2Limiting Reactant A limiting reactant in a chemical reaction is the substance thatIs used up first.Stops the reaction.Limits the amount of product that can form.
3Reacting Amounts In a table setting, there is 1 plate, 1 fork, 1 knife, and1 spoon.How many table settings arepossible from 5 plates, 6 forks,4 spoons, and 7 knives?What is the limiting item?
4Reacting Amounts Four table settings can be made. Initially Use Left overplatesforksspoonsknivesThe limiting item is the spoon.
5Example of Everyday Limiting Reactant How many peanut butter sandwiches could be made from 8 slices bread and 1 jar of peanut butter?With 8 slices of bread, only 4 sandwiches could be made. The bread is the limiting item.
6Example of Everyday Limiting Reactant How many peanut butter sandwiches could be made from 8 slices bread and 1 tablespoon of peanut butter?With 1 tablespoon of peanut butter, only 1 sandwich could be made. The peanut butter is the limiting item.
7Limiting Reactants When 4.00 mol H2 is mixed with 2.00 mol Cl2,how many moles of HCl can form?H2(g) Cl(g) 2HCl (g)4.00 mol mol ??? molCalculate the moles of product from each reactant, H2 and Cl2.The limiting reactant is the one that produces the smaller amount of product.
9Limiting Reactants Using Moles HCl from H24.00 mol H2 x 2 mol HCl = mol HCl1 mol H (not possible)HCl from Cl22.00 mol Cl2 x 2 mol HCl = mol HCl1 mol Cl (smaller number)The limiting reactant is Cl2 because it is used up first. Thus Cl2 produces the smaller number of moles of HCl.
11Limiting Reactants Using Mass If 4.80 mol Ca mixed with 2.00 mol N2, which is thelimiting reactant? 3Ca(s) + N2(g) Ca3N2(s)Moles of Ca3H2 from Ca4.80 mol Ca x 1 mol Ca3N2 = 1.60 mol Ca3N mol Ca (Ca used up)Moles of Ca3H2 from N22.00 mol N2 x 1 mol Ca3N2 = mol Ca3N21 mol N (not possible)All Ca is used up when 1.60 mol Ca3N2 forms. Thus, Ca is the limiting reactant.
12Limiting Reactants Using Mass Calculate the mass of water produced when8.00 g H2 and 24.0 g O2 react?2H2(g) + O2(g) H2O(l)
13Limiting Reactants Using Mass Calculate the grams of H2 for each reactant.H2:8.00 g H2 x 1 mol H2 x 2 mol H2O x g H2O2.016 g H mol H mol H2O= 71.5 g H2O (not possible)O2:24.0 g O2 x 1 mol O2 x 2 mol H2O x g H2O32.00 g O mol O mol H2O= 27.0 g H2O (smaller)O2 is the limiting reactant.