Download presentation

Presentation is loading. Please wait.

Published byAna Wakeham Modified about 1 year ago

1
Prolog The language of logic

2
History Kowalski: late 60’s Logician who showed logical proof can support computation. Colmerauer: early 70’s Developed early version of Prolog for natural language processing, mainly multiple parses. Warren: mid 70’s First version of Prolog that was efficient.

3
Characteristics Prolog approximates first-order logic. Every program is a set of Horn clauses. Inference is by resolution. Search is by backtracking with unification. Basic data structure is term or tree. Variables are unknowns not locations. Prolog does not distinguish between inputs and outputs. It solves relations/predicates.

4
SWI-Prolog Notes Free! Down Loadable To load a file: – consult( ‘C:\\kibler\\prolog\\test’). For help: –help(predicate-name). “ ; “ will give you next solution. listing(member) will give definition.

5
Example Facts: () –likes(john,mary). –likes(john,X). % Variables begin with capital Queries –?- likes(X,Y). – X=john, y=Mary. % hit “;” for more –?- likes(X,X). –X=john.

6
Example Rules –likes(john,X) :- likes(X,wine). % :- = if –likes(john,X):- female(X), likes(X,john). Note: variables are dummy. Standarized apart Some Facts: –likes(bill,wine). female(mary). female(sue). Query: ? - likes(john,Y). –Y = bill ; –no.

7
Family father(a,b). father(e,d). mother(c,b). mother(d,f). parent(X,Y) :- father(X,Y). parent(X,Y) :- mother(X,Y). grandfather(X,Y):- father(X,Z),parent(Z,Y). % Do your own for practice.

8
Informal Summary Program is facts + rules. (horn clauses). Query = conjunct of predicates. First set of bindings for variables that solve query are reported. If none, then Prolog returns no. Use “;” to get other solutions. Can be viewed as constraint satisfaction program.

9
MapColoring color(r). color(g). color(b). colormap(C1,C2,C3):- color(C1),color(C2),color(C3), C1\==C2, C1\==C3, C2\==C3. Query: colormap(X,Y,Z). –X = r, Y= g, Z=b. Is that it. Yes! Turn on trace.

10
Unification: (matching) terms Two terms UNIFY if there is a common substitution for all variables which makes them identical. f(g(X),Y) = f(Z,Z). % = cheap unification –X = _G225, Y=g(_G225). Look at parse tree for each term. –variables match –variable matches anything (set the binding) –function symbols only match identical function symbols.

11
Satisfiability: uses unification sat(true). % base case sat(not(false)). % base case sat(or(X,Y)):- sat(X). sat(or(X,Y)):-sat(Y). sat(and(X,Y)):-sat(X),sat(Y). test1(X,Y):- sat(and(not(X),X)). test2(X,Y):- sat(and(X,not(Y))).

12
List Operator [H |T] [a,b,c] is a list in Prolog. [H|T] = [a,b,c] results in –H = a i.e. the head of list –T = [b,c] i.e. the tail of the list. membership definition –member(H,[H|T]). % base case first. Why? –member(H,[_|T]):- member(H,T). –Use it.

13
Member Tests ?- member(3,X). –X = [3| _G109]. % _G.., system generated variable – X= [_G11,3| _]. % etc. ?- member(X,Y). –X = _G131, Y= [_G131|, _G321].

14
Permutation & Insert insert(X,L, [X|L]). insert(X,[H|T],[H|T1]):- insert(X,T,T1). perm([],[]). perm([H|T],P):-perm(T,T1),insert(H,T1,P).

15
DFS % solve(goal, solution Path) % s(state, successor-state) dfs(N,[N]) :- goal(N). dfs(N,[N|Sol1]):- s(N,N1), dfs(N1,Sol1). s(a,b). s(a,c). s(b,d). s(b,e). s(c,f). s(c,g). s(d,h). s(e,i). s(e,j). s(f,k). goal(i). goal(f). ?- dfs(a,N). N = [a, b, e, i] ; N = [a, c, f] ;

16
Limitations 2 nd order: Can’t ask what is relationship between heart and lungs? Probabilities: What is likelihood of fire destroying Julian?

Similar presentations

© 2016 SlidePlayer.com Inc.

All rights reserved.

Ads by Google