5Superposition Principle Because the circuit is linear we can find the response of the circuit to each source acting alone, and then add them up to find the response of the circuit to all sources acting together. This is known as the superposition principle.The superposition principle states that the voltage across (or the current through) an element in a linear circuit is the algebraic sum of the voltages across (or currents through) that element due to each independent source acting alone.
6Turning sources off Current source: We replace it by a current source whereAn open-circuitVoltage source:We replace it by a voltage source whereiAn short-circuit
7Steps in Applying the Superposition Principle Turn off all independent sources except one. Find the output (voltage or current) due to the active source.Repeat step 1 for each of the other independent sources.Find the total output by adding algebraically all of the results found in steps 1 & 2 above.In some cases, but certainly not all, superposition can simplify the analysis.
8Example: In the circuit below, find the current i by superposition Turn off the two voltage sources (replace by short circuits).
15Circuit Theorems Linear Circuits and Superposition Thevenin's Theorem Norton's TheoremMaximum Power Transfer
16Thevenin's TheoremIn many applications we want to find the response to a particular element which may, at least at the design stage, be variable.Each time the variable element changes we have to re-analyze the entire circuit. To avoid this we would like to have a technique that replaces the linear circuit by something simple that facilitates the analysis.A good approach would be to have a simple equivalent circuit to replace everything in the circuit except for the variable part (the load).
17Thevenin's TheoremThevenin’s theorem states that a linear two-terminal resistive circuit can be replaced by an equivalent circuit consisting of a voltage source VTh in series with a resistor RTh, where VTh is the open-circuit voltage at the terminals, and RTh is the input or equivalent resistance at the terminals when the independent sources are all turned off.
18Thevenin's TheoremThevenin’s theorem states that the two circuits given below are equivalent as seen from the load RL that is the same in both cases.VTh = Thevenin’s voltage = Vab with RL disconnected (= ) = the open-circuit voltage = VOC
19Thevenin's TheoremRTh = Thevenin’s resistance = the input resistance with all independent sources turned off (voltage sources replaced by short circuits and current sources replaced by open circuits). This is the resistance seen at the terminals ab when all independent sources are turned off.
21Circuit Theorems Linear Circuits and Superposition Thevenin's Theorem Norton's TheoremMaximum Power Transfer
22Norton's TheoremNorton’s equivalent circuit can be found by transforming the Thevenin equivalent into a current source in parallel with the Thevenin resistance. Thus, the Norton equivalent circuit is given below.Formally, Norton’s Theorem states that a linear two terminal resistive circuit can be replaced by an equivalent circuit consisting of a current source IN in parallel with a resistor RN, where IN is the short-circuit current through the terminals, and RN is the input or equivalent resistance at the terminals when all independent sources are all turned off.
23Circuit Theorems Linear Circuits and Superposition Thevenin's Theorem Norton's TheoremMaximum Power Transfer
24Maximum Power Transfer In all practical cases, energy sources have non-zero internal resistance. Thus, there are losses inherent in any real source. Also, in most cases the aim of an energy source is to provide power to a load. Given a circuit with a known internal resistance, what is the resistance of the load that will result in the maximum power being delivered to the load?Consider the source to be modeled by its Thevenin equivalent.
25The power delivered to the load (absorbed by RL) is This power is maximum when
26Thus, maximum power transfer takes place when the resistance of the load equals the Thevenin resistance RTh. Note also thatThus, at best, one-half of the power is dissipated in the internal resistance and one-half in the load.