Presentation on theme: "Computer Networking Error Control Coding"— Presentation transcript:
1 Computer Networking Error Control Coding Dr Sandra I. Woolley
2 An Introduction to Error Control Coding Data transmission and channel errorsIntroduction to error controlParityHamming codesexample of a simple linear block codeInterleaving and product codes(+ demonstration).IP checksums (Polynomial/Cyclic Redundancy Codes)We will work through examples in class.
3 IntroductionError control coding involves the addition of redundancy to enable error detection and/or correction.There are two basic approaches to error controlAutomatic retransmission request (ARQ)Forward error correction (FEC)More generally, when errors are detected data can be resent, concealed or corrected.
4 Data Transmission Channel errors Data Compress Encrypt Error control CompressEncryptError controlLine codeEncode signal to suit communication channel characteristicsEncrypt message for added securityRemove redundancy for efficient communicationAdd systematic redundancy to protect data against channel errors
5 Designing Error Protection Systems “Know your enemy”Understand the channel burst length distribution and gap length distribution, i.e., how large and how frequent are the errors.Trade-off the correction of data with the addition of redundancySystem cost/delayShould errors be detected and corrected?Detect and request retransmission? Detect and conceal?How important is the data.Is all data equally important? Should some data elements be protected more than others?Is accepting bad data as good worse than rejecting good data as bad?
6 Channel Errors Errors can occur singly or in bursts. Most channel errors can be approximated by simple state models.The BER (Byte error rate) is a simple measure of channel quality.In the Good state there are no errors.Bad Type 1 and Bad Type 2 represent two types of error events; non-burst and burst.p1 and p2 are the probabilities of starting the errored states.q1 and q2 are the probabilities of ending the errored states.GoodBadType 21-q2p2Type 11-q1p11-p1-p2The modifiedGilbert modelq1q2
7 Channel ErrorsBurst length distributions provide important information about channel error activity.GoodBadType 21-q2p2Type 11-q1p11-p1-p2q1q2increasing p1Probability (log scale)decreasing q1increasing p2decreasing q2error length (log scale)
8 The Simplest Error Detection – Parity Bit Odd or even parity requires that the sum total of codewords be odd or even, respectively.So for odd parity there will be an odd number of ones and for even parity there will be an even number of ones.For example, if we have data bits and we want even parity. We need to add a parity bit of 1 to have an even number on ones. So, if we append our parity bit to the end, we have a codeword of (where 1 is our even parity bit).7 bits of data (number of 1s)8 bits including parityevenodd(0)(3)(4)(7)Examples from WikipediaThe parity bit is added to the front
9 The Hamming (7,4) CodeAn example of an (n,k) linear block code. Each codeword contains n bits, k information bits and (n-k) check bits.The Hamming (7,4) is a nice easy code but it is not very efficient (it has a 75% overhead!). It generates codewords with a ‘Hamming distance’ of 3, i.e., all codewords differ in 3 locations. It can correct one bit in error and detect two.In the codeword [C]= k1 k2 k3 k4 c1 c2 c3,k1-k4 are information bits and c1-c3 are check bits (the ‘systematic redundancy’). “+” here denotes binary addition (it is the same as XOR).c1=k1+k2+k4c2=k1+k3+k4c3=k2+k3+k4So the data [X] = [ ] becomes the codeword[ (0+1+0) (0+1+0) (1+1+0)] = [ ]
10 The Hamming (7,4) CodeIf we insert an error at bit 2 [ x ](syndrome) [ ] becomes [ ] Note c1 and c3 are wrong - these intersect at k2 hence k2 is in errorc1=k1+k2+k41k1k2k411c2=k1+k3+k4k3c3=k2+k3+k4
11 The Hamming (7,4) CodeIf we insert an error at bit 4 [ x ](syndrome) [ ] becomes [ ] Note c1,c2 and c3 are all wrong hence k4 is in errorc1=k1+k2+k41k1k211k411c2=k1+k3+k4k3c3=k2+k3+k4
12 Bi-Directional/Product Codes Imagine we have 4 x 4 data bits k11-k14, k21-k24, k31-k34, k41-k44Arranging them horizontally we can add error protection in the vertical direction as well.k11 k12 k13 k14 c11 c12 c13k21 k22 k23 k24 c21 c22 c23k31 k32 k33 k34 c31 c32 c33k41 k42 k43 k44 c41 c42 c43d11 d12 d13 d14 f11 f12 f13d21 d22 d23 d24 f21 f22 f23d31 d32 d33 d34 f31 f32 f33
