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Lecture 3: Parallel Algorithm Design 1. 2  Balanced binary tree  Pointer jumping  Accelerated cascading  Divide and conquer  Pipelining  Multi-level.

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Presentation on theme: "Lecture 3: Parallel Algorithm Design 1. 2  Balanced binary tree  Pointer jumping  Accelerated cascading  Divide and conquer  Pipelining  Multi-level."— Presentation transcript:

1 Lecture 3: Parallel Algorithm Design 1

2 2  Balanced binary tree  Pointer jumping  Accelerated cascading  Divide and conquer  Pipelining  Multi-level divide and conquer..... Techniques of Parallel Algorithm Design

3 3 Balanced binary tree Processing on binary tree: Let the leaves correspond to input and internal nodes to processors. Example Find the sum of n integers (x 1, x 2,..., x n ).

4 4 Problem of finding Prefix Sum Definition of Prefix Sum Input : n integers put in array A[1..n] on the shared memory Output : array B[1..n], where for each B[i] (1 ≦ i ≦ n) B[i] = A[1] + A[2] A[i] Example Input: A[1..5] = (5, 8, -7, -10, 3) , Output: B[1..5] = (5, 13, 6, -4, -1) Sequential algorithm for Prefix Sum main (){ B[1] = A[1]; for (i = 2; i ≦ n; i++) { B[i] = B[i-1] + A[i]; } } Balanced binary tree

5 5 Solving Prefix Sum problem on balanced binary tree (1) Outline of the parallel algorithm for prefix sum To simplify the problem, let n = 2 k (k is an integer) (1)Calculate the sub-sum from the leaves to the root in bottom up style. (2)Using the sub-sum obtained in (1), calculate the prefix sum from the root to the leaves in up down style. Balanced binary tree

6 6 Solving Prefix Sum problem on balanced binary tree (2) (1)First read the input at the leaves. Then, calculate the sub-sum from the leaves to the root in bottom up style. (2) From the root to the leaves, do the following: send the right son its sub-sum obtained in (1), and send the left son the value of (its sub-sum) – the right son’s sub-sum). 12-(-2) P 4 P 3 P 2 P =14 P 2 P 1 P = (-3) =10 2-(-4) =6 2-5 = = =2 Balanced binary tree

7 7 Solving Prefix Sum problem on balanced binary tree (3) Correctness of the algorithm  When step (1) finished, the sub-sum in each internal node is the sum of its subtree. Balanced binary tree

8 8 Solving Prefix Sum problem on balanced binary tree (4)  In step (2), at each internal node (a)The sub-sum sent to the right son is the summation of its subtree. (b) The sub-sum sent to the left son is the sum of its subtree subtracted by the sum of its right son’s subtree. (a) P 4 P 3 P 2 P 1 P 2 P 1 P =2 7 5 (b) Correctness of the algorithm - Continue 12 Balanced binary tree

9 9 Algorithm Parallel-PrefixSum (EREW PRAM algorithm) main (){ if (number of processor == i) B[0, i] = A[i]; for (h=1; h ≦ log n; h++) { if (number of processor j ≦ n/2 h ) { B[h, j] = B[h-1, 2j-1] + B[h-1, 2j]; } C[log n, 1] = B[log n, 1] for (h = (log n) - 1; h ≧ 0; h--) { if (number of processor j ≦ n/2 h ) { if (j is even) C[h, j] = C[h+1, j/2]; if (j is odd) C[h, j] = C[h+1, (j+1)/2] - B[h, j+1]; } Solving Prefix Sum problem on balanced binary tree (5) Balanced binary tree

10 10 (First step) B[3,1] B[0,4]B[0,3] B[0,2] B[0,1] A[1]A[2]A[3]A[4] B[1,2]B[1,1] B[2,1] B[0,8]B[0,7]B[0,5]B[0,6] A[5]A[6]A[7]A[8] B[1,4]B[1,3] B[2,2] Solving Prefix Sum problem on balanced binary tree (6) Balanced binary tree

11 11 (Second step) C [3,1] C[0,4]C[0,3] C[0,2] C[0,1] C[1,2]C[1,1] C[2,1] C[0,8]C[0,7]C[0,5]C[0,6] C[1,4]C[1,3] C[2,2] Solving Prefix Sum problem on balanced binary tree (7) Balanced binary tree

