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Presentation on theme: "ORDINARY DIFFERENTIAL EQUATIONS (ODE)"— Presentation transcript:


2 Differential Equations
Heat transfer Mass transfer Conservation of momentum, thermal energy or mass ODE (4.1) (4.2) PDE (4.3)

3 ODE Definition Example A 3rd order differential equation for r = r(t)
Solution independent (4.4) dependent (4.5) (4.6) (4.7)

4 Important Issues Existence of a solution Uniqueness of the solution
How to determine a solution

5 Linear Equation (1) Rewrite 4.9 for all t Determine
(4.8) (4.9) Rewrite 4.9 Determine for all t (4.10) (4.11) where m(t) is called an integrating factor

6 Linear Equation (2) Multiply both sides of equation 4.10 by m(t)
Observe that the left-hand side of eqn 4.12 can be written as or (4.12) (4.13)

7 Linear Equation (3) Equation (4.12) can be rephrase as:
Integrate both sides of Equation (4.14) with respect to the independent variable: (4.14) (4.15) where c is the constant of integration

8 Example 1 Water containing 0.5 kg of salt per liter is poured into a tank at a rate of 2 l/min, and the well-stirred mixture leaves at the same rate. After 10 minutes, the process is stopped and fresh water is poured into the tank at a rate of 2 l/min, with the new mixture leaving at 2 l/min. Determine the amount (kg) of salt in the tank at the end of 20 minutes if there were 100 liters of pure water initially in the tank. 2 l/min ½ kg salt/l CA 2 l/min, CA (l/min)

9 Solution

10 Example 2 Consider a tank with a 500 l capacity that initially contains 200 l of water with 100 kg of salt in solution. Water containing 1 kg of salt/l is entering at a rate of 3 l/min, and the mixture is allowed to flow out of the tank at a rate of 2 l/min. Determine the amount (kg) of salt in the tank at any time prior to the instant when the solution begins to overflow. Determine the concentration (kg/l) of salt in the tank when it is at the point of overflowing. Compare this concentration with the theoretical limiting concentration if the tank had infinite capacity.

11 Solution

12 THEOREM If the functions p and g are continuous on an open interval a < x < b containing the point x = x0, then there exists a unique function y = f(x) that satisfies the differential equation y’ + p(x)y = g(x) for a < x < b , and that also satisfies the initial condition y(x0) = y0 where y0 is an arbitrary prescribed initial value.

13 Higher ODE Reduces to 1st Order
In general, it is sufficient to solve first-order ordinary differential equations of the form

14 reduces the above equation to a linear equation.
Nonlinear equations can be reduced to linear ones by a substitution. Example: y’ + p(x)y = q(x)yn and if n ¹ 0,1 then n(x) = y1-n(x) reduces the above equation to a linear equation. (4.16) (4.17)

15 Example 3 Suppose that in a certain autocatalytic chemical reaction a compound A reacts to form a compound B. Further, suppose that the initial concentration of A is CA0 and that CB(t) is the concentration of B at time t. Then CA0 – CB (t) is the concentration of A at time t. Determine CB(t) if CB(0) = CB0.

16 Solution


If M is a function of t only, and N is a function of r only, then Separable

19 NONLINEAR EQUATIONS Consider subject to
Then, it is separable and results in: (4.16)

20 Simplifying left-hand side; 1st consider the fraction
(4.17) where a and g are constants to be determined. Then: If we put then

21 If we put then Rewrite equation 4.17

22 And equation 4.16 becomes which integrates to: where m1 is an arbitrary constant to be determined with the given initial t = 0, CB = CB0, then

23 Example of Problem Setup
Consider the continuous extraction of benzoic acid from a mixture of benzoic acid and toluene, using water as the extracting solvent. Both streams are fed into a tank where they are stirred efficiently and the mixture is then pumped into a second tank where it is allowed to settle into two layers. The upper organic phase and the lower aqueous phase are removed separately, and the problem is to determine what proportion of the acid has passed into the solvent phase.

