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Part 1 - Recap We looked at the history of helicopters. We studied ways of overcoming reactive torque – tail rotors, co-axial rotors, tilt- rotors, tip.

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Presentation on theme: "Part 1 - Recap We looked at the history of helicopters. We studied ways of overcoming reactive torque – tail rotors, co-axial rotors, tilt- rotors, tip."— Presentation transcript:

1 Part 1 - Recap We looked at the history of helicopters. We studied ways of overcoming reactive torque – tail rotors, co-axial rotors, tilt- rotors, tip jets, NOTAR etc. We looked at a number of ways predicting helicopter performance in hover, and climb.

2 Momentum theory- Induced Velocities V V+v V+2v The excess velocity in the Far wake is twice the induced Velocity at the rotor disk. To accommodate this excess Velocity, the stream tube has to contract.

3 Induced Velocity at the Rotor Disk Now we can compute the induced velocity at the rotor disk in terms of thrust T. T=2  Av(V+v)

4 Ideal Power Consumed by the Rotor In hover, ideal power Use this during conceptual design to size rotor, select engines

5 Figure of Merit Figure of merit is defined as the ratio of ideal power for a rotor in hover obtained from momentum theory and the actual power consumed by the rotor. For most rotors, it is between 0.7 and 0.8.

6 Non-Dimensional Forms

7 Blade Element Theory R dr r dT Root Cut-out Use this during preliminary design, when You have selected airfoils, number of blades, Planform (taper), twist, solidity, etc.

8 Typical Airfoil Section

9 Closed Form Expressions

10 Average Lift Coefficient Let us assume that every section of the entire rotor is operating at an optimum lift coefficient. Let us assume the rotor is untapered. Rotor will stall if average lift coefficient exceeds 1.2, or so. Thus, in practice, C T /  is limited to 0.2 or so. Use this to select solidity  during design.

11 Combined Blade Element-Momentum Theory Equate the Thrust for the Elements from the Momentum and Blade Element Approaches Total Inflow Velocity from Combined Blade Element-Momentum Theory

12 Vortex Theory We also looked at modeling the tip vortices from the rotor using a prescribed form, and computing induced velocity v due to these vortices using Biot-Savart law.

13 We next looked at.. What happens when a helicopter vertically descends, perhaps due to a loss of engine power. The rotor may grow through four phases: –Hover –Vortex Ring State –Turbulent Wake State –Wind Mill Brake State We mentioned that the rotor is as good as a parachute with drag coefficient 1.4

14 We finally looked at.. Coning Angle of the blades Lock Number Lock Number, 

15 Recap- Part 2 We studied how to compute the induced velocity v through a rotor in forward flight.

16 We studied a simplified picture of Force Balance Flight Direction  TPP Rotor Disk, referred to As Tip Path Plane

17 Force Balance in Forward Flight Flight Direction Weight, W Vehicle Drag, D Thrust, T

18 We refined the Horizontal Force Balance V∞V∞ DFDF HMHM HTHT Total Drag= Fuselage Drag (D F ) + H-force on main rotor (H M ) + H-force on the tail rotor (H T )

19 We included fuselage lift in Vertical Force Balance LFLF GW Vertical Force = GW- Lift generated by the fuselage, L F

20 We discussed how to estimate Power Consumption in Forward Flight Induced Power, Tv Parasite Power Blade Profile Power V∞V∞ Power Total Power

21 We discussed hinge and control mechanisms

22 We discussed.. Three coordinate systems –Shaft Plane –Tip path Plane –Control Plane Blade Flapping Dynamics Equation: Natural frequency=  If a first harmonic input at the resonance frequency is imposed, The blades will respond 90 degrees later!

23 We discussed.. Sectional angle of attack This angle of attack can be achieved either by flapping or by cyclic pitch. One degree of pitch is equivalent to one degree of flapping as far as the blade is concerned.

24 We discussed.. How to compute the sectional loads. How to integrate them radially, and average them azimuthally to get total thrust, total torque, power, H- force, and Y- force.


