# CE 541 Electrochemistry.

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CE 541 Electrochemistry

It is needed in Environmental Engineering to understand:
Electrochemistry is the relationship between Chemical Phenomena and Electrical Phenomena It is needed in Environmental Engineering to understand: Corrosion Electrochemical oxidation of wastes Analytical procedures Automatic monitoring of waste streams Oxidation-reduction reactions

Current Flow in Solution
Current can flow through: Solution of electrolyte Metallic conductors Characteristics of current flow through a metal: Chemical properties of metal are not changed Current is carried by electrons Increase in temperature increases resistance

Characteristics of current flow through a solution:
Chemical change occurs in solution Current is carried by ions Increase in temperature decreases resistance Resistance is normally greater than that with metals

E = IR Conductivity of Solution
"Is its ability to carry an electrical current" Conductivity can be measured by a conductivity meter and it is affected by: Number of ions Type of ions E = IR Where: E = electromotive force (volts) I = current (amperes) R = resistance (ohms)

And Where l = length of conductor A = cross-sectional area of conductor  = specific resistance of conductor (ohm-cm) k = specific conductance (1 / ohm-cm) or siemens (S) Specific conductance is conductance afforded by 1 cm3 of an electrolyte solution

Specific Conductance of a Solution = C / R
Conductivity cells are calibrated by determining the resistance of a standard solution (Rs) and the cell constant (C) can be found. C = ksRs In such cases N KCl is used in calibrating conductivity cells. For N KCl: ks = S =  C So, Specific Conductance of a Solution = C / R R needs to be determined

Equivalent Conductance ()
Where N = normality of the solution k = specific conductance or, and are equivalent ionic conductance of cations and anions, respectively

Table 3-3 shows equivalent ionic conductance @ 25 C in S-cm3/equivalent.
Only ions can carry current. Un-ionized species of weak acids or bases will not carry current. Also uncharged soluble organics (ethanol and glucose) can not carry current. Study Example page 80

What is the approximate specific conductance at 25 C of a solution containing 100 mg/l of CaCl2 and 75 mg/l of Na2SO4

Current and Chemical Change
Chemical change depends on: Nature of solution (composition) Nature of electrodes Magnitude of electromotive force imposed

Applying a voltage of 1.3 v H2 evolves at Cathode Cl2 evolves at Anode
HCl H+ e- Cathode (-) Cl- Anode (+) Platinum Electrodes Applying a voltage of 1.3 v H2 evolves at Cathode Cl2 evolves at Anode

To bring about 1 equivalent of chemical change at an electrode:
An Avogadro No of electrons must flow through the external circuit This quantity of electrons is called the faraday (F) The rate of flow of electrons gives the current (I) in amperes 1 F is equivalent to an ampere of current flowing for seconds An ampere is defined as a Coulomb per second 1 F = Coulomb Study Example page 78

What weight of silver will pass into solution from a silver anode by the passage of 0.02 A of current through the solution for 24 hours?

Electrochemical Cell two electrodes will be connected by metallic conductor electrons will flow chemical change begins electromotive force (emf) will be generated by the cell this emf is a measure of the driving force of the chemical reaction occurring in the solution the driving force represents the chemical potential or free energy of the reaction

Electrical Energy = EIt
Based on that, a relationship between electrical potential and chemical free energy can be found: Electrical Energy = EIt E = emf in volts I = current in amperes t = time in seconds Electrical energy is expressed in Volt-Coulomb or Joule Electrical energy required to produce one mole of chemical change = zEF Where z = number of electron-equivalent per mole F = faraday or coulombs per equivalent

If reaction proceeds (E is +ve), then:
where G is the free energy -zEF is the electrical energy

aA + bB  cC + dD Consider the following reaction: Substituting in:
we get:

The value of R in electrical units is:
R = J / K-mol At 25 C and converting ln to log

If an electrochemical cell reaches the state of equilibrium, then:
The emf can be found in Tables (Table 3-4) just like free-energy and enthalpy. The values in the table are for a reaction written for 1 mole of e- change, such as: If an electrochemical cell reaches the state of equilibrium, then: no current can flow emf is zero

In this case: since or log K = 16.9zE Study Examples page 85

Estimate the solubility-product constant for Mg(OH)2(s) at 25  C from standard electrode potential?

Chemical Kinetics then, the rate of reaction could be:
Chemical kinetics deal with speed of reactions. If then, the rate of reaction could be: first – order reaction (exponent 1) kCa second – order reaction (exponent 2) kCa2 kCaCb third – order reaction (exponent 3) kCa3 kCa2Cb kCaCbCc Ca, Cb, and Cc = concentrations of A, B, and C, respectively k = rate constant

The reaction rates are required in:
These are simple reaction rates, but in reality there are more complex equations. The unit of k depends on the reaction order and units of concentration of A, B, and C. The reaction rates are required in: Microbial growth Aeration Disinfection Radioactive decay

Zero-Order Reactions They are independent of concentration
Most of biological growth occur in linear relationship over a range of concentrations of substance (C).

