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Published byJustus Broxson Modified about 1 year ago

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Get a calculator!

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How many parts are there to a triangle ? a b c C Pardekooper AA BB CC

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tan = opposite Pardekooper adjacent

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Lets try setting up for tan C Pardekooper tan = opposite adjacent tan = 8 6 10 8 6

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Lets try setting up for tan C Pardekooper tan = opposite adjacent tan = 8 6 10 6 8

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Lets try setting up for tan C Pardekooper tan = opposite adjacent tan = 12 5 13 12 5

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Lets try setting up for tan C Pardekooper tan = opposite adjacent tan = 12 5 13 5 12

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Pardekooper Solve right triangle ABC if b=32, A=25 o, and C=90 o a b=32 c = 25 o = 90 o The sum of the angles of a triangle is 180 o. = 65 o A B C a c b AA BB CC A+ B+ C = 180 o. 25 o + B+90 o = 180 o. B+115 o = 180 o B = 65 o 65 o 32

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Solve right triangle ABC if b=32, A=25 o, and C=90 o a b=32 c = 25 o = 90 o = 65 o A B C a c =15 32 AA BB CC Pardekooper tan = opposite adjacent tan25 0 = a 65 o 32 32 32 32tan25 0 = a 15 = a 15

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Solve right triangle ABC if b=32, A=25 o, and C=90 o a b=32 c = 25 o = 90 o = 65 o A B C c =15 32 AA BB CC Pardekooper We will find c tomorrow 65 o 15

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Now lets find A to the nearest degree. C Pardekooper tan = opposite adjacent tan = 11 7 7 = tan -1 11 7 = 58 0

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Now lets find B to the nearest degree. C Pardekooper tan = opposite adjacent tan = 11 7 7 = tan -1 7 11 = 32 0

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Pardekooper Here comes the assignment

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Assignment Workbook Page 401 all

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