26 We discussed.. How to trim an entire vehicle, taking into account fuselage lift and drag characteristics. We also discussed how to trim an entire vehicle, when it is in autorotative descent. Trim means all the forces and moments on the vehicle are balanced, and the power required equals power available.

27 Vehicle Performance Methods An Overview

28 Performance Engineer needs to tell How high? - Service altitude How fast?- Maximum forward speed How far?- Vehicle range How long?- Vehicle endurance

29 We will assume Engine performance data is available from engine manufacturer. –This information comprises of variation of shaft horse power and fuel consumption with altitude, forward speed, and temperature at various settings (max continuous power, max take-off power, etc.) –Estimates of installed power losses are available.

30 Installed Power losses are caused by.. Inlet duct total pressure losses due to skin friction (1 to 4%) Inlet total pressure losses due to particle separators (3 to 10%) Exhaust duct total pressure losses due to skin friction (2%), and due to infra-red suppressors (3% to 15%). Exhaust gas reingestion (1 to 4 degrees inlet temp rise) Compressor bleed (1 to 20%) Engine mounted accessories (addition 100 HP) Transmission losses

31 We also need vertical drag or download of the fuselage in hover This is done experimentally, or by modeling the fuselage as a series of bluff body segments. Segments

32 We also need corrections for Main rotor-tail rotor interference. The tail rotor is immersed in the downwash of the main rotor. The tail rotor will need to generate more thrust than estimated, because some of the thrust generated is lost by the interference effects. Empirical curves that plot this interference effect as a function of separation distance between the main and tail rotor shafts are constructed.

33 We also need models/corrections for Ground effect: This reduces the inflow through the rotor, and has the beneficial effect of reducing the torque needed. Fuselage plus hub Parasite Drag coefficient (or equivalent flat plate area, f) as a function of fuselage angle of attack. Miscellaneous drag due to antennae, Pitot probes, hinges, latches, steps, etc. One of the major efforts in performance studies is an accurate fuselage drag estimate. The fuselage drag is expressed as equivalent flat plate area.

34 Equivalent Flat Plate Areas (Ref. Prouty) HelicopterOH64AUH-1BCH-47 Gross weight, lb2550950033000 Main rotor disc area, sq ft55015205900 f, Fuselage and nacelle, sq.ft1.5516.1 f, rotor hubs, sq.ft1.25.514.1 f, Landing Gear, sq.ft0.537.9 f, Empennage, sq ft0.10.90 f, Miscellaneous, sq ft1.75.1 Total f, sq ft519.543.2 f/A0.0090910.0128290.007322

35 Ground Effect in Hover Height above Ground/Rotor Diameter= z/D v IGE /v OGE 0.1 1.0 0.6 0.95 When operating near ground, induced Velocity decreases. Induced power Decreases. Performance increases, since Total power consumed is less. IGE: In ground effect OGE: Out of ground effect

36 Power needed for vertical climb Sum of: –Rate of change of potential energy –Main rotor power (based on Thrust equals Gross weight plus fuselage vertical drag) –Tail rotor power taking into account extra thrust needed to overcome interference –Transmission and Installation Losses This is compared against the available power, to determine the maximum GW that the vehicle can lift. When power required equals power available under zero climb rate, absolute ceiling has been reached. When there is just enough power left to climb at 100 ft/min, service ceiling is reached. These calculations are plotted as charts.

37 Example Gross Weight = 16000 lb Main rotor –R=27 ft, c=1.7 ft,  =0.082, b=4,  R=725 ft/sec Tail rotor –R=5.5 ft, c=0.8 ft,  =0.19, b=4,  R=685 ft/sec Distance between main and tail rotor= 32.5 ft Use  =1.15, Drag coefficient=0.008 Available power less losses = 3000 HP at sea- level less 10% Neglect download. Find absolute ceiling as density altitude.

