# RK Patrol.

## Presentation on theme: "RK Patrol."— Presentation transcript:

RK Patrol

The HOT, BURNING News TODAY:
Mechanical Energy and its types: DISCOVERED What is meant by Conservation of Mechanical Energy: ANSWERED THINGS TO REMEMBER when solving conservation of Energy problems Formulas to be IMPLANTED on mind and EXAMPLES of Energy Transfers Problem SOLVED

Mechanical Energy and its types: DISCOVERED
Mechanical Energy is the sum of KINETIC and POTENTIAL ENERGY. 3 TYPES: Kinetic Energy a.k.a. KE Gravitational Potential Energy a.k.a PEg Elastic Potential Energy a.k.a. PEs

What is meant by Conservation of Mechanical Energy: ANSWERED
In a closed system, nothing leaves and nothing enters. Therefore, in a closed system, total mechanical energy is conserved. An example of a mechanical system: A satellite is orbiting the Earth only influenced by the conservative gravitational force and the mechanical energy is therefore conserved.

THINGS TO REMEMBER when solving conservation of Energy problems
Carefully identify the system. Make sure it is closed; no objects can enter it or leave it. It must also be isolated; no external force can act on any object in the system. Thus, no work can be done on or by objects outside the system. Is friction present? If it is, then the sum of kinetic and potential energy will not be constant. But, the sum of kinetic energy, potential energy and the work done against friction will be constant. Finally, if there is no friction, find the initial and final total energies and set them equal

Formulas to be IMPLANTED on mind and EXAMPLES of Energy Transfers
KEi + PEi = KEf + PEf PE = mgh KE = ½ mv2

Formulas to be IMPLANTED on mind and EXAMPLES of Energy Transfers
KEi + PEi = KEf + PEf PE = mgh KE = ½ mv2

Formulas to be IMPLANTED on mind and EXAMPLES of Energy Transfers
KEi + PEi = KEf + PEf PE = mgh KE = ½ mv2

Formulas to be IMPLANTED on mind and EXAMPLES of Energy Transfers
KEi + PEi = KEf + PEf PE = mgh KE = ½ mv2

Problem SOLVED Problem: A large chunk of ice with mass 15.0 kg falls from a roof 8.00 m above e the ground a. Find the kinetic energy of the ice when it reaches the ground b. What is the speed of the ice when it reaches the ground? c. Is the answer the same as you would determine by solving as a constant acceleration problem?

Problem SOLVED Given: m = 15.0 kg Unknowns: a. Kef b.Vf g = 9.80 m/s2
Basic Equations: KEi + PEi = KEf + PEf Given: m = 15.0 kg g = 9.80 m/s2 h = 8.00 m KEi = 0 PEf = 0 Solution: KEi + PEi = KEf + PEf 0 + mgh = KEf + 0 KEf = mgh = (15.0 kg) (9.80 m/s2) (8.00 m) = 1.18 x 10^3 J

Problem SOLVED b. KEf = ½ mvf2 vf2 = 2KEf = 2(1.18 x 10^3 J) =157 m2/s2 m 15.0 kg vf = 12.5 m/s c. yes

THE END

Questions to Answer I. IDENTIFICATION 1. What is mechanical energy?
2 – 4. Give the 3 types of Mechanical energy and their corresponding examples. (0.5 point each number) 5. What is meant by Conservation of Mechanical Energy?

6. A mechanical system has been mentioned earlier and in connection to that, cite an example of it.
7-9. Identify the formulas needed to be implanted on mind with regards to this topic. 10. What formula would perfectly suit to this problem and how is it derived? Bill throws a 10 g ball straight down from a height of 2.0m. The ball strikes the floor at a speed of 7.5 m/s. What was the initial speed of the ball?