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Ap Stoichiometry Limiting Reactant

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There are 2.5 g of NH3 reacting with 2.85 g of O2 Which is limiter? 4NH 3 + 5 O 2 → 4NO + 6 H 2 O 2.50 gNH3 1molNH3 4mol NO 30gNO 17g NH3 4mol NH3 1molNO 2.85g O2 1 mol O2 4 mol NO 30g NO 16g O2 5 mol O2 1 mol NO

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NH3 = 4.4 g O2 = 2.14 g O2 is limiter

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How much is there in excess? Law of Conservation of Mass 4NH 3 + 5 O 2 → 4NO + 6 H 2 O 2.85g 2.14 Finish stoich for water 2.85g O2 1 mol O2 6 mol H2O 18g H2O 32g O2 5 mol O2 1 mol H2O = 1.92 g of H2O

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4NH 3 + 5 O 2 → 4NO + 6 H 2 O ? 2.85g = 2.14 1.92 = 4.06 1.21 + 2.85 = 4.06 Original NH3 was 2.50 g Excess = 2.50 – 1.21 = 1.29 grams

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Solving a Stoichiometry Problem 1.Balance the equation. 2.Convert given to moles. 3.Determine which reactant is limiting. 4.Use moles of limiting reactant.

Solving a Stoichiometry Problem 1.Balance the equation. 2.Convert given to moles. 3.Determine which reactant is limiting. 4.Use moles of limiting reactant.

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