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Exercício 1. FLASH PT: exerc1.m funcaoex1.m Tfvetor = 150 Xvetor = 0.0514 0.2802 0.3705 0.2979 Yvetor = 0.2978 0.4546 0.1944 0.0532 Lvetor = 59.9809 Vvetor.

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Presentation on theme: "Exercício 1. FLASH PT: exerc1.m funcaoex1.m Tfvetor = 150 Xvetor = 0.0514 0.2802 0.3705 0.2979 Yvetor = 0.2978 0.4546 0.1944 0.0532 Lvetor = 59.9809 Vvetor."— Presentation transcript:

1 Exercício 1

2 FLASH PT: exerc1.m funcaoex1.m Tfvetor = 150 Xvetor = 0.0514 0.2802 0.3705 0.2979 Yvetor = 0.2978 0.4546 0.1944 0.0532 Lvetor = 59.9809 Vvetor = 40.0191 beta = 0.4002 Resposta:

3 FLASH T BETA: fivetor = 0.3500 Xvetor = 0.0356 0.3310 0.5255 0.4470 Yvetor = 0.0808 0.1858 0.0826 0.0210 Lvetor = 38.9876 Vvetor = 20.9933 exerc1b.m funcaoexerc1b.m Resposta:

4 FLASH P BETA: Xvetor = 0.0849 0.4084 0.3637 0.1430 Yvetor = 0.3891 0.4744 0.1218 0.0147 Lvetor = 12.0057 Vvetor = 28.0134 Tfvetor = 109.2889 exerc1c.m funcaoexerc1c.m Resposta:

5 Exercício 2

6 Temperatura de bolha: Temperatura de bolha para P=120: 60 exerc2.m funcaoexerc2.m Resposta:

7 Temperatura de orvalho (pressao 120) 159 Temperatura de orvalho: exerc2b.m funcaoexerc2b.m Resposta:

8 Exercício 3

9 FLASH PT (COM CALCULO DO CALOR): exerc3.m funcaoexerc3.m Tfvetor = 70 Xvetor = 0.1373 0.2443 0.6184 Yvetor = 0.5679 0.2559 0.1762 Lvetor = 50.6072 Vvetor = 49.3928 beta = 0.4939 Q = 1.6451e+005 Resposta:

10 FLASH PQ: exerc3b.m funcaexerc3b.m Resultados manuais: Tflash Q 45 -2.3487e+004 48 -1.0582e+003 48.1 -317.4960 48.13 -95.3481 48.14 -21.3059 48.142 -6.4979 48.143 0.9060 48.145 15.7138 48.15 52.7326 48.2 422.8717 48.3 1.1629e+003 48.5 2.6419e+003 49 6.3337e+003 50 1.3696e+004

11 FLASH PQ: exerc3c funcaoexerc3c.m funcaoexerc3c1.m Func-count x f(x) Procedure 1 70 164510 initial 2 68.0201 148616 search 3 71.9799 180786 search 4 67.2 142134 search 5 72.8 187652 search 6 66.0402 133056 search 7 73.9598 197499 search 8 64.4 120385 search 9 75.6 211716 search 10 62.0804 102751 search 11 77.9196 232475 search 12 58.8 78260.1 search 13 81.2 263349 search 14 54.1608 44167.7 search 15 85.8392 310779 search 16 47.6 -4024.91 search Looking for a zero in the interval [47.6, 85.8392] 17 48.0889 -399.658 interpolation 18 48.1427 -1.05888 interpolation 19 48.1429 -0.000277233 interpolation 20 48.1429 1.74623e-010 interpolation 21 48.1429 -2.47383e-010 interpolation Zero found in the interval: [47.6, 85.8392]. Q = 48.1429

12

13 Exercício 4

14 Ponto de bolha (corrente 1): exerc4.m funcaoexerc4.m Resposta: Tvetor = 79.2173 Pfvetor = 60 Yvetor = 0.9419 0.0002 0.0579

15 Tfvetor = 130.0855 Pf = 60 Xvetor = 0.0673 0.1343 0.7984 Ponto de orvalho (corrente 4): exerc4b.m funcaoexerc4b.m Resposta:

16 Corrente 2: Resposta: Obtido a partir da corrente 4: Tfvetor = 151.3286 Pvetor = 60 Yvetor = 0.3784 0.0008 0.6208 Ponto de bolha (corrente 2): exerc4c.m funcaoexerc4c.m Resposta: Xvetor = 0.0673 0.1343 0.7984

17 Yvetor = 0.083 0.151 0.775 Corrente 3: Obtido a partir de balanço de massa: Tvetor = 156.2986 Pvetor = 60 Xvetor = 0.0140 0.0582 0.9278 Resposta: Ponto de orvalho: exerc4d.m funcaoexerc4d.m

18 Calculo de Q: H1 = -186.4527 H2 = 1.0460e+003 H3 = 5.4260e+003 H4 = 5.3860e+003 Q = -4.0699e+004 Resposta calculoQ.m


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