Download presentation

Presentation is loading. Please wait.

Published byCarla Hardy Modified over 2 years ago

1
Solutions to Chapter 3 Assignment 3 CE/AE/EnvSci 4/524

2
3.7: The wind has a velocity of 10 m/h at 10 m in a rural area. When lapse rate is 0.2°C/100, what is the velocity at an elevation of 100 m in miles per hour? u/u 1 = (z/z 1 ) p Table 3-2, ΔT/ΔZ = 0.2C/100, Stability Class = E U = u 1 (z/z 1 ) p = 10 mph * (100m/10m) 0.35 = 22.4 mph

3
3.9: Consider that the wind speed u is 2 m/s at a height of 10 m. Estimate wind speed at a) 200 m and b) 300 m for the 6 stability classes in Table 3-3 for rural conditions. U = u 1 (z/z 1 ) p = 2 m/s (200/10)^ P A: U = 2 (200/10) 0.07 = 2.47 m/s B: U = 2 (200/10) 0.07 = 2.47 m/s C: U = 2 (200/10) 0.10 = 2.70 m/s D: U = 2 (200/10) 0.15 = 3.13 m/s E: U = 2 (200/10) 0.35 = 5.71 m/s F: U = 2 (200/10) 0.55 = 10.39 m/s U = u 1 (z/z 1 ) p = 2 m/s (300/10)^ P A: U = 2 (300/10) 0.07 = 2.54 m/s B: U = 2 (300/10) 0.07 = 2.54 m/s C: U = 2 (300/10) 0.10 = 2.81 m/s D: U = 2 (300/10) 0.15 = 3.33 m/s E: U = 2 (300/10) 0.35 = 6.58 m/s F: U = 2 (300/10) 0.55 = 12.9 m/s

4
3.14: In a given situation the ground-level air temperature is 15° C, while the normal maximum surface temperature for that month is a) 26°C and b) 24°C. At an elevation of 300 m, the temperature is found to be 21°C. What is the maximum mixing depth in meters for the two cases? Air parcel will rise until its temperature T` = local atmospheric temperature, neutral equilibrium. Temperature profile = DT/dz, solid line Dry adiabatic is dashed MMD

5
3.14: In a given situation the ground-level air temperature is 15° C, while the normal maximum surface temperature for that month is a) 26°C and b) 24°C. At an elevation of 300 m, the temperature is found to be 21°C. What is the maximum mixing depth in meters for the two cases? Air parcel will rises until intersection of lines. Slope for existing condition is: (21° – 15°) = 0.02°C/m 300m Adiabatic lapse rate (slope) is -0.0098°C/m (equation 3-5) MMD is point where slopes intersect (Z)

6
3.14: for condition A existing condition is: 0.02°C/m Adiabatic lapse rate (slope) is -0.0098°C/m (equation 3-5) MMD is point where slopes intersect (Z) 15 + Z (0.02°C/m) = 26 + Z(-0.0098°C/m) = Z = _______26°C - 15°C_____ = 369.13 m (0.02°C/m + 0.0098°C/m) MMD

7
3.14: for condition B existing condition is: 0.02°C/m Adiabatic lapse rate (slope) is -0.0098°C/m (equation 3-5) MMD is point where slopes intersect (Z) 15 + Z (0.02°C/m) = 24 + Z(-0.0098°C/m) = Z = _______24°C - 15°C_____ = 302 m (0.02°C/m + 0.0098°C/m) MMD

Similar presentations

OK

Skew T. What is a skew-T diagram? Diagram used to plot vertical profiles through the atmosphere Determine atmospheric stability.

Skew T. What is a skew-T diagram? Diagram used to plot vertical profiles through the atmosphere Determine atmospheric stability.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on mathematics for class 9 Ppt on question tags in english grammar Ppt on latest technology in cse Ppt on different kinds of birds Ppt on economic reforms in india 1991 crisis Converter pub to ppt online templates Store design and display ppt on ipad Ppt on 500 mw turbo generator Ppt on clutch system in automobile Ppt on industrial public address system