# DMO’L.St Thomas More C4: Starters Revise formulae and develop problem solving skills. 123456789 101112131415161718 19 2021 222324252627 28293031.

## Presentation on theme: "DMO’L.St Thomas More C4: Starters Revise formulae and develop problem solving skills. 123456789 101112131415161718 19 2021 222324252627 28293031."— Presentation transcript:

DMO’L.St Thomas More C4: Starters Revise formulae and develop problem solving skills. 123456789 101112131415161718 19 2021 222324252627 28293031

DMO’L.St Thomas More Starter 1 Express in partial fractions. Hence find

DMO’L.St Thomas More Starter 1 Express in partial fractions. Hence

DMO’L.St Thomas More Starter 1 Back

DMO’L.St Thomas More Starter 2 Express in partial fractions. Hence find

DMO’L.St Thomas More Starter 2 Express in partial fractions. Hence

DMO’L.St Thomas More Starter 2 Back

DMO’L.St Thomas More Starter 3 Find the cartesian equation of the curve given by the parametric equations

DMO’L.St Thomas More Starter 3 Find a way to eliminate t Back

DMO’L.St Thomas More Starter 4 Find the cartesian equation of the curve given by the parametric equations

DMO’L.St Thomas More Starter 4 Find a way to eliminate t Back

DMO’L.St Thomas More Starter 5 Find the cartesian equation the curve given by the parametric equations

DMO’L.St Thomas More Starter 5 Find a way to eliminate t Back

DMO’L.St Thomas More Starter 6 Find the coordinates of the points where the following curves meet the x,y axes Back

DMO’L.St Thomas More Starter 7 Find the coordinates of the points where the following curves meet the x,y axes Back

DMO’L.St Thomas More Starter 8 Find dy / dx leaving your answer in terms of t. Back

DMO’L.St Thomas More Starter 9 Find dy / dx leaving your answer in terms of t. Back

DMO’L.St Thomas More Starter 10 Find the equation of the tangent to the curve defined by the following parametric equations at the point P where t =  / 2 At P t =  / 2 so that giving Back

DMO’L.St Thomas More Starter 11 Evaluate Back

DMO’L.St Thomas More Starter 12 Complete the table: Back

DMO’L.St Thomas More Starter 13 Complete the table: Back

DMO’L.St Thomas More Starter 14 Complete the table: Back

DMO’L.St Thomas More Starter 15 Evaluate Back

DMO’L.St Thomas More Starter 16 Evaluate Back

DMO’L.St Thomas More Starter 17 In each case find Back in terms of x and y

DMO’L.St Thomas More Starter 18 Find Back

DMO’L.St Thomas More Starter 19 Find Back

DMO’L.St Thomas More Starter 20 Find Back

DMO’L.St Thomas More Starter 21 Use the trapezium rule with 6 strips to estimate x 1st/lastothers 00 0.5 0.2231 1 0.6931 1.5 1.1787 2 1.6094 2.5 1.9810 32.3026  5.6854

DMO’L.St Thomas More Starter 21 Use the trapezium rule with 6 strips to estimate x 1st/lastothers 00 0.5 0.2231 1 0.6931 1.5 1.1787 2 1.6094 2.5 1.9810 32.3026  5.6854

DMO’L.St Thomas More Starter 21 Use the trapezium rule with 6 strips to estimate x 1st/lastothers 00 0.5 0.2231 1 0.6931 1.5 1.1787 2 1.6094 2.5 1.9810 32.3026  5.6854

DMO’L.St Thomas More Starter 21 Use the trapezium rule with 6 strips to estimate x 1st/lastothers 00 0.5 0.2231 1 0.6931 1.5 1.1787 2 1.6094 2.5 1.9810 32.3026  5.6854

DMO’L.St Thomas More Starter 21 Use the trapezium rule with 6 strips to estimate x 1st/lastothers 00 0.5 0.2231 1 0.6931 1.5 1.1787 2 1.6094 2.5 1.9810 32.3026  5.6854 To 3 sig. fig. Back

DMO’L.St Thomas More Starter 22 Use the trapezium rule with 4 strips to estimate x 1st/lastothers 01  / 12 1.1260 /6/6 1.2559 /4/4 1.4142 /3/3 1.6529  2.65293.7962

DMO’L.St Thomas More Starter 22 Use the trapezium rule with 4 strips to estimate x 1st/lastothers 01  / 12 1.1260 /6/6 1.2559 /4/4 1.4142 /3/3 1.6529  2.65293.7962