13 Bi-Directional/Product Codes In the class we observe animated demonstrations of these codes at work using the product code demonstrator.First we generate errors using the Modified Gilbert Error Model. The model requires just 4 probability values to describe the errors it generates.Next the data was interleaved.Then the data was iteratively corrected vertically and horizontally.The demonstration shows how, with more sophisticated error control coding, we can significantly increase correction capacity making even severely corrupted data correctable.The complex and time-consuming nature of this method makes it inappropriate for Internet protocols*. However, robust correction is desirable in storage systems and these methods can be found in the more sophisticated server room RAID-type** storage systems.*but important payload data could be protected in this way**RAID – Redundant Array of Inexpensive Disks
14 InterleavingInterleaving (systematically reordering) the protected data stream means that errors are distributed, i.e., more correctable.For example, consider the three (7,4) Hamming codewords below in transmission on a channel with a small burst of 3 errored bits (syndrome x x x).k1 k2 k3 k4 c1 c2 c3 k1 k2 k3 k4 c1 c2 c3 k1 k2 k3 k4 c1 c2 c3x x xThese 3 bits all fall in one codeword, so would be uncorrectable.But with a three-way interleave:-k1 k1 k1 k2 k2 k2 k3 k3 k3 k4 k4 k4 c1 c1 c1 c2 c2 c2 c3 c3 c3Assuming the same syndrome of 3 bits in error, if we unscamble the bits (shown below) we can see now there is now just one bit in error in each codeword, and so our data is correctable.x x x
15 More Sophisticated Codes Sophisticated interleaving strategies are used in most advanced digital recording systems.CDs use product codes but with Reed-Solomon codes (not Hamming.) They also use interleaving. DVDs and Blu-ray discs also use Reed Solomon block codes.Reed-Solomon (RS) codes work on groups (e.g., bytes) of inputs. For bytes n<28 (codewords are a maximum of 255 bytes). There is only a very small probability of ‘crypto-errors’, i.e., correcting good bytes by mistake.RS block codes can correct (n-k)/2 bytes and detect (n-k) bytes. For example, RS(122,106) can correct ( )/2 = 8 bytes in error.Other systems use layers of error correction. If a lower (simpler) layer detects errors, the next (more powerful) layer is inspected. If errors are still detected the final layer is interrogated. This method increases the speed of decoding by only computing check bytes when errors are suspected. DAT tape drives uses 3 layers of error control.Newer “turbo codes” provide enhanced protection by making soft decisions.
16 IP ChecksumThe IP checksum is an IP header field. It is calculated using the contents of the header.It was designed for ease of implementation in software (rather than its error-detection ability) because it has needed to be recalculated (IPv4) at every router.Consider L 16-bit words making up the information bits (IP header).Checksum, bL, is given by : bL=-xSo that adding the 16-bit words and the checksum (as below) gives 0.(Assessment does not require worked examples.For interest only, this is a tutorial example of how the checksum is calculated with 1’s complement arithmetic is )
17 Polynomial/Cyclic Redundancy Check (CRC) Codes k information bits (ik-1, ik-2, .... i1,i0) create an information polynomial i(x), of degree k-1.i(x)=ik-1xk-1 + ik-2xk i1x + i0i(x) and a generator polynomial, g(x), are used to calculate a codeword polynomial, b(x).Checksum calculation :Divide xn-ki(x) by g(x) to obtain the remainder r(x).xn-ki(x)=g(x).q(x) + r(x)(q(x)= quotient and r(x)=remainder)b(x) = xn-ki(x) + r(x)n bitsk bitsn-k bits
18 Binary Polynomial Division Division with Decimal Numbers35 ) 122231051724140divisorquotientremainderdividend1222 = 34 xdividend = quotient x divisor +remainder32x3 + x + 1 ) x6 + x5x x4 + x3x5 + x4 + x3x x3 + x2x x2x x2 + xx= q(x) quotient= r(x) remainderdivisordividend+ x+ x2x3Polynomial DivisionNote: Degree of r(x) is less than degree of divisor
21 Thank YouRecommended private study exercise : read the error control coding section from Chapter 3 of the recommended text.Use the content of the slides to guide your revision. Methods not referred to in the slides will not be assessed.