12 12 Analysis of the algorithm Computing time: for loop repeated log n times and each loop can be executed in O(1) time → O(log n) time Number of processors: Not larger than n→ n processors Speed up: O(n/log n) Cost: O(n log n) It is not cost optimal since the running time of the optimal Θ(n). It is not cost optimal since the running time of the optimal Θ(n). Solving Prefix Sum problem on balanced binary tree (8) Balanced binary tree

13 13 To reduce the cost, solve the problem sequentially when the size of the problem is small. Accelerated cascading is used, usually, with balanced binary tree and divide and conquer techniques. Accelerated cascading is used, usually, with balanced binary tree and divide and conquer techniques. Accelerated cascading Balanced binary tree

14 14 Policy for improving the algorithm To make the algorithm cost optimal, we decrease the number of processors from n to n/logn. (Note: Computing time of the algorithm is O(logn).) Steps: 1.Instead of processing n elements in parallel, divide n elements into n/logn groups with logn elements each. 2.To each group assign one processor and solve the problem for the group sequentially. Accelerated cascading for Prefix Sum problem Balanced binary tree

15 15 Improved algorithm Parallel-PrefixSum (1)Divide n elements in A[1..n] in to n/log n groups with log n elements each. ( O(1) time , O(n/log n) processors ) (2) Assign each group one processor and find the prefix sum for each group. ( O(log n) time , O(n/log n) processors ) Accelerated cascading for Prefix Sum problem A[1..n] log n elements Balanced binary tree

16 16 Improved algorithm Parallel-PrefixSum - continue (3) Let S be the set of the last element in each group (it is the sum of the group). Use algorithm Parallel-PrefixSum to find the prefix sum of S. ( O(log (n/log n) ) = O(log n) time , O(n/log n) processors) Accelerated cascading for Prefix Sum problem (3) Algorithm Parallel-PrefixSum Last element in each group Balanced binary tree

17 17 Improved algorithm Parallel-PrefixSum - continue (4) Use the prefix sum of S to find the prefix sum of the input A[1..n]. ( O(log n) time , O(n/log n) processor ) Result of (3) Accelerated cascading for Prefix Sum problem (4) Balanced binary tree

18 18 Analysis of the improved algorithm Computing time and the number of processors : Each step: O(log n) time, O(n/log n) → Totally, O(log n) time, O(n/log n) processors  Speed up = O(n/log n)  Cost : O(log n × n/log n) = O(n)  It is cost optimal.  It is also time optimal ( Don’t show the proof here) It is optimal algorithm.  It is cost optimal.  It is also time optimal ( Don’t show the proof here) It is optimal algorithm. Accelerated cascading for Prefix Sum problem (5) Balanced binary tree

19 19 (1) 2 divide and conquer (2) n divide and conquer ( ε <1) ε Divide and conquer Divide and Conquer

20 20 Divide and conquer technique Well known technique in algorithm design Solving problems recursively Used very often in both sequential and parallel algorithms How to divide and conquer (1)Dividing step: dividing the problem into a number of subproblems. (2)Conquering step: solving each subproblem recursively. (3) Merging step: merging the solutions of subproblems to the solution of the original problem. Divide and Conquer

21 21 Convex hull problem Input: a set of n points in the plane. Output: the smallest convex polygon which contains all points of the input. (The convex polygon is represented by the list of its vertices in order of clockwise.)  Basic problems in computational geometry.  A lot of applications.  Solved in O(nlogn) time sequentially. In the following we only consider the upper convex hull. ( Upper convex hull: ( P 9, P 8, P 1, P 0 ) ) P 1 P 2 P 3 P 9 P 4 P 5 P 6 P 7 P 8 P 0 Output: ( P,P,P,P,P,P ) Lower convex hull Upper convex hull Divide and Conquer

22 22 Merging of two upper convex hulls p 1 p 2 p 3 p 9 p 4 p 5 p 6 p 7 p 8 p 10 Common upper tangent = (p,p ) 38 Finding the upper common tangent It is known that common tangents can be found in O(log n) time sequentially. Divide and Conquer

23 23 2 divide and conquer (1) Outline of the algorithm Parallel-UpperConvexHull Preprocessing Sort all the points according to their x coordinates, and let the result is the sequence (p 1, p 2, p 3,..., p n ). (1)If the size of sequence is 2, return the sequence. (2)Divide (p 1, p 2, p 3,..., p n ) to the left half part and the right half part, and find the upper convex hull of each recursively. (3) Find the upper common tangent of two upper convex hulls obtained in (2), and output the solution of the problem. Divide and Conquer