38 Variation of Density with altitude Variation of Power with Altitude:

39 Assume an altitude, h. Compute density, . Do the following for main rotor: –Find main rotor area A –Find v as [T/(2  A)] 1/2 Note T= Vehicle weight in lbf.+ download –Insert supplied values of , C d0, W to find main rotor P. –Divide this power by angular velocity  to get main rotor torque. –Divide this by the distance between the two rotor shafts to get tail rotor thrust. Now that the tail rotor thrust is known, find tail rotor power in the same way as the main rotor. Add main rotor and tail rotor powers. Compare with available power. Increase altitude, until required power = available power.

40 h,ft20006000700080009000100001100012000 rho0.0022420.0019880.0019280.0018690.0018120.0017560.0017020.001649 A, Main rotor2290.221 A, Tail rotor95.03318 v, Main rotor39.4723741.9201642.5669443.228543.9052844.5977645.3064146.03174 sigma,main0.082 sigma,tail0.17  R, main 725  R, tail 685 Pmainlbf.Ft/sec886738.6913587.4921198929180.2937540.6946286.2955424.3964962.5 Q,main33023.3734023.2534306.6834603.9534915.33524135581.3235936.54 T,tail, lbf1016.1041046.8691055.591064.7371074.3171084.3391094.811105.74 v,tail48.8318752.6393253.6736654.7434855.8501256.9949858.1795159.40526 P,tail lbf.ft/sec68702.8273694.4375166.6876737.1478410.5380191.8782086.584100.15 P,required1737.1661795.0581811.5721828.9411847.1841866.3241886.3831907.387 P,avail2569.0812277.8152209.122142.0222076.4942012.511950.0461889.076 R/C, ft/min1715.823995.6857819.9425645.7298472.9515301.5098131.3049-37.7654

41 Hover Ceiling with Take-Off Power Gross Weight Hover Ceiling Standard Day 95 deg F

42 Rate of Climb Altitude, ft R/C, ft/min Standard Day 95 deg F

43 Rate of Climb Gross Weight R/C, ft/min Standard Day 95 deg F

44 Power needed in Hover Gross Weight Engine HP Low Altitude High Altitude

45 Forward Flight Performance Power required is the sum of –Induced power of the main rotor,  Tv –Profile power of the main rotor –Tail rotor induced power and profile power –Fuselage parasite drag times forward speed

46 Power Requirements Forward Speed Power Low altitude High altitude Intermediate altitude Onset of stall Severe Stall

47 Maximum Speed Select GW, atmospheric density, density ratio=  /  at sea-level Use engine charts to find total power available at sea level Divide power by density ratio to find excess power needed at higher altitudes. Match power required to (Power available at sea level + Excess Power needed at high altitudes), to get a first estimate for forward flight. If compressibility effects are present, correct sectional drag coefficient to include wave drag. Iterate on the maximum speed.

48 Maximum Speed Maximum speed in ft/sec or knots Altitude GW ~10,000 lb Take-off Power Continuous Power Take-off Power GW ~ 24,000 lb 180 knots 120 knots

49 Equivalent Lift to Drag Ratio It is at times of interest to compare a rotor with that of a fixed wing. This comparison is done in terms of L/D of the rotor. Fuselage effects are excluded in this comparisons. L is the vertical component of rotor thrust D = Main rotor power/Forward Speed – Fuselage Drag

50 Equivalent Rotor L/D Forward Speed L/D 10 160 knots

51 Specific Range Distance traveled per unit fuel. Similar to miles per gallon on automobiles. Generally expressed as nautical miles traveled per pound of fuel. If one knows the power required by the helicopter as a function of forward speed, and the fuel consumption of the engine as a function of horse power, we can compute fuel flow rate at any given forward speed. For multiple engines, divide power required by the number of engines to obtain power required per engine.

52 Graphical Determination of Maximum Specific Range for a given GW Relative Forward Speed including head or tail wind, knots Fuel Flow Rate lb/hr Best speed for maximum specific range Best SR=1/slope

53 Range of the Aircraft Range is found by numerical integration of the curve below, Generated by computing the best SR for various gross weights. Gross Weight 99% of Best SR Landing Take off

54 Payload Range Provides an indication of the helicopter for carrying useful loads. This information can be extracted from the range calculations described previously. Plotted as Range vs. Payload, for various payload conditions, for a fixed maximum take-off weight. As payload increases, the amount of fuel that can be carried decreases, and the range decreases.

