is true.

5
If two objects are similar then one is an enlargement of the other The rectangles below are similar: Find the scale factor of enlargement that maps A to B A B 8 cm 16 cm 5 cm 10 cm Not to scale! Scale factor = x2 Note that B to A would be x ½

6
Given the shapes are similar, find the values y and z ? Scale Factor applies to ANY SHAPES that are mathematically similar. 15 cm 3 cm 7 cm 2cm y z 6 cm Scale factor = ESF = 3 15 = 5 is 2 x 5 = 10 1.4 cm Scale factor = RSF = 5 1 is 6 x 0.2 = 1.2 = 0.2 yz

7
Given the shapes are similar, find the values a and b ? Scale Factor applies to ANY SHAPES that are mathematically similar. 8 cm 7.5 cm b 10 cm Scale factor = RSF = 10 4 = 0.4 is 8 x 0.4 = 3.2 Scale factor = ESF = 4 is 2 x 2.5 = 5 = 2.5 ab 4 cm 2cm a 3 cm

8
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Now try TJ 4+ Ex 20.1 Ch 20 (page 167) www.mathsrevision.com Scale Factor

9
Level 4 Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015 Starter Questions Q1.Find the roots to 1 decimal place Q2.A freezer is reduced by 20% to £200 in a sale. What was the original price. Q3.Calculate www.mathsrevision.com

10
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Learning Intention Success Criteria 1.We are learning how the scale factor applies to similar triangles. 1.Understand how the scale factor applies to similar triangles. www.mathsrevision.com 2.Solve problems using scale factor. Similar Triangles

11
Level 4 Similar Triangles www.mathsrevision.com

12
70 o 45 o 65 o 45 o These two triangles are similar since they are equiangular. 50 o 55 o 75 o 50 o These two triangles are similar since they are equiangular. If 2 triangles have 2 angles the same then they must be equiangular = 180 – 125 = 55

13
Level 4 Scale factors 8cm 12cm Enlargement Scale factor? Reduction Scale factor? 5cm 7.5cm ESF = RSF = Can you see the relationship between the two scale factors? www.mathsrevision.com 12 8 8 12 3 2 = 2 3 =

14
Level 4 9cm a Find a given ESF = 3 b 15cm By finding the RSF Find the value of b. ESF = 3 a 9 = Scale factors www.mathsrevision.com 27cm 5cm 1 3 RSF = b 15 == 5

15
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Now try TJ 4+ Ex 20.2 Ch 20 (page 169) www.mathsrevision.com Scale Factor

16
Level 4 Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015 Starter Questions Q1.A 42” TV is reduced by 10% to £540 in a sale. What was the original price. Q3.Calculate www.mathsrevision.com

17
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Learning Intention Success Criteria 1.We are learning how to use scale factor for parallel triangles. 1.Understand how the scale factor applies to parallel triangles. www.mathsrevision.com 2.Solve problems using scale factor for parallel triangles. Parallel Triangles

18
A BC D E If BC is parallel to DE, explain why triangles ABC and ADE are similar Angle BAC = angle DAE (common to both triangles) Angle ABC = angle ADE (corresponding angles between parallels) Angle ACB = angle AED (corresponding angles between parallels) A D E A D E B C B C A line drawn parallel to any side of a triangle produces 2 similar triangles. Triangles EBC and EAD are similar Triangles DBC and DAE are similar

19
A B C DE 20 cm 45 cm5 cm y The two triangles below are similar: Find the distance y. RSF = 50 5 = AD AE 10 1 x 20 y = = 2 cm 10 1 =

20
A B C D E In the diagram below BE is parallel to CD and all measurements are as shown. (a)Calculate the length CD (b)Calculate the perimeter of the Trapezium EBCD 4.8 m 6 m 4 m 4.5 m 10 m A C D 8 cm 3 cm 7.5 cm So perimeter = 3 + 8 + 4 + 4.8 = 19.8 cm

21
In a pair of similar triangles the ratio of the corresponding sides is constant, always producing the same enlargement or reduction. x Corresponding sides are in proportion ESF PQ TS = 5 8 = RT = x= x6.4= S T P Q R 5 Find the values of x given that the triangles are similar. 8 6.4 5 8 x 4 4