24 24 2 divide and conquer (2) How 2 divide and conquer works Find the upper common tangent for two upper convex hulls of two vertices each. Find the upper common tangent for two upper convex hulls of two vertices each. Find the upper common tangent for two upper convex hulls of four vertices each. Find the upper common tangent for two upper convex hulls of four vertices each. Find the upper common tangent for two upper convex hulls of eight vertices each. Find the upper common tangent for two upper convex hulls of eight vertices each. Divide and Conquer

25 25 2 divide and conquer (3) Recursive execution  When the problem is divide once, the size of the subproblem becomes half.  Suppose the size of the subproblems becomes 2 when the problem is divided k times. n/2 k = 2 ⇒ k = log 2 n - 1 n n/2 n/ Height= log 2 n Divide and Conquer

26 26 Complexity of the algorithm Preprocessing : O(log n) time , n processors Steps (1) 〜 (3) : each step runs O(log n) time , use n/2 processors T(n) = T(n/2) + O(log n) Therefore, T(n) = O(log n) ∴ The algorithm runs in O(log n) time using O(n) processors. Computational model: There is no concurrent access ⇒ EREW PRAM 2 divide and conquer (4) Proprocessing Sort the sequence of the points according to their x coordinates. (1)If the size of the sequence is 2, return the sequence. (2)Divide the sequence into the left half part and the right half part, and find the upper convex hull of each recursively. (3)Find the upper common tangent of two upper convex hulls obtained in (2), and output the upper convex hull of the sequence. Proprocessing Sort the sequence of the points according to their x coordinates. (1)If the size of the sequence is 2, return the sequence. (2)Divide the sequence into the left half part and the right half part, and find the upper convex hull of each recursively. (3)Find the upper common tangent of two upper convex hulls obtained in (2), and output the upper convex hull of the sequence. 2 2 Divide and Conquer

27 27 Finding the complexity of the algorithm from recursive tree  Computing time  Number of processors At the level of the leaves, n/2 processors are used at the same time. ⇒ n/2 processors 2divide and conquer (5) T(n)×P(n)=O(nlog n) It is not cost optimal 2 Divide and Conquer

28 28 n divide and conquer Outline of the algorithm Preprocessing Sort the sequence of the input points according to their x coordinates, and let the result be sequence (p 1, p 2, p 3,..., p n ). (1) If the size of the sequence is 2, return the sequence. (2) Divide (p 1, p 2, p 3,..., p n ) to equally-sized subsequence, and find the upper convex hull of each recursively. (3) Merge upper convex hulls into the upper convex hull of the sequence . 1/2 n n Divide and Conquer

29 29 Assign each upper convex hull processors to find the upper common tangents in O(log n) time, and then determine the edges which belong to the solution . n 1/2 n Merging upper convex hull Case 1 Case 2 Divide and Conquer

30 30  When the problem is divided once, the size of the subproblems becomes.  Suppose that the size of the subproblems becomes 2 when the problem is divided k times. = 2 ⇒ k = log log n Recursive tree of n divide and conquer 1/2 n n 1/(2 ) k Height= loglog n n 1/2 n n n 1/4 n n n Divide and Conquer

31 31 Preprocessing : O(log n) time , n processors. Steps (1) 〜 (3) : each step O(log n) time , n processors. T(n) = T(n ) + O(log n), therefore, T(n) = O(log n) ∴ Totally, the algorithm runs in O(log n) time using O(n) processors. Computational model Concurrent reading happens in the procedure of finding the upper common tangents ⇒ CREW PRAM Preprocessing Sort the sequence of the points in their x coordinates. (1) If the size of the sequence is 2 , return the sequence. (2) Divide the sequence into equally-sized subsequences, and find the upper convex hull of each recursively. (3) Find the upper common tangents of the upper convex hulls obtained in (2), and determine the solution. Preprocessing Sort the sequence of the points in their x coordinates. (1) If the size of the sequence is 2 , return the sequence. (2) Divide the sequence into equally-sized subsequences, and find the upper convex hull of each recursively. (3) Find the upper common tangents of the upper convex hulls obtained in (2), and determine the solution. n 1/2 n T(n)×P(n)=O(nlog n) Optimal !!! Analysis of the algorithm Divide and Conquer

32 32 Exercise 1. Suppose nxn matrix A and matrix B are saved in two dimension arrays. Design a PRAM algorithm for A×B using n and nxn processors, respectively. Answer the following questions: (1)What PRAM models that you use in your algorithms? (2)What are the runings time? (3)Are you algorithms cost optimal? (4)Are your algorithms time optimal? 2. Design a PRAM algorithm for A×B using k (k <= nxn processors). Answer the same questions.


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