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Fig. 5.4 Centripetal Acceleration: a = v 2 /r Directed inwards, towards the center.

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A lever is used to lift a rock. A small force F 1 generates a larger force F 2 to lift the rock, but F 1 acts through a larger distance d 1 than does F 2. In other words, the work you do equals the work done on the rock. (Conservation of energy.)

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A crate is moved a distance d across a concrete floor under the influence of a constant horizontal force F. WORK = Force times Distance Can work be negative?

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The work done on an object by the net force acting on the object results in an increase in the object’s kinetic energy. What about friction?

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Important concepts 1.Work = force x distance 2.Kinetic energy KE = (1/2)mv 2 3.Total work done = change in KE 4.Potential energy from gravity PE = mgh 5.Energy is conserved: E = KE + PE = constant! (Some restrictions apply!!)

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Conservation of mechanical energy: If there are no forces doing work on a system, the total mechanical energy of the system remains constant. If W=0,E = PE + KE = constant.

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Momentum is a vector: Magnitude = mass times speed = mv Direction = same as velocity (To be more precise, this is the linear momentum.)

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If the net external force acting on a system of objects is zero, the total momentum of the system is conserved.

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We also want to know about changes in momentum. Notation:initial momentump i final momentump f change in momentum p = p f - p i

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There is a close resemblance between quantities used to describe linear motion and those used to describe rotational motion.

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Figure 8.15 Expressions for the rotational inertia of several objects, each with a uniform distribution of mass over its volume. The letter m is used to represent the total mass of the object.

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Physics of Angular Motion 1. If the total torque on an object is zero, then it does not rotate, or it rotates at a constant angular velocity.

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Physics of Angular Motion 2. The net torque on an object is proportional to its angular acceleration. The constant of proportionality is the moment of inertia. vectors

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Physics of Angular Motion 3. If the net torque on a system is zero, the total angular momentum of the system is conserved. L=I vectors

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CONCEPT Linear Motion Rotational InertiamI Second LawF=ma MomentumP=mv L=I conservationP=constant, if F=0. L=constant, if Kinetic energyKE=1/2mv 2 KE=1/

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A woman’s high heels sink into the soft ground, but the larger shoes of the much bigger man do not. Pressure = force/area

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Pascal’s Principle: Any change in the pressure of a fluid is transmitted uniformly in all directions throughout the fluid.

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In Boyle’s experiment, adding mercury to the open side of the bent tube caused a decrease in the volume of the trapped air in the closed side. P 1 V 1 = P 2 V 2 Boyle’s Law

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Archimedes’ Principle: The buoyant force acting on an object fully or partially submerged in a fluid is equal to the weight of the fluid displaced by the object.

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What is heat? It is the energy that flows from a hot object to a cooler one.

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Will adding heat to a body always raise its temperature? No, there can be a change of phase. It takes 0.49 cal to raise 1 gram of ice from -1 C to 0 C. But, it takes another 80 cal to go from ice at 0 C to water at 0 C. Similarly, it takes 540 cal to go from 1 gram of water at 100 C to one gram of steam at 100 C.

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An object can get hotter by adding heat to it doing work on it! Total energy is conserved. Heat is another form of energy.

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1. When an ice skater twirling on the point of a skate draws her arms in she ends up whirling faster. This is because -- A. rotational energy is conserved. B. angular momentum is conserved. C. linear momentum is conserved. D. a net torque acts on the skater.

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1. When an ice skater twirling on the point of a skate draws her arms in she ends up whirling faster. This is because -- B. angular momentum is conserved.

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2. Suppose water is boiled in a vessel open to the atmosphere. Compare the internal energy of 1 gram of steam at the boiling point to the internal energy of 1 gram of water at the same temperature. A. The internal energy of the water and steam are the same. B. The internal energy of the water will be higher. C. The internal energy of the steam will be higher.

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2. Suppose water is boiled in a vessel open to the atmosphere. Compare the internal energy of 1 gram of steam at the boiling point to the internal energy of 1 gram of water at the same temperature. C. The internal energy of the steam will be higher.

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3. A bullet is fired into a wall and comes to rest. Considering the bullet as the system we can say that -- A. the total mechanical energy is conserved. B. the momentum is conserved. C. both total mechanical energy and momentum are conserved. D. neither total mechanical energy nor momentum are conserved.

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3. A bullet is fired into a wall and comes to rest. Considering the bullet as the system we can say that -- D. neither total mechanical energy nor momentum are conserved.

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4. Anthea exerts a force of 500 N against a 100-kg desk which does not move. Campaspe exerts a force of 400 N against a 60-kg desk which moves 2 m in the direction of the push. Fiorinda exerts a force of 200 N against a 50-kg desk which moves 4 m in the direction of the push. The most work is done by A. Anthea. B. Campaspe. C. Fiorinda. D. Campaspe and Fiorinda, who do equal amounts of work.

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4. Anthea exerts a force of 500 N against a 100-kg desk which does not move. Campaspe exerts a force of 400 N against a 60-kg desk which moves 2 m in the direction of the push. Fiorinda exerts a force of 200 N against a 50-kg desk which moves 4 m in the direction of the push. The most work is done by D. Campaspe and Fiorinda, who do equal amounts of work.

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5. A truck of mass 4000 kg is at rest but free to roll with no resistance. If you push with a force of 500 N, the momentum at the end of 5 s of pushing will be A. zero. B. 500 N. C. 800 kg/s. D. 2500 kg m/s.

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5. A truck of mass 4000 kg is at rest but free to roll with no resistance. If you push with a force of 500 N, the momentum at the end of 5 s of pushing will be D. 2500 kg m/s.

