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Int: 7 th Session: 7-3- 1 ENGINEERS MECHANICS ENGINEERS MECHANICS STATICS STATICS CHAPTER7CHAPTER7 Lecture Notes: Professor A. Salam Al-Ammri Suhad Ibraheem.

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Presentation on theme: "Int: 7 th Session: 7-3- 1 ENGINEERS MECHANICS ENGINEERS MECHANICS STATICS STATICS CHAPTER7CHAPTER7 Lecture Notes: Professor A. Salam Al-Ammri Suhad Ibraheem."— Presentation transcript:

1 Int: 7 th Session: ENGINEERS MECHANICS ENGINEERS MECHANICS STATICS STATICS CHAPTER7CHAPTER7 Lecture Notes: Professor A. Salam Al-Ammri Suhad Ibraheem Mohammed Al-Khwarizmi College of Engineering University of Baghdad Theorems of Pappus-Guldinus Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad 2/17/2012

2 Int: 7 th Session: IntroductionTheorms of Pappus-GuldinusSample Problem 7.3.1Sample Problem 7.3.2Sample Problem 7.3.3Sample Problem 7.3.4Sample Problem 7.3.5Sample Problem 7.3.6Sample Problem /17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad Contents

3 Int: 7 th Session: Introduction Theorems of Pappus-Guldinus are useful to find a surface area or volume of revolution. Volume (V) of revolution Surface area (A s ) of revolution 2/17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad

4 Int: 7 th Session: Theorems of Pappus-Guldinus Surface of revolution is generated by rotating a plane curve about a fixed axis. Area of a surface of revolution is equal to the length of the generating curve times the distance traveled by the centroid through the rotation. 2/17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad

5 Int: 7 th Session: Theorems of Pappus-Guldinus Body of revolution is generated by rotating a plane area about a fixed axis. Volume of a body of revolution is equal to the generating area times the distance traveled by the centroid through the rotation. 2/17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad

6 Int: 7 th Session: Sample Problem The circular arc is rotated through 360 o about the y-axis.Determine the outer surface area of the resulting body, which is a portion of a sphere. 2/17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad

7 Int: 7 th Session: Sample Problem The body shown in cross section is a complete circular ring formed by revolving the octagonal area about the z-axis. The entire surface is to be covered with a special coating. Determine this surface area. 2/17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad

8 Int: 7 th Session: Sample Problem The two circular arcs AB and BC are revolved about the vertical axis to obtain the surface of revolution shown. Compute the area A of the outside of this surface. 2/17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad

9 Int: 7 th Session: Sample Problem The outside diameter of a pulley is 0.8 m, and the cross section of its rim is as shown. Knowing that the pulley is made of steel and that the density of steel is ρ=7.85x10 3 kg/m 3,determine the mass and weight of the rim. 2/17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad

10 Int: 7 th Session: Calculate the mass m of concrete required to constructthe arched dam shown. Concrete has a density of 2.40 Mg/m 3. Sample Problem /17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad

11 Int: 7 th Session: A hand-operated control wheel made of aluminum has the proportions shown in the cross-sectional view. The area of the total section shown is 15,200 mm 2, and the wheel has a mass of 10 kg. Calculate the distance to the centroid of the half- section. The aluminum has a density of 2.69 Mg/m 3. Sample Problem /17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad

12 Int: 7 th Session: Sample Problem A steel die, shown in section,has the form of a solid generated by revolving the shaded area around the z-axis.Calculate the mass of the die. 2/17/2012Professor Dr. A.Salam Al-Ammri & Suhad Ibraheem Mohammad


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