55 Payload Range Range, Nautical Miles Payload, lb GW=28000 lb (auxiliary tanks) 20,000 lb 1600 10,000 lb 400

56 Endurance In some military missions and search and rescue operations, loiter is more important than range. Endurance is defined as the hours of loiter per pound of fuel. Loiter is done at the forward speed where power consumption is minimum.

57 Power Consumption at a given GW Forward Speed Power HP Best speed for Loiter Power loiter

58 Specific Endurance Specific endurance is defined as 1 / (fuel consumption in lb/hr) under loiter conditions. Once we know the power consumption at loiter speed from the previous chart, we can use engine performance data to find fuel consumption in lb/hr ar this power. The inverse of this is SE.

59 Total Endurance Gross Weight SE

60 Rate of Climb Power Required Power Forward Speed Power Available Maximum Forward Speed

61 Absolute Flight Ceiling: (Power required=Power Available) Service Ceiling: 100ft/min climb possible Gross Weight Altitude Absolute Ceiling Service ceiling

62 Helicopter Performance Special Performance Problems

63 Turns and Pull-Ups Autorotation Maximum Acceleration Maximum Deceleration

64 Load Factor in Steady Turn T CF W Radius of Turn, R Power needed to perform a turn is analyzed in the same way as steady level flight. The gross weight is multiplied by n.

65 Turn while losing altitude and speed In some cases, the engine can not supply the power needed to perform a steady level turn at a constant altitude. The pilot will lose vehicle velocity, and altitude. In other words, some of the vehicle kinetic energy and potential energy are expended to perform the turn. In that case, the average velocity may be used to compute the load factor n and the thrust/power needed. From the energy required to perform the turn, subtract off the energy extracted from the change in the vehicle kinetic energy during the turn, and subtract off the energy extracted by a change in the vehicle potential energy. The rest is the energy that must be supplied by the engine. Divide the energy by time spent on the turn to get power needed.

66 Load Factor in Pull-Up Maneuvers R W+CF T V Power is computed as in Steady level flight.

67 Nap-of-the-Earth Flight W T+CF R

68 Autorotation In the case of power failure, the RPM rapidly decays. How fast, how much? The vehicle supplies power to the rotor by descending rapidly. How fast? The vehicle continues to move forward. How far?

69 Inertia of the Entire System

70 Time Available

71 Variation in Angular Velocity following Power Failure A high J and high  0 needed to keep rotor spinning at a high enough speed.

72 Rotor Speed Decay following Power Failure Time  0 1 t KE = 4 sec t KE = 1 sec 0.4 3 to 4 sec

73 Descent Angle Ground Descent Angle V descent. t V Forward. t

74 Once the autorotative mode is entered…

75 Rate of Descent in Autorotation Forward SpeedRate of Descent = P/GW Best Forward Speed For minimum descent rate Best descent angle Too steep a descent Vortex ring state Encountered.. Speed for minimum Descent angle feasible

76 Zoom Manuever Ground Aircraft has high forward speed when power failure occurs. Vehicle is too low. Pilot zooms to higher altitude, trading kinetic energy for potential energy. Autorotative descent is attempted.

77 Deadman’s Curve See NASA TND-4336 Avoid! Velocity Height Avoid. High speed Impact with ground likely Power consumption Is too high. Vortex ring state possible

78 Minimum Touchdown Speed Steady Autorotative Descent Cyclic Flare: Cyclic pitch is increased to Increase lift, tilt rotor Aft, slow down descent rate. Vehicle pitches up. Collective Flare Increase collective. Bring nose down. Touch down as slowly as possible

79 Autorotative Index Thumb Rule: For safe autorotative landing employing flare, the autorotative index must be higher than 60 for single engine helicopters, and higher than 25 for twin- engine aircraft (assuming only one engine Is likely to fail).

