Skydiving - Reaching Terminal Velocity The SLOPE is the Velocity 65.2 m/s = 148 mph
Parachute Deployment - Velocity Change The AREA = a dt = v Max Acc = 3.7 g’s! Somersaults Final Chute Velocity
Velocity Change From Parachute (14.4g x sec) – (8.3g x sec) = 6.1g x sec v = (6.1g x sec) x 9.8m/s/s = 59.78m/s Subtract Velocity Change from Terminal Velocity 65.2m/s - 59.78m/s = 5.42m/s New Velocity (12 mph) Most of the Terminal Velocity lost when chute deployed Area below 1 gTotal Area vv
Drag Coefficient Force of Drag: F D = -bv 2 where b is the drag coefficient As velocity increases, the magnitude of the resistive force approaches the gravitational force: mg – bv 2 = 0 Therefore, terminal velocity: v T = (mg / b) 1/2 Giving average drag coefficient of: b = mg / v T 2 b = 160kg x 9.8m/s/s / (65.2m/s) 2 = 0.369 (Total Mass)
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