1. ΗΥ-566 ΔΙΑΧΕΙΡΙΣΗ ΓΝΩΣΗΣ ΣΤΟ ΔΙΑΔΙΚΤΥΟ Ασκηση 1 Πεδρο, Κατη και Μπεριτ Ελενη

2. The zoo ontology Description and diagram of the domain. RDFS. RDF Data. RQL Queries.

3. Description and diagram.diagrams_and_concepts.pdfdiagrams_and_concepts.pdf

4. Description and diagram II

5. RDFS (1 of 4) The class of all the persons. Implemets the first name of Person. Person's phone number.

6. RDFS (2 of 4) The class of Employee is a subclass of Person The id for the Employee.

7. RDFS (3 of 4) The class AnimalWorker is a sublass of Employee This is the class of the Animals. The class of all the Cages for the Animals

8. RDFS (4 of 4) Property which makes a relation between an AnimalWorker and an Animal. An AnimalWorker can take care of one or more Animals. Property which makes a relation between an AnimalWorker and a Cage. An AnimalWorker can clean one or more Cages. Property which makes a relation between an Animal and a Cage. One Animal lives in one Cage.

9. RDF Data (1 of 3) <rdf:RDF xml:lang="en" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#" xmlns:zoo="myZoo"> <zoo:Cage rdf:ID="cage2" zoo:cageID="002" zoo:size="10x10x10" zoo:buildingDate="12/12/2000" /> <zoo:AnimalWorker zoo:firstName="Janis" zoo:lastName="Halkiadakis" zoo:telephoneNumber="123456789" zoo:addressStreet="Dimokratias 22" zoo:addressCity="Iraklion" zoo:addressCountry="Greece" zoo:dateOfBirth="21/11/71" zoo:sex="male"

10. RDF Data (2 of 3) zoo:employeeID="0004" zoo:salary="1000" zoo:absentDays="44" zoo:hiredDate="12/12/2000" zoo:contractType="Full time" zoo:specialization="land" zoo:freeDay="Tuesday" zoo:animalPreferences="cats“>

11. RDF Data (3 of 3) <zoo:WaterAnimal rdf:ID="animal2“ zoo:animalID="0002" zoo:latinName="Fishus" zoo:englishName="Fish" zoo:birthDate="12/12/2001" zoo:length="1m" zoo:weight="8kg" zoo:height="10cm" zoo:arrivalDate="12/12/2001" zoo:plantEater="yes" zoo:threatened="no" zoo:dailyFoodAmount="1kg" zoo:temperature="33" zoo:poisonous="no" zoo:saltPercentageInWater=“3" zoo:minVolumeInWater="90“>

12. RQL (1 of 4) -Find english name of all animals who are threatened: select N from Animal{X}, {Y}englishName{N}, {Z}threatened{P} where X=Y and X=Z and P="true" -Find first and last name of all animal workers who takes care of poisonous animals: select F,L from AnimalWorker{X}, {Y}firstName{F}, {Z}lastName{L}, AnimalWorker{S}.takesCareOf{T}, {U}poisonous{V} where X=Y and X=Z and X=S and T=U and V="true"

13. RQL (2 of 4) -Find first name, last name and telephone number of employees more than 5 absent days: select F,L,PH from Employee{X}, {Y}firstName{F}, {Z}lastName{L}, {U}telephoneNumber{PH}, {V}absentDays{W} where X=Y and X=Z and X=U and X=V and W>5 -Find all classes: Class

14. RQL (3 of 4) -Find the animal workers (first and last name), and the animals (animal ID) they take care of: select F,L,AID from AnimalWorker{X}.takesCareOf{Y}, {V}firstName{F}, {W}lastName{L}, {U}animalID{AID} where Y=U and X=V and X=W - Find which animal (animal ID) lives in the cage with id="cage1": select AID from Animal{X}.livesIn{Y}, {Z}cageID{W}, {U}animalID{AID} where Y=Z and W="cage1“ and X=U

15. RQL (4 of 4) - The employees (first and last name) who works in the department with id="01": select F,L from Employee{X}, {U}belongsTo{B}, {Z}deptID{W},{V}firstName{F}, {S}lastName{L} where X=U and B=Z and W="01 and V=X and S=X - Find the english name for the animal which is taken care of by the animal worker with ID=“0001" select N from animal{A}.isTreatedBy{W}, {C}englishName{N}, {W}employeeID{X} where X=“0001" and A=C