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Category 5 Category 4 Category 3 Category 2 Category 1 50 40 30 20 10 20 30 40 50 10 20 30 40 50 10 20 30 40 50 10 20 30 40 50

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The number of grams in one mole of carbon… Answer

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12 grams From Periodic Table

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The number of moles in 24 grams of carbon… Answer!

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2 moles of C 24 grams C x 1 mol C = 2 mol of C 12 g C

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The volume in L of gas evolved from 2.0 moles of O2 at STP… AnswerAnswer!

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44.8 L of O2 2 mol O2 x 22.4 L O2 = 44.8 L 1 mol O2

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The number of atoms in 1.4 moles of carbon… AnswerAnswer!

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8.43 x 10^(23) atoms 1.4 mol C x (6.02x10^(23) particles) = 8.43x10^(23) 1 mol C

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The volume in L of gas evolved from 20 g of O2 at STP… AnswerAnswer!

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14 L of O2 20 g O2 x 1 mol O2 x 22.4 L O2 = 14 L 32 g O2 1 mol O2

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The number of grams in one mole of sodium… AnswerAnswer!

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22.99 grams From Periodic Table

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The number of moles in 99 grams of sodium… AnswerAnswer!

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4.32 moles Na 99 grams Na x 1 mol = 4.32 mol of Na 22.99 g

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The number of moles in 48 grams of oxygen gas… AnswerAnswer!

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1.5 moles O2 48 grams O2 x 1 mol = 1.5 mol of O2 32 g O2

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The volume in L of gas evolved from 98 grams of H2O… AnswerAnswer!

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121. 96 L H2O 98 g H2O x 1 mol H2O x 22.4 L H2O = 121.96 L 18 g H2O 1 mol H2O

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The volume in L of gas evolved from 61 grams of CO2… AnswerAnswer!

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31.05 L of CO2 61 g CO2 x 1 mol x 22.4 L = 31.05 L 44 g 1 mol

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The number of grams in one mole of calcium… AnswerAnswer!

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40.08 grams Ca From Periodic Table!

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The volume in L of gas evolved from 2.21 moles of CCl4… AnswerAnswer!

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49.5 L of CCl4 2.21 mol CCl4 x 22.4 L = 49.5 L CCl4 1 mol

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The number of atoms in 0.003 moles of calcium… AnswerAnswer!

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1.81x10^(21) atoms of Ca 0.003 mol Ca x (6.02x10^(23) particles) = 1.81 x 10^(21) 1 mol Ca

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The volume in L of gas evolved from 2.21 grams of CCl4… AnswerAnswer!

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0.322 L of CCl4 2.21 g CCl4 x 1 mol CCl4 x 22.4 L CCl4 = 0.322 L 153.8 g 1 mol

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The number of atoms found in 24.2 grams of calcium AnswerAnswer!

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3.6x10^(23) atoms of Ca 24.2 g Ca x 1 mol Ca x (6.02x10^(23) particles = 3.6 x 10^(23) atoms 40.08 g Ca 1 mol Ca

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The number of grams in one mole of hydrogen gas… AnswerAnswer!

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1.008 grams 1 mol H2 x 1.008 g H2 = 1.008 g 1 mol H2

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The number of moles in 922 grams of bromine gas… AnswerAnswer!

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5.76 moles Br2 922 grams Br2 x 1 mol Br2 = 5.76 mol Br2 159.8 g Br2

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The volume in L of gas evolved from 0.12 moles of hydrogen gas at STP… AnswerAnswer!

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2.688 L H2 0.12 mol H2 x 22.4 L H2 = 2.688 L 1 mol H2

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The volume in L of gas evolved from 66 grams of H2 at STP… AnswerAnswer!

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733.3 L H2 66 g H2 x 1 mol H2 x 22.4 L H2 = 733.3 L 2.016 g H2 1 mol H2

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The number of atoms found in 0.4400000000 grams of bromine gas… AnswerAnswer!

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1.67x10^(21) atoms of Br2 0.44 g Br2 x 1 mol Br2 x (6.02x10^(23) particles = 1.67 x 10^(21) atoms 153.8 g Br2 1 mol Br2

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The number of grams in one mole of lead… AnswerAnswer!

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207.2 grams 1 mol Pb x 207.2 g Pb = 207.2 g Pb 1 mol Pb

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The number of moles in 35 grams of lead… AnswerAnswer!

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0.169 mol Pb 35 grams Pb x 1 mol Pb = 0.169 mol of Pb 207.2 g Pb

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The number of atoms in 9.9x10^(-23) moles of lead… AnswerAnswer!

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59.59 atoms of Pb 9.9x10^(-23) mol Pb x (6.02x10^(23) particles) = 59.59 atoms of Pb 1 mol Pb

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The volume in L of gas evolved from 8522 grams of Rn at STP… AnswerAnswer!

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859.8 L Rn 8522 g Rn x 1 mol Rn x 22.4 L Rn = 859.8 L Rn 222 g Rn 1 mol Rn

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The number of atoms found in 1.3x10^(-21) grams of lead… AnswerAnswer!

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3.78 atoms of Pb 1.3x10^(-21) g x 1 mol x (6.02x10^(23) particles = 3.78 atoms Pb 207.2 g 1 mol Pb

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