First question Marks: % 20 First question Marks: % 20.

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First question Marks: % 20 First question Marks: % 20

Choose the correct complement (complements) for the following statements by checking mark  in the box. The shortest distance on a sphere may be:  an arc of a great circle.  an arc of a meridian.  an arc of a parallel.  an arc of the equator. The shortest distance on a sphere may be:  an arc of a great circle.  an arc of a meridian.  an arc of a parallel.  an arc of the equator. Answer

Polar spherical triangle formed by:  tow meridians and one parallel.  tow meridians and an arc of great circle.  tow meridians and arc of the equator.  three meridians. Polar spherical triangle formed by:  tow meridians and one parallel.  tow meridians and an arc of great circle.  tow meridians and arc of the equator.  three meridians. Choose the correct complement (complements) for the following statements by checking mark  in the box. Answer

On an ellipsoid we can consider that:  N > M always.  N ≥ M.  M > N always.  M = N at the equator.  M = N at the pole. On an ellipsoid we can consider that:  N > M always.  N ≥ M.  M > N always.  M = N at the equator.  M = N at the pole. Choose the correct complement (complements) for the following statements by checking mark  in the box. Answer

Spherical excess is:  a negative value.  a positive value.  positive or negative value.  sometime equal to zero. Spherical excess is:  a negative value.  a positive value.  positive or negative value.  sometime equal to zero. Choose the correct complement (complements) for the following statements by checking mark  in the box. Answer

For locations on the meridian of Makka city, Qibla direction may be:  180°.  0° or 180°.  90°.  90° or 270°. For locations on the meridian of Makka city, Qibla direction may be:  180°.  0° or 180°.  90°.  90° or 270°. Choose the correct complement (complements) for the following statements by checking mark  in the box. Answer

The shortest distance on a sphere may be:  an arc of a great circle.  an arc of a meridian.  an arc of a parallel.  an arc of the equator. The shortest distance on a sphere may be:  an arc of a great circle.  an arc of a meridian.  an arc of a parallel.  an arc of the equator. Choose the correct complement (complements) for the following statements by checking mark  in the box.   

Polar spherical triangle formed by:  tow meridians and one parallel.  tow meridians and an arc of great circle.  tow meridians and an arc of the equator.  three meridians. Polar spherical triangle formed by:  tow meridians and one parallel.  tow meridians and an arc of great circle.  tow meridians and an arc of the equator.  three meridians. Choose the correct complement (complements) for the following statements by checking mark  in the box.  

On an ellipsoid we can consider that:  N > M always.  N ≥ M.  M > N always.  M = N at the equator.  M = N at the pole. On an ellipsoid we can consider that:  N > M always.  N ≥ M.  M > N always.  M = N at the equator.  M = N at the pole. Choose the correct complement (complements) for the following statements by checking mark  in the box.  

Spherical excess is:  a negative value.  a positive value.  positive or negative value.  sometime equal to zero. Spherical excess is:  a negative value.  a positive value.  positive or negative value.  sometime equal to zero. Choose the correct complement (complements) for the following statements by checking mark  in the box.  

For locations on the meridian of Makka city, Qibla direction may be:  180°.  0° or 180°.  90°.  90° or 270°. For locations on the meridian of Makka city, Qibla direction may be:  180°.  0° or 180°.  90°.  90° or 270°. Choose the correct complement (complements) for the following statements by checking mark  in the box.  

Second question Marks: % 50 Second question Marks: % 50

Find out the coordinates of points A and B In Mercator Projection; Equivalent Cylindrical Projection and Equidistance Cylindrical Projection, considering the sphere as a reference. where: A(40N, 20E); B(60N, 80E); R = 6371 km cylinder is tangent. Find out the coordinates of points A and B In Mercator Projection; Equivalent Cylindrical Projection and Equidistance Cylindrical Projection, considering the sphere as a reference. where: A(40N, 20E); B(60N, 80E); R = 6371 km cylinder is tangent. Answers

Third question Marks: % 30 Third question Marks: % 30

Find out the difference between the Loxodrome and the Orthodrome connecting points A and B, considering the sphere as a reference. Where: A(40N, 20E); B(60N, 80E); R = 6371 km Find out the difference between the Loxodrome and the Orthodrome connecting points A and B, considering the sphere as a reference. Where: A(40N, 20E); B(60N, 80E); R = 6371 km Answers

XA =XA =XA =XA = YA =YA =YA =YA = XB =XB =XB =XB = YB =YB =YB =YB = XA =XA =XA =XA = YA =YA =YA =YA = XB =XB =XB =XB = YB =YB =YB =YB = XA =XA =XA =XA = YA =YA =YA =YA = XB =XB =XB =XB = YB =YB =YB =YB = In Mercator Projection Equivalent Cylindrical Projection Equidistance Cylindrical Projection

Loxodrome distance Orthodrome distance Difference

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