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Bamm Mining Company Transshipment Problem STRATEGIC RESOURCE ALLOCATION and PLANNING MGMT E-5050.

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Presentation on theme: "Bamm Mining Company Transshipment Problem STRATEGIC RESOURCE ALLOCATION and PLANNING MGMT E-5050."— Presentation transcript:

1 Bamm Mining Company Transshipment Problem STRATEGIC RESOURCE ALLOCATION and PLANNING MGMT E-5050

2 Bamm Mining Company Bamm Mining Company is currently extracting rock from two mines. Once it is taken from the ground and loaded on a truck, it is sent to one of two plants for processing. The processed rock is then shipped to one of three builders’ supply stores, where it is sold for landscaping purposes. The cost of transportation, the supply available at each mine, and the processing capacity of each plant are given on the following table:

3 Bamm Mining Company To Plant From Mine #1#2 Daily Supply A$6.00$ tons B$7.00$ tons Daily Process Capacity 500 tons Cost per Ton for Shipping

4 Bamm Mining Company The cost of shipping from each processing plant to each store and the daily demand are as follows: To From Plant Supply Store ASupply Store BSupply Store C #1$13.00$17.00$20.00 #2$19.00$22.00$21.00 Daily Demand Cost per Ton for Shipping

5 Bamm Mining Company REQUIREMENT: 1.Formulate a linear program that can be used to determine how to meet the demands of the 3 supply stores at the least cost. 2.Solve this by computer. How many tons should be shipped from each mine to each plant? 3.How many tons should go from each plant to each store?

6 Bamm Mining Company Assume that the cost of processing the rock is $22.00 per ton at Plant 1 and $18.00 per ton at Plant 2. REQUIREMENT: 1.Formulate a linear program to minimize the total processing and transportation cost. 2.Solve this by computer. What is the optimal solution?

7 Solution Let : A 1 = tons of ore from mine A to plant 1 A 2 = tons of ore from mine A to plant 2 B 1 = tons of ore from mine B to plant 1 B 2 = tons of ore from mine B to plant 2

8 Solution Let : X 1 = tons shipped to Builder’s Home from plant 1 X 2 = tons shipped to Builder’s Home from plant 2 Y 1 = tons shipped to Homeowners’ Hdqtrs from plant 1 Y 2 = tons shipped to Homeowners’ Hdqtrs from plant 2 Z 1 = tons shipped to Hardware City from plant 1 Z 2 = tons shipped to Hardware City from plant 2

9 Solution Minimize cost = 6A 1 + 8A 2 + 7B B X X Y Y Z Z 2 subject to : A 1 + A 2 = 320 ( supply at mine A ) B 1 + B 2 = 450 ( supply at mine B ) A 1 + B 1 =< 500 ( capacity at plant 1 ) A 2 + B 2 =< 500 ( capacity at plant 2 )

10 Solution X 1 + X 2 = 200 ( demand at Builder’s Home ) Y 1 + Y 2 = 240 ( demand at Homeowners’ Hdqtrs ) Z 1 + Z 2 = 330 ( demand at Hardware City ) A 1 + B 1 = X 1 + Y 1 + Z 1 Units shipped into plant 1 must equal units shipped out of plant 1 A 2 + B 2 = X 2 + Y 2 + Z 2 Units shipped into plant 2 must equal units shipped out of plant 2 All variables => 0

11 Solution A1 = 50 tons of ore from mine A to plant 1 A2 = 270 tons of ore from mine A to plant 2 B1 = 450 tons of ore from mine B to plant 1 X1 = 200 tons shipped to Builder’s Home from plant 1 Y1 = 240 tons shipped to Homeowners’ Hdqtrs from plant 1 Z1 = 60 tons shipped to Hardware City from plant 1 Z2 = 270 tons shipped to Hardware City from plant 2 All other variables = 0 Minimum total cost = $19,160.00

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