4 8B Describing Polyfunctional Bases The overall basic dissociation reaction of sodium carbonate is described by the equationsSolving the several simultaneous equations that are involved can be difficult and time consuming. Fortunately, simplifying assumptions can be invoked when the successive equilibrium constants for the acid (or base) differ by a factor of about 10³ (or more).8-4
5 8C Finding the pH of Solutions of Amphiprotic Salts The solution could be acidic because ofor basic because of8-5
6 8C Finding the pH of Solutions of Amphiprotic Salts Whether a solution of NaHA is acidic or basic depends on the relative magnitude of the equilibrium constants for these processes:(8-1)(8-2)8-6
7 8C Finding the pH of Solutions of Amphiprotic Salts As we can see in Feature 8-2, solution of these equations yields an approximate value of [H₃O⁺] that is given by the equation(8-3)
8 8C Finding the pH of Solutions of Amphiprotic Salts Frequently, the ratio cNaHA / Ka1 is much larger than unity in the denominator of Equation 8-3 and Ka2cNaHA is considerably greater than Kw in the numerator.(8-4)
9 Example 8-1Calculate the hydronium ion concentration of a M NaHCO₃ solution.We first examine the assumptions leading to Equation 8-4. The dissociation constants for H₂CO₃ are Ka1 = 1.5 × 10⁻⁴ and Ka2 = 4.69 × 10⁻¹¹. Clearly, cNaHA / Ka1 in the denominator is much larger than unity; in addition, Ka2cNaHA has a value of 4.69 × 10¯¹², which is substantially greater than Kw . Thus, Equation 8-4 applies and
10 Example 8-2Calculate the hydronium ion concentration of a 1.00×10¯³ M Na₂HPO₄ solution. The pertinent dissociation constants are Ka2 and Ka3 , which both contain [HPO₄2–]. Their values are Ka2 = × 10¯⁸ and Ka3 = 4.5 × 10⁻¹³. Considering again the assumptions that led to Equation 8-4, we find that the ratio (1.00 × 10¯³)/(6.32 × 10¯⁸) is much larger than 1, so the denominator can be simplified. The product Ka3cNa₂HPO₄ is by no means much larger than Kw , however. We therefore use a partially simplified version of Equation 8-3:Use of Equation 8-4 yields a value of 1.7 × 10¯¹⁰M.
11 Figure 8-1Figure 8-1 Titration of mL of M H2A with M NaOH. For H2A, Ka1 = 1.00 10–3 and Ka2 = 1.00 10–7. The method of pH calculation is shown for several points and regions on the titration curve.
12 Example 8-4Construct a curve for the titration of mL of M maleic acid, with M NaOH. Consider the initial pH, the first buffer region, the first equivalence point, the second buffer region, the second equivalence point, and the region beyond the second equivalence point. The calculations are done manually here.
13 Example 8-4Because the ratio Ka1/Ka2 is large (2 × 10⁴), we proceed as just described for constructing Figure 8-1.
14 Example 8-4Initial pHSubstituting these relationships into the expression for Ka1 gives
16 Example 8-4 First Buffer Region A buffer consisting of the weak acid H₂M and its conjugate base HM¯. To the extent that dissociation of HM¯ to give M²¯ is negligible,
17 Example 8-4Substitution of these values into the equilibrium-constant expression for Ka1 yields a tentative value of 5.2 × 10¯² M for [H₃O⁺]. It is clear, however, that the approximation [H₃O⁺] << cH₂M or cHM¯ is not valid; therefore, Equations 7-6 and 7-7 must be used, and
18 Example 8-4Because the solution is quite acidic, the approximation that [OH¯] is very small is surely justified. Substitution of these expressions into the dissociationconstant relationship gives
20 Example 8-4 Second Buffer Region Further additions of base to the solution create a new buffer system consisting of HM¯ and M²¯.
21 Example 8-4 Second Equivalence Point After the addition of mL of M sodium hydroxide, the solution is M in Na2M (2.5 mmol/75.00 mL). Reaction of the base M²¯ with water is the predominant equilibrium in the system
23 Example 8-4 pH Beyond the Second Equivalence Point When mL of NaOH have been added,
24 8D Constructing Titration Curves for Polyfunctional Acids Figure 8-3 shows titration curves for three other polyprotic acids.The ratio Ka1/Ka2 for oxalic acid (curve B) is approximately 1000.The magnitude of the pH change is too small to permit precise location of equivalence with an indicator.
25 8D Constructing Titration Curves for Polyfunctional Acids Curve A in Figure 8-3 is the theoretical titration curve for triprotic phosphoric acid. Here, the ratio Ka1/Ka2 is approximately 10⁵, as is Ka2/Ka3.Curve C is the titration curve for sulfuric acid, a substance that has one fully dissociated proton and one that is dissociated to a relatively large extent (Ka2 = × 10¯²).
26 Figure 8-3Figure 8-3 Curves for the titration of polyprotic acids. A M NaOH solution is used to titrate mL of M H3PO4 (curve A), M oxalic acid (curve B), and M H2SO4 (curve C).
27 8E Drawing Titration Curves for Polyfunctional Bases
28 Figure 8-4Figure 8-4 Curve for the titration of mL of M Na2CO3 with M HCl.
29 Feature 8-4 Titration Curves for Amino Acids The internal proton transfer from the carboxyl group to the amine group of an amino acid is very favorable in aqueous solution so that amino acids exist as zwitterions as shown below for glycine.
30 Feature 8-4 Titration Curves for Amino Acids The conjugate acid of the zwitterion can be treated as a polyprotic acid.The zwitterion can act as an acid because of the second proton transfer or as a base because of
31 Feature 8-4 Titration Curves for Amino Acids The pH at which no net migration occurs is called the isoelectric point; this point is an important physical constant for characterizing amino acids. The isoelectric point is readily related to the ionization constants for the species. Thus, for glycine,
32 Feature 8-4 Titration Curves for Amino Acids At the isoelectric point,
33 Feature 8-4 Titration Curves for Amino Acids If we substitute Kw/[H₃O⁺] for [OH¯] and rearrange, we getThe isoelectric point for glycine occurs at a pH of 6.0. That is,
34 8F The Composition of Polyprotic Acid Solutions as A Function of pH (8-11)8-34
35 8F The Composition of Polyprotic Acid Solutions as A Function of pH (8-12)(8-13)(8-14)
36 Figure 8-6Figure 8-6 Titration of mL of M maleic acid with M NaOH. The solid curves are plots of alpha values as a function of volume. The broken curve is the titration curve of pH as a function of volume.8-36
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