22
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Now try TJ 4+ Ex 20.3 Ch 20 (page 171) www.mathsrevision.com Parallel Triangles

23
Level 4 Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015 Starter Questions Q1.Find the mean and standard deviation for the data Q2.Solve the equation www.mathsrevision.com

24
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Learning Intention Success Criteria 1.We are learning how the scale factor applies to area. 1.Understand how the scale factor applies to area. www.mathsrevision.com 2.Solve area problems using scale factor. Area of Similar Shape

25
Level 4 It should be quite clear that second area is four times the first. The scaling factor in 2D (AREA) is (SF) 2. x y x y Area = 2 x 2 = 4 Area = 4 x 4 = 16 For this example we have this case SF = 2 (2) 2 = 4. www.mathsrevision.com Draw an area with sides 2 units long. Draw an area with sides 4 units long. 2 2 4 4 Area of Similar Shape

26
4cm 2cm 12cm 6cm Small Area = 4 x 2 = 8cm 2 Large Area = 12 x 6 = 72cm 2 Connection ? Another example of similar area ? Work out the area of each shape and try to link AREA and SCALE FACTOR Large Area = (3) 2 x 8 =9 x 8 = 72cm 2 Scale factor = ESF = 4 12 = 3

27
ExampleThe following two shapes are said to be similar. If the smaller shape has an area of 42cm 2. Calculate the area of the larger shape. 3cm 4cm Working ESF = So area S.F = Area of 2 nd shape = X 42 = = 74.67cm 2

28
Questions 1. 2.

29
3. 4.

30
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Now try TJ 4+ Ex 20.4 Ch 20 (page 173) www.mathsrevision.com Area Similarity

31
Level 4 Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015Thursday, 23 April 2015 Starter Questions Q1.Draw a box plot to represent the data. Q2.Find the coordinates where the line and curve meet. www.mathsrevision.com

32
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Learning Intention Success Criteria 1.We are learning how the scale factor applies to volume. 1.Understand how the scale factor applies to 3D – volume. www.mathsrevision.com 2.Solve volume problems using scale factor. Volumes of Similar Solids

33
Level 4 4 4 4 Draw a cube with sides 2 units long. Scale factor = Using our knowledge from AREA section, (SF) 2. Volume = 2 x 2 x 2 = 8 For VOLUME the scale factor is (SF) 3 = (2) 3 = 8 Volume = 4 x 4 x 4 = 64 x y z x y z Draw a cube with sides 4 units long. ESF = 2 4 = 2 2 2 2 www.mathsrevision.com Volumes of Similar Solids

34
Another example of similar volumes ? Work out the volume of each shape and try to link volume and scale factor 3cm 2cm 6cm 4cm V = 3 x 2 x 2 = 12cm 3 V = 6 x 4 x 4 = 96cm 3 Large Volume = (2) 3 x 12 = Scale factor = ESF = 3 6 = 2 Connection ? 8 x 12 =96cm 3

35
2cm 6cm Given that the two boxes are similar, calculate the volume of the large box if the small box has a volume of 15ml ESF = So volume of large box == 405 ml = 2 6 =3

36
Example ESF = So volume of large jug == 2.7 litres=

37
(a) SD : B = 4 : 3SD : M = 8 : 5 (b) RSF =900cm 2 (c) RSF =1562.5cm 3

38
ESF = So volume of large jug = = £1.35 =

39
(SF ) 3 = So surface area ratio = (SF) 2 == 4.64 SF = 2.1544 Ratio of their surface area is 1 : 4.6 (to 1 d.p.)

40
Level 4 23-Apr-15Created by Mr. Lafferty Maths Dept. Now try TJ 4+ Ex 20.5 Ch 20 (page 175) www.mathsrevision.com Volume Similarity

Similar presentations

Presentation is loading. Please wait....

OK

Similar Figures and Scale Drawings

Similar Figures and Scale Drawings

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on role of political parties in india Ppt on retail management information system Ppt on production management system Ppt on principles of object-oriented programming php Download ppt on teamviewer 9 Compress ppt online Ppt on satellite orbits Ppt on acute renal failure Ppt on power sector reforms in india Ppt on praying together