First-Order Reactions
The rate is directly proportional to the concentration if we are dealing with a decay or decomposition reaction, then the rate can be expressed as Unit of k is (1/time) and the –ve sign indicates the loss of material with time.

Integrating the above equation:
Converting to log10

k = - slope of line [t versus ln(C/C0)]
k = -slope [t versus log10(C/C0)] Half-life (t1/2) In this case, t = t1/2 and C = (1/2)C0 Then Applications of 1st order reactions in Environmental Engineering: Dissolution of gases in water Removal of gases from water Rate of death of microorganisms Decomposition of organic matters (BOD5 test) Study Example page 89

The radioactive nuclide P32 has a half-life of 14. 3 days
The radioactive nuclide P32 has a half-life of 14.3 days. How long would a waste containing 10 mg/l of this nuclide have to be stored in order to reduce the concentration to 0.3 mg/l?

Second-Order Reactions
The rate of reaction is proportional to the square of the concentration of one of the reactants or to the product of concentrations of two different reactants.

Ca and Cb are concentrations of A and B, respectively
Ca and Cb are concentrations of A and B, respectively. Integrating (1) and (2), we obtain:

Consecutive Reactions
If rates of reactions are 1st order, then:

Integrating between t = 0 to t = t

Examples of consecutive reactions in Environmental Engineering

Total enzyme concentration in the system = E = [Ef] + [EcS]
Enzyme Reactions Are used to describe the rate of biological waste treatment. The relationship between Substrate (S) and the rate of utilization per unit mass of enzyme or bacteria (V/E) Michaelis – Menton Relationship Ef = free enzyme S = substrate EcS = enzyme-substrate complex Total enzyme concentration in the system = E = [Ef] + [EcS]

The rate of formation of enzyme-substrate complex is:
The rate of complex formation  rate of overall reaction. Therefore, d[EcS] / dt can be considered as ZERO when overall reaction rate is required to be determined. So:

Rate of product formation V = k[EcS]
The rate of product formation = overall rate of reaction Rate of product formation V = k[EcS]

Study Example page 95 Then Where
k is the maximum rate Ks is the substrate concentration at arte = (1/2)k Ks is called the "half velocity" constant V/E  k'S when S<< Ks (1st order with respect to S) V/E  k when S >> Ks (zero order with respect to S) Study Example page 95

Temperature Dependence of Reaction Rates
"rates increase with increase in temperature" Rate doubles for each 10 C rise. Using Arrehenius equation: Where T = temperature,  K R = universal gas constant Ea = constant

Integrating k2 and k1 are rate constants at T2 and T1. In environmental engineering processes, the range of temperature is small. So T2T1 can be assumed constant.

Therefore

Adsorption "sorption is the concentration or movement of contaminants from one place to another" "adsorption involves partitioning of contaminants from one phase to another" "adsorption is the process by which ions or molecules present in one phase tend to condense and concentrate on the surface of another phase"

Adsorption Physical Chemical Ion exchange Weak multi-layers
free moving reversible Chemical Strong mono-layer no movement non-reversible in most cases Ion exchange electrical attraction smaller particles have stronger attraction trivalent have stronger attraction than monovalent ions

Activated Carbon 1 gram has surface area of 1000 m2 Pore size ranges between 10 to 1000 A Adsorption of gas increases wit the increase I pressure Adsorption depends on: Nature of materials Concentration Temperature

Freundlich Isotherm Freundlich found that:
Where q = mass of contaminant per unit weight of the adsorbent C = concentration of solute after adsorption K and n = constants (they should be evaluated for each soluble and temperature) Freundlich isotherm can be expressed as:

Langmuir Isotherm Langmuir isotherm is also used to describe adsorption of single layer: qm = maximum adsorption that can take place in grams of adsorbate per gram of adsorbent a = constant

BET Isotherm A third isotherm is BET (Brunauer, Emmett, and Teller) which can be used to describe multi-layer adsorption Assumptions Multi-layers of adsorbent accumulate at the surface of adsorbent Each layer can be described by Langmuir isotherm Cs = saturation concentration for the adsorbate in solution

If C > Cs then the solute precipitates or condenses from solution as solid or liquid and concentrates on the surface BET equation can be put in this form: If we have data, then we have to find the best isotherm that can be used to describe the data (get straight line)

Study Examples Page 104