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6. A merry-go-round is set in motion by students applying a a force of 500 N tangential to the rim of the wheel having a radius of 2.0 m. The merry-go round reaches a rotational velocity of 2.0 rad/s after 10 seconds, starting from rest. The rotational inertia of the merry-go-round is A. 1.0 x 10 5 kg m2 B. 5.0 x 10 3 kg m2 C. 5.0 x 10 4 kg m2 D. 5.0 x 10 5 kg m2 E. 1.0 x 10 4 kg m2

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6. A merry-go-round is set in motion by students applying a a force of 500 N tangential to the rim of the wheel having a radius of 2.0 m. The merry-go round reaches a rotational velocity of 2.0 rad/s after 10 seconds, starting from rest. The rotational inertia of the merry-go-round is B. 5.0 x 10 3 kg m2

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7. A hard rubber ball is thrown against a wall and rebounds with nearly the same speed that it had initially. A tomato of the same mass is thrown against the wall with the same speed, splatters and hardly rebounds. The impulse exerted by the wall on each object-- A. is larger for the tomato B. is the same for both and not zero C. is zero for both D. is larger for the ball.

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7. A hard rubber ball is thrown against a wall and rebounds with nearly the same speed that it had initially. A tomato of the same mass is thrown against the wall with the same speed, splatters and hardly rebounds. The impulse exerted by the wall on each object-- D. is larger for the ball.

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8. In using a long steel rod as a lever to move a large rock, where should the fulcrum be placed? A. Halfway between the rock and the applied force. B. Close to the rock. C. Close the point where the force is applied. D. Anywhere in between -- it makes no difference.

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8. In using a long steel rod as a lever to move a large rock, where should the fulcrum be placed? B. Close to the rock.

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9. A ball at the end of a string is started swinging as a simple pendulum. Assuming no loss in energy due to friction we can say for the ball that A. the potential energy is maximum at the center of motion. B. the potential energy is maximum where the kinetic energy is a minimum. C. the potential energy is maximum where the kinetic energy is maximum. D. the kinetic energy is maximum at each end of the motion.

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9. A ball at the end of a string is started swinging as a simple pendulum. Assuming no loss in energy due to friction we can say for the ball that B. the potential energy is maximum where the kinetic energy is a minimum.

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10. A penny, a quarter and a silver dollar lie at the bottom of a wishing well filled with water. The coin experiencing the largest downward force due to the water pressure is: A. penny B. quarter C. silver dollar D. all the same

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10. A penny, a quarter and a silver dollar lie at the bottom of a wishing well filled with water. The coin experiencing the largest downward force due to the water pressure is: C. silver dollar

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11. An ice cube of mass 100 g and at 0 C is dropped into a styrofoam cup containing 200 g of water at 25 C. The heat of fusion of ice is 80 cal/g and the specific heat capacity of water is 1.0 cal/g C. Assuming the cup doesn't exchange any heat, the final temperature of the system will be which of the following? A. -10 C B. 0 C C. +10 C D. +2.5 C E. +5.0 C

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11. An ice cube of mass 100 g and at 0 C is dropped into a styrofoam cup containing 200 g of water at 25 C. The heat of fusion of ice is 80 cal/g and the specific heat capacity of water is 1.0 cal/g C. Assuming the cup doesn't exchange any heat, the final temperature of the system will be which of the following? B. 0 C

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12. A piece of aluminum has a mass of 0.25 kg and a density of 2700 kg/m3. The buoyant force exerted on this body when completely submerged in water of density 1000 kg/m3 is approximately: A. 2.4 N B. 1.2 N C. 0.91 N D. 0.093 N E. 2.45 x 10 -3 N

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12. A piece of aluminum has a mass of 0.25 kg and a density of 2700 kg/m3. The buoyant force exerted on this body when completely submerged in water of density 1000 kg/m3 is approximately: C. 0.91 N

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13. A painter of mass 80 kg climbs 3.0 m up a ladder. The painter has gained potential energy in amount of -- A. 240 J B. 784 J C. 2352 J D. 261 J E. 1284 J

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13. A painter of mass 80 kg climbs 3.0 m up a ladder. The painter has gained potential energy in amount of -- C. 2352 J

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14. A body of rotational inertia 1.0 kg m2 is acted upon by a torque of 2.0 Nm. The angular acceleration of the body will be: A. 0.50 rad/s2 B. 0.5 rev/s2 C. 1.0 rad/s2 D. 2.0 rad/s2 E. 2.0 rev/s2

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14. A body of rotational inertia 1.0 kg m2 is acted upon by a torque of 2.0 Nm. The angular acceleration of the body will be: D. 2.0 rad/s2

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15. A box is moved 10 m across by a floor a force of 20 N acting along the direction of motion. The work done is A. 2.0 J B. 20 J C. 30 J D. 100 J E. 200 J

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15. A box is moved 10 m across by a floor a force of 20 N acting along the direction of motion. The work done is E. 200 J

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16. An object of mass 1.0 kg with a velocity of 4.0 m/s strikes head-on a second object of mass 2.0 kg at rest. After the collision the first body moves backward at 1.0 m/s and the struck body moves forward with a velocity of 2.5 m/s. In this collision -- A. momentum is conserved but kinetic energy is not B. kinetic energy is conserved but momentum is not C. momentum and kinetic energy are conserved D. neither momentum nor kinetic energy are conserved.

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16. An object of mass 1.0 kg with a velocity of 4.0 m/s strikes head-on a second object of mass 2.0 kg at rest. After the collision the first body moves backward at 1.0 m/s and the struck body moves forward with a velocity of 2.5 m/s. In this collision -- A. momentum is conserved but kinetic energy is not.

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PHYSICS 111 Rotational Momentum and Conservation of Energy.

PHYSICS 111 Rotational Momentum and Conservation of Energy.

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