80 Maximum Acceleration in Level Flight We first find the highest fuselage equivalent flat plate area, f max at which steady level flight is possible. This is done by assuming various values of f, and computing power needed in forward flight using methods described earlier. f is increased to its maximum value f max until power needed=power available. Compute maximum thrust= maximum drag=1/2  f max V 2 Compute actual thrust needed1/2  f max V 2 The maximum acceleration= (Maximum thrust-Actual Thrust)/m, where m is the mass of the aircraft.

81 Maximum Deceleration When the vehicle decelerates, the pilot tilts the rotor disk aft, so that thrust is pointing backwards, and vehicle slows down. If deceleration occurs too quickly, autorotation may occur, and the rotor RPM may increase too much, and structural limits may be exceeded. To avoid this, only a 10% to 20% overspeeding of the blade RPM is permitted. Compute the H force, tip path plane angle, T, fuselage drag fq, etc. at this higher permitted RPM, for autorotative condiitons. Compute the maximum permissible rearward directed force = -T  TPP +H+f q Maximum deceleration is this force divided by helicopter mass.

82 Airfoils for Rotor Blades

83 Requirements High maximum static and dynamic lift coefficients to allow flight at high speeds or at high maneuver loads. A high drag divergence number to allow flight at high advance ratios without prohibitive power requirements or noise. Low drag coefficient at moderate lift coefficients and Mach numbers to minimize profile power. Low pitching moments at moderate lift coefficients. Enough thickness for structural strength.

84 C lmax limits high speed forward flight Forward Speed Power Low altitude High altitude Intermediate altitude Onset of stall Severe Stall

85 Lift Characteristics Alpha ClCl Static Dynamic Stall Shape depends on Many factors. Causes vibrations, Due to the large Changes to lift. 1.2 1.6

86 Pitching Moment Characteristics Cm Nose up is Positive Static, moment stall Dynamic Stall High nose-down pitching moment May stress the pitch links too much And cause fatigue. Alpha

87 Trailing Edge Tabs can reduce Pitching Moments High Pressure Low Pressure

88 Drag Characteristics Alpha CdCd Dynamic Stall Laminar Drag Bucket

89 Drag Divergence at a Fixed Alpha or C l M Drag rise due to formation of shock waves on the Advancing side, near the tip. MDD: Mach number at which drag rises at the rate of 0.1 per unit Mach number. Curve slope=0.1 Drag Divergence Mach No, M DD

90 M tip < 0.9

91 Rotorcraft Noise, M Tip > 0.9 High-Speed-Impulsive noise

92 Drag Rise is avoided by Thinner airfoils, twist, and sweep. UH-60A Black Hawk

93 Factors to consider in the Preliminary Design of the Rotor

94 Requirements Payload Range or Endurance Hover ceiling Vertical Climb Maximum speed Maximum Maneuver load factor

95 Disk Loading, Gross Weight/A Advantages of High Disk Loading: –Compact size –Low empty weight –Low hub drag in forward flight Advantages of Low Disk Loading: –Low induced velocities –Low autorotative rate of descent –Low power requirements in hover.

96 Tip Speed If it is too high, shocks will form, shock noise will rise, power consumption will go up. If it is too low, there will be inadequate storage of energy when autorotative descent is necessary. If it is too low, rotor may stall sooner.

97 Constraints on Tip Speed Forward Speed Tip speed 800 ft/sec 200 knots Noise Wave drag, high power Stall Stored energy 400 ft/sec

98 Solidity Advantages of high solidity –Allows hover at high altitude and temperature. –Permits high forward speed without stall on the retreating side. –Permits maneuvers at high load factors. Disadvantages: –Increased profile power consumption –Increased weight –Increased cost of ownership

99 Number of Blades Advantage of fewer blades –Low rotor weight, cost –Ease of folding and storing –Low vulnerability to combat damage Disadvantages of fewer blades –High rotor induced vibrations –Distinctive noise

100 Concluding Remarks During the first three days, we have looked at engineering methods for predicting –Hover and vertical climb characteristics –Forward flight characteristics –Rotorcraft Performance During the next two days, we will look at representative CFD techniques for a more accurate modeling of the hover and forward flight loads.

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