24 Example (cont…) List of assumptions
Combine the two tanks into a single stage Express stream-flow rates on solute-free basis Steady flowrate for each phase Toluene and water are immiscible Feed concentration is constant Mixing is efficient, the two streams leaving the stage are in equilibrium with each other given by y = mx Composition stream leaving is the same with the composition in the stage The stage initially contains V1 liter toluene, V2 liter water and no benzoic acid

25 Problem 1 Consider an engine that generates heat at a rate of 8,530 Btu/min. Suppose this engine is cooled with air, and the air in the engine housing is circulated rapidly enough so that the air temperature can be assumed uniform and is the same as that of the outlet air. The air is fed to the housing at 6lb-mole/min and 65oF. Also, an average of 0.20 lb-mole of air is contained within the engine housing and its temperature variation can be neglected. If heat is lost from the housing to its surroundings at a rate of Ql(Btu/min) = 33.0(T-65oF) and the engine is started with the inside air temperature equal to 65oF. Derive a differential equation for the variation of the outlet temperature with time. Calculate the steady state air temperature if the engine runs continuously for indefinite period of time, using Cv = 5.00 Btu/lb-mole oF.

26 Problem 2 A liquid-phase chemical reaction with stoichiometry A  B takes place in a semi-batch reactor. The rate of consumption of A per unit volume of the reactor is given by the first order rate expression rA (mol/liter.s) = kCA where CA (mol/liter) is the reactant concentration. The tank is initially empty. At time t=0, a solution containing A at a concentration CA0(mol/liter) is fed to the tank at a steady rate f(liters/s). Develop differential balances on the total volume of the tank contents, V, and on the moles of A in the tank, nA .

27 Solving ODEs using Numerical Methods
Initial Value Problem (IVP) y’’ = -yx y(0) = 2, y’(0) = 1 Boundary Value Problem (BVP) y” = -yx y(0) = 2, y’(1) = 1

28 General Procedure Re-write the dy and dx terms as Δy and Δx and multiply by Δx Literally doing this is Euler’s method

29 Tank mixing problem

30 Mixing tank Dt Error Et at t=600 300 1.4 150 0.61 100 0.39 50 0.19 30
0.11 15 0.055 10 0.036 5 0.018 3 0.011

31 Matlab output

32 Error analysis We saw that the error depended on the time step size
Why? Extrapolating the curve using a linear function

33 Improvements to Euler’s Method
Heun’s method (predictor-corrector) Procedure calc yi+1 with Euler (predictor) calc slope at yi+1 calc average slope use this slope to calc new yi+1 (corrector)

34 Heun example

35 Midpoint Method Use Euler to calculate a midpoint location
evaluate slope y’ at the midpoint use that to calculate full step location

36 Runge-Kutta

37 R-K – General form

38 R-K – 1st Order Form

39 R-K – 2nd Order Form y(x) xi xi x

40 RK2 – Options y(x) xi xi x

41 RK2 – Options y(x) xi xi x y(x) xi xi x

42 R-K – 2nd Order Form

43 RK – 3rd Order Form y(x) xi xi x

44 RK – 4th Order y(x) xi xi x

45 Example y΄=x+y, y(0)=0 x yo k1=fi k2=f(x+h/2,y+h/2k1)
yn=yo+1/6(k1+2k2+2k3+k4)h 0.1 0.11 0.222 0.2 0.0214 0.221 0.344 0.356 0.493 0.0918 0.4 0.092 0.492 0.641 0.656 0.823 0.2221 0.6 0.822 1.004 1.023 1.227 0.4255 0.8 0.426 1.226 1.448 1.470 1.720 0.718 1 1.718 1.990 2.017 2.322 1.120 1.2 2.320 2.652 2.685 3.057 1.655 1.4 3.055 3.461 3.501 3.955 2.353 1.6 3.953 4.448 4.498 5.052 3.250 1.8 5.050 5.654 5.715 6.393 4.389


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