DMO’L.St Thomas More Starter 22 Use the trapezium rule with 4 strips to estimate x 1st/lastothers 01  / 12 1.1260 /6/6 1.2559 /4/4 1.4142 /3/3 1.6529  2.65293.7962

DMO’L.St Thomas More Starter 22 Use the trapezium rule with 4 strips to estimate x 1st/lastothers 01  / 12 1.1260 /6/6 1.2559 /4/4 1.4142 /3/3 1.6529  2.65293.7962 To 3 sig. fig. Back

DMO’L.St Thomas More Region A is bounded by the curve with equation, the lines x = 1, x = 0 and the x -axis. The region A is rotated through 360 o about the x -axis Find the volume generated. Starter 23 Volume Back

DMO’L.St Thomas More Points A and B have position vectors i + j + k and 2i - 3j + 2k respectively. Find the vector equation of the straight line through A and B. Starter 24 AB = ( 2i - 3j + 2k) – (i + j + k)

DMO’L.St Thomas More Points A and B have position vectors i + j + k and 2i - 3j + 2k respectively. Find the vector equation of the straight line through A and B. Starter 24 AB = ( 2i - 3j + 2k) – (i + j + k) = i – 4j + k Hence, a vector equation is; r = i + j + k + (i – 4j + k) Back

DMO’L.St Thomas More angle Find the acute angle between the two lines with vector equations r = 2i + j + k +t(3i – 5j – k) and r = 7i + 4j + k +s(2i + j – 9k) Starter 25 Consider the angle between their direction vectors; a = (3i – 5j – k) and b = (2i + j – 9k) Cosine of angle Back

DMO’L.St Thomas More Starter 26 The direction vector of the line is a = i + j +k A line has vector equation r = 3i + 5j - k +t(i + j +k) Find the position vector of the point P, on the line, such that OP is perpendicular to the line. When t = OP  a

DMO’L.St Thomas More Starter 26 The direction vector of the line is a = i + j +k A line has vector equation r = 3i + 5j - k +t(i + j +k) Find the position vector of the point P, on the line, such that OP is perpendicular to the line. When t = OP  a  OP. a = 0

DMO’L.St Thomas More Starter 26 When t = OP  a  OP. a = 0 So P has position vector OP = 3i + 5j - k - 7 / 3 (i + j +k) Back

DMO’L.St Thomas More Starter 27 Find the of the tangent to the given curve at the point (1,0). Differentiate; At (1,0) Hence tangent is Back

DMO’L.St Thomas More Starter 28 A curve has parametric equations x = 4cos  and y = 8sin  (a)Find the gradient of the curve at P, the point where  =  / 4 (b)Find the equation of the tangent to the curve at P. (c)Find the coordinates of the point R where the tangent meets the x -axis. (d)Find the area of the region bounded by the curve, the tangent and the x -axis.

DMO’L.St Thomas More Starter 28 A curve has parametric equations x = 4cos  and y = 8sin  (a)Find the gradient of the curve at P, the point where  =  / 4 At P  =  / 4;

DMO’L.St Thomas More Starter 28 A curve has parametric equations x = 4cos  and y = 8sin  (b) Find the equation of the tangent to the curve at P. At P  =  / 4; Equation of tangent;

DMO’L.St Thomas More Starter 28 A curve has parametric equations x = 4cos  and y = 8sin  (c) Find the coordinates of the point R where the tangent meets the x -axis. At R y  =  0

DMO’L.St Thomas More Starter 28 A curve has parametric equations x = 4cos  and y = 8sin  (d) Find the area of the region bounded by the curve, the tangent and the x -axis. Back

DMO’L.St Thomas More Starter 29 Find the general solution of each differential equation: Back

DMO’L.St Thomas More The region R is bounded by the curve C, the x -axis and the lines x = -8 and x = 8. The parametric equations for C are x = t 3 and y = t 2 Find the area of R. Area under curve Starter 30

DMO’L.St Thomas More The region R is bounded by the curve C, the x -axis and the lines x = -8 and x = 8. The parametric equations for C are x = t 3 and y = t 2 The region R is rotated about the x -axis, find the volume generated. Volume Starter 30 Back

DMO’L.St Thomas More A curve has equation Find the coordinates of the points on the curve where Differentiate w.r.t. x Starter 31 What’s this? Sub. back Back

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