Presentation on theme: "Agonist and Antagonist Relationship"— Presentation transcript:
1 Agonist and Antagonist Relationship Agonist – is a muscle described as being primarily responsible for a specific joint movement while contractingAntagonist – is a muscle that counteracts or opposes the contraction of another muscleSimply, these are relative terms describing “opposites”
2 If an agonist muscle is considered a concentric contractor for a movement then the antagonist muscle is the eccentric contractor for the same movement.Generally, concentric and eccentric contractions do not occur at the same time for a given movement.
3 What determines which one is working is the purpose of movement, acceleration (speeding-up) or deceleration (slowing-down).Examples
4 Steps to determine contraction type Identify the joint movementIdentify the agonist (concentric contractor) and antagonist (eccentric contractor) for the joint movementDetermine if the movement is speeding-up (accelerating) or slowing-down (decelerating)If speeding-up then agonist working concentricallyIf slowing-down then antagonist working eccentrically
5 Elbow and Radioulnar Joint Movements elbow - flexion and extensionRadioulnar (forearm) - pronation and supination
6 Biceps Brachii* O: Long Head – supraglenoid tubercle above the superior lip of glenoid fossa Short Head – coracoid process and upper lip of glenoid fossa I: Tuberosity of radius and bicipital aponeurosis A: Flexion of elbow, supination of forearm (radioulnar), weak flexion of shoulder, and weak abduction of shoulder
7 Brachialis O: Distal ½ anterior shaft of humerus I: Coronoid process of ulna A: True flexion of the elbow
8 Brachioradialis O: Distal 2/3 of lateral condyloid (supracondyloid) ridge of humerus I: Lateral surface distal end of radius at the styloid process A: Flexion of elbow, pronation from supinated position to neutral (thumb up), supination from pronated position to neutral
9 Triceps brachii O: Long head – infraglenoid tubercle below inferior lip of glenoid fossa of scapula Lateral head – upper ½ posterior surface of humerus Medial head – distal 2/3 of posterior surface of humerus I: Olecranon process of ulna A: All heads: extension of elbow Long head: extension, adduction, and horizontal abduction of shoulder
10 Anconeus O: Posterior surface of lateral condyle of humerus I: Posterior surface of olecranon process and proximal ¼ of ulna A: extension of elbow
11 Pronator teres O: Distal part of medial condyloid ridge of humerus and medial side of proximal ulna I: Middle third of lateral surface of radius A: Pronation of forearm (radioulnar) and weak flexion of elbow
12 Pronator quadratus O: Distal fourth anterior side of ulna I: Distal fourth anterior side of radius A: Pronation of forearm
13 Supinator O: Lateral epicondyle of humerus and neighboring posterior part of ulna I: Lateral surface of proximal radius just below the head A: Supination of forearm
14 Ligaments of the ElbowRadial collateral ligament – provides lateral stability of the elbow; resists lateral displacement of elbowUlnar collateral ligament – provides medial stability of the elbow; resists medial displacement of elbowAnnular ligament – stabilizes the head of radius to the ulna and allows smooth articulation with the ulna
19 Introduction to Linear Kinetics Linear Kinetics – the study of linear forces associated with motion (ex. force, momentum, inertia).Linear Kinematics – the study of linear motion.Force = mass x accelerationForce → Acceleration → Velocity → Displacement
20 Vector – is a quantity that has both magnitude (how much) and direction. Used as a measuring tool for linear variables which have both magnitude and direction.Illustrated by an arrow where the tip represents direction and the length representing magnitude.
21 Muscle Force – can be measured with vectors, since muscle force pulls on bone in a linear fashion. Vector composition – is a process of determining a single vector (usually called resultant) from two or more vectors.
22 Vectors can typically be analyzed as having horizontal (x) and vertical (y) components. In this case, these perpendicular component vectors can be used to form a right triangle.A common trigonometric principle used is the Pythagorean theorem, where A2 + B2 = C2.CθAθB
23 sin θ = opposite / hypotenuse cos θ = adjacent / hypotenuse Furthermore, the following equations are derived from the Pythagorean theorem:sin θ = opposite / hypotenusecos θ = adjacent / hypotenusetan θ = opposite / adjacentCθAθB
24 Sample ProblemIf the muscle force generated by the biceps brachii is 20 lbs, how much rotary (y) force is generated by the muscle? How much dislocating (x) force?
25 Known: angle of pull = 45 degrees Muscle force (resultant) = 20 lbsUnknown: rotary (y) forcedislocating (x) force
26 Rotary force (y) calculation: sin θ = opposite / hypotenusesin 45 = rotary (y) / 20 lbssin 45 x 20 lbs = rotary (y)rotary (y) = lbs
27 Dislocating force calculation: cos θ = adjacent / hypotenusecos 45 = dislocating (x) / 20 lbscos 45 x 20 lbs = dislocating (x